这是我使用的，不管边界和矩阵变换:

function clearCanvas(canvas) {
  const ctx = canvas.getContext('2d');
  ctx.save();
  ctx.globalCompositeOperation = 'copy';
  ctx.strokeStyle = 'transparent';
  ctx.beginPath();
  ctx.lineTo(0, 0);
  ctx.stroke();
  ctx.restore();
}

基本上，它保存了上下文的当前状态，并以globalCompositeOperation为copy绘制了一个透明像素。然后，恢复以前的上下文状态。

假设canvas是一个canvas元素或者OffscreenCanvas对象，使用clearRect:

const context = canvas.getContext('2d');
context.clearRect(0, 0, canvas.width, canvas.height);

这适用于我的pieChart in chart.js

<div class="pie_nut" id="pieChartContainer">
    <canvas id="pieChart" height="5" width="6"></canvas> 
</div>

$('#pieChartContainer').html(''); //remove canvas from container
$('#pieChartContainer').html('<canvas id="pieChart" height="5" width="6"></canvas>'); //add it back to the container

用途:上下文。clearRect(0,0, canvas.)宽度,canvas.height);

这是清除整个画布的最快和最直观的方法。

不要使用:canvas。宽度= canvas.width;

重置画布。width重置所有的画布状态(例如，转换，lineWidth, strokeStyle等)，它非常慢(与clearRect相比)，它不能在所有浏览器中工作，并且它不能描述你实际上试图做什么。

处理变换后的坐标

如果你已经修改了转换矩阵(例如使用缩放，旋转或翻译)，那么context.clearRect(0,0,canvas.width,canvas.height)可能不会清除画布的整个可见部分。

解决方案?在清除画布之前重置转换矩阵:

// Store the current transformation matrix
context.save();

// Use the identity matrix while clearing the canvas
context.setTransform(1, 0, 0, 1, 0, 0);
context.clearRect(0, 0, canvas.width, canvas.height);

// Restore the transform
context.restore();

编辑: 我刚刚做了一些分析(在Chrome中)，它是大约10%的速度，以清除一个300x150(默认大小)的画布，而不重置转换。随着画布尺寸的增加，这种差异就会减小。

这已经是相对微不足道的了，但在大多数情况下，您提取的金额将远远超过您出清的金额，我相信这种性能差异是无关紧要的。

100000 iterations averaged 10 times:
1885ms to clear
2112ms to reset and clear

使用clearRect方法通过传递x,y坐标和画布的高度和宽度。ClearRect将清除整个画布:

canvas = document.getElementById("canvas");
ctx = canvas.getContext("2d");
ctx.clearRect(0, 0, canvas.width, canvas.height);

This is a Free hand drawing Canvas with a Clear Canvas Button. See this live example of a canvas which you can draw on and also when required clear it for redrawing clearRect() is used to delete the prersent canvas and fillRect() is used to again draw the initial canvas which was clean and had no drawings on it. var canvas = document.getElementById("canvas"), ctx = canvas.getContext("2d"), painting = false, lastX = 0, lastY = 0, lineThickness = 1; canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250); canvas.onmousedown = function(e) { painting = true; ctx.fillStyle = "#ffffff"; lastX = e.pageX - this.offsetLeft; lastY = e.pageY - this.offsetTop; }; canvas.onmouseup = function(e){ painting = false; } canvas.onmousemove = function(e) { if (painting) { mouseX = e.pageX - this.offsetLeft; mouseY = e.pageY - this.offsetTop; // find all points between var x1 = mouseX, x2 = lastX, y1 = mouseY, y2 = lastY; var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1)); if (steep){ var x = x1; x1 = y1; y1 = x; var y = y2; y2 = x2; x2 = y; } if (x1 > x2) { var x = x1; x1 = x2; x2 = x; var y = y1; y1 = y2; y2 = y; } var dx = x2 - x1, dy = Math.abs(y2 - y1), error = 0, de = dy / dx, yStep = -1, y = y1; if (y1 < y2) { yStep = 1; } lineThickness = 4; for (var x = x1; x < x2; x++) { if (steep) { ctx.fillRect(y, x, lineThickness , lineThickness ); } else { ctx.fillRect(x, y, lineThickness , lineThickness ); } error += de; if (error >= 0.5) { y += yStep; error -= 1.0; } } lastX = mouseX; lastY = mouseY; } } var button=document.getElementById("clear"); button.onclick=function clearcanvas(){ canvas=document.getElementById("canvas"), ctx = canvas.getContext('2d'); ctx.clearRect(0, 0, 250, 250); canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250);} #clear{border-radius:10px; font-size:8px !important; position:absolute; top:1px;} #canvas{border-radius:10px} <link href="https://www.w3schools.com/w3css/4/w3.css" rel="stylesheet"/> <button id="clear" class="w3-padding w3-xxlarge w3-pink" type="button">Clear Canvas</button> <canvas id="canvas"></canvas>