这是2018年，仍然没有本地的方法来完全清除画布重新绘制。clearRect()不会完全清除画布。非填充型图纸不清除(例如。矩形())

1.要完全清除画布，无论你如何绘制:

context.clearRect(0, 0, context.canvas.width, context.canvas.height);
context.beginPath();

优点:保留strokeStyle, fillStyle等;没有滞后;

缺点:如果你在绘制任何东西之前已经使用了beginPath，那就不必要了

2.使用宽度/高度hack:

context.canvas.width = context.canvas.width;

OR

context.canvas.height = context.canvas.height;

优点:与IE兼容 缺点:重置strokeStyle, fillStyle为黑色;延迟;

我想知道为什么本地解决方案不存在。实际上，clearRect()被认为是单行解决方案，因为大多数用户在绘制任何新路径之前都会执行beginPath()。虽然beginPath只在绘制线条时使用，而不是像rect()那样使用封闭路径。

这就是为什么接受的答案并没有解决我的问题，我最终浪费时间尝试不同的方法。诅咒你mozilla

如果你只使用clearRect，如果你在一个表单中提交你的图纸，你会得到一个提交而不是清除，或者可能它可以先清除，然后上传一个无效的图纸，所以你需要在函数的开头添加一个preventDefault:

   function clearCanvas(canvas,ctx) {
        event.preventDefault();
        ctx.clearRect(0, 0, canvas.width, canvas.height);
    }


<input type="button" value="Clear Sketchpad" id="clearbutton" onclick="clearCanvas(canvas,ctx);">

希望它能帮助到别人。

最短的方法:

canvas.width += 0

private clearCanvas() {
  const canvas: HTMLCanvasElement = this.ctx.canvas
  this.ctx.save()
  this.ctx.setTransform(1, 0, 0, 1, 0, 0)
  this.ctx.clearRect(0, 0, canvas.width, canvas.height)
  this.ctx.restore()
}

This is a Free hand drawing Canvas with a Clear Canvas Button. See this live example of a canvas which you can draw on and also when required clear it for redrawing clearRect() is used to delete the prersent canvas and fillRect() is used to again draw the initial canvas which was clean and had no drawings on it. var canvas = document.getElementById("canvas"), ctx = canvas.getContext("2d"), painting = false, lastX = 0, lastY = 0, lineThickness = 1; canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250); canvas.onmousedown = function(e) { painting = true; ctx.fillStyle = "#ffffff"; lastX = e.pageX - this.offsetLeft; lastY = e.pageY - this.offsetTop; }; canvas.onmouseup = function(e){ painting = false; } canvas.onmousemove = function(e) { if (painting) { mouseX = e.pageX - this.offsetLeft; mouseY = e.pageY - this.offsetTop; // find all points between var x1 = mouseX, x2 = lastX, y1 = mouseY, y2 = lastY; var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1)); if (steep){ var x = x1; x1 = y1; y1 = x; var y = y2; y2 = x2; x2 = y; } if (x1 > x2) { var x = x1; x1 = x2; x2 = x; var y = y1; y1 = y2; y2 = y; } var dx = x2 - x1, dy = Math.abs(y2 - y1), error = 0, de = dy / dx, yStep = -1, y = y1; if (y1 < y2) { yStep = 1; } lineThickness = 4; for (var x = x1; x < x2; x++) { if (steep) { ctx.fillRect(y, x, lineThickness , lineThickness ); } else { ctx.fillRect(x, y, lineThickness , lineThickness ); } error += de; if (error >= 0.5) { y += yStep; error -= 1.0; } } lastX = mouseX; lastY = mouseY; } } var button=document.getElementById("clear"); button.onclick=function clearcanvas(){ canvas=document.getElementById("canvas"), ctx = canvas.getContext('2d'); ctx.clearRect(0, 0, 250, 250); canvas.width=canvas.height = 250; ctx.fillRect(0, 0, 250, 250);} #clear{border-radius:10px; font-size:8px !important; position:absolute; top:1px;} #canvas{border-radius:10px} <link href="https://www.w3schools.com/w3css/4/w3.css" rel="stylesheet"/> <button id="clear" class="w3-padding w3-xxlarge w3-pink" type="button">Clear Canvas</button> <canvas id="canvas"></canvas>

一个快速的方法就是去做

canvas.width = canvas.width

我不知道它是如何工作的，但它确实如此!