在Go中,我只想要一个随机字符串(大写或小写),没有数字。最快最简单的方法是什么?


当前回答

另一个版本,灵感来自于生成密码在JavaScript加密:

package main

import (
    "crypto/rand"
    "fmt"
)

var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890-"

func shortID(length int) string {
    ll := len(chars)
    b := make([]byte, length)
    rand.Read(b) // generates len(b) random bytes
    for i := 0; i < length; i++ {
        b[i] = chars[int(b[i])%ll]
    }
    return string(b)
}

func main() {
    fmt.Println(shortID(18))
    fmt.Println(shortID(18))
    fmt.Println(shortID(18))
}

其他回答

两个可能的选项(当然可能有更多):

您可以使用crypto/rand包,它支持读取随机字节数组(来自/dev/urandom),并面向加密随机生成。见http://golang.org/pkg/crypto/rand/#example_Read。它可能比普通的伪随机数生成慢。 取一个随机数,用md5或类似的方法进行哈希。

/*
    korzhao
*/

package rand

import (
    crand "crypto/rand"
    "math/rand"
    "sync"
    "time"
    "unsafe"
)

// Doesn't share the rand library globally, reducing lock contention
type Rand struct {
    Seed int64
    Pool *sync.Pool
}

var (
    MRand    = NewRand()
    randlist = []byte("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890")
)

// init random number generator
func NewRand() *Rand {
    p := &sync.Pool{New: func() interface{} {
        return rand.New(rand.NewSource(getSeed()))
    },
    }
    mrand := &Rand{
        Pool: p,
    }
    return mrand
}

// get the seed
func getSeed() int64 {
    return time.Now().UnixNano()
}

func (s *Rand) getrand() *rand.Rand {
    return s.Pool.Get().(*rand.Rand)
}
func (s *Rand) putrand(r *rand.Rand) {
    s.Pool.Put(r)
}

// get a random number
func (s *Rand) Intn(n int) int {
    r := s.getrand()
    defer s.putrand(r)

    return r.Intn(n)
}

//  bulk get random numbers
func (s *Rand) Read(p []byte) (int, error) {
    r := s.getrand()
    defer s.putrand(r)

    return r.Read(p)
}

func CreateRandomString(len int) string {
    b := make([]byte, len)
    _, err := MRand.Read(b)
    if err != nil {
        return ""
    }
    for i := 0; i < len; i++ {
        b[i] = randlist[b[i]%(62)]
    }
    return *(*string)(unsafe.Pointer(&b))
}

24.0 ns/op 16 B/op 1 allocs/

如果需要选择是否大写,我通常会这样做

func randomString(length int, upperCase bool) string {
    rand.Seed(time.Now().UnixNano())

    var alphabet string

    if upperCase {
        alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    } else {
        alphabet = "abcdefghijklmnopqrstuvwxyz"
    }

    var sb strings.Builder

    l := len(alphabet)

    for i := 0; i < length; i++ {
        c := alphabet[rand.Intn(l)]
        sb.WriteByte(c)
    }

    return sb.String()
}

如果不需要大写字母,就像这样

func randomString(length int) string {
        rand.Seed(time.Now().UnixNano())

        var alphabet string = "abcdefghijklmnopqrstuvwxyz"
        var sb strings.Builder

        l := len(alphabet)

        for i := 0; i < length; i++ {
                c := alphabet[rand.Intn(l)]
                sb.WriteByte(c)
        }

        return sb.String()
}

这里是一个简单而高效的加密安全随机字符串的解决方案。

package main

import (
    "crypto/rand"
    "unsafe"
    "fmt"
)

var alphabet = []byte("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

func main() {
    fmt.Println(generate(16))
}

func generate(size int) string {
    b := make([]byte, size)
    rand.Read(b)
    for i := 0; i < size; i++ {
        b[i] = alphabet[b[i] % byte(len(alphabet))]
    }
    return *(*string)(unsafe.Pointer(&b))
}

基准

Benchmark  95.2 ns/op      16 B/op      1 allocs/op

这是我的方式)使用数学兰特或加密兰特如你所愿。

func randStr(len int) string {
    buff := make([]byte, len)
    rand.Read(buff)
    str := base64.StdEncoding.EncodeToString(buff)
    // Base 64 can be longer than len
    return str[:len]
}