我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。
当前回答
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib
msg = MIMEMultipart()
password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()
其他回答
Gmail版本,使用Python 3.6(请注意,您需要更改Gmail设置,以便能够通过smtp从它发送电子邮件:
import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.application import MIMEApplication
from os.path import basename
def send_mail(send_from: str, subject: str, text: str,
send_to: list, files= None):
send_to= default_address if not send_to else send_to
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = ', '.join(send_to)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
ext = f.split('.')[-1:]
attachedfile = MIMEApplication(fil.read(), _subtype = ext)
attachedfile.add_header(
'content-disposition', 'attachment', filename=basename(f) )
msg.attach(attachedfile)
smtp = smtplib.SMTP(host="smtp.gmail.com", port= 587)
smtp.starttls()
smtp.login(username,password)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
用法:
username = 'my-address@gmail.com'
password = 'top-secret'
default_address = ['my-address2@gmail.com']
send_mail(send_from= username,
subject="test",
text="text",
send_to= None,
files= # pass a list with the full filepaths here...
)
要与任何其他电子邮件提供商一起使用,只需更改smtp配置。
有了我的代码,您可以使用gmail发送电子邮件附件,您将需要:
将您的gmail地址设置为您的SMTP邮箱地址 将您的gmail帐户密码设置为__YOUR SMTP password HERE___ 在___EMAIL TO RECEIVE the MESSAGE__部分,您需要设置目的电子邮件地址。 告警通知是主题。 有人进入房间,附上的照片是尸体。 ["/home/pi/webcam.jpg"]是一个图像附件。
以下是完整的代码:
#!/usr/bin/env python
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
from email import Encoders
import os
USERNAME = "___YOUR SMTP EMAIL HERE___"
PASSWORD = "__YOUR SMTP PASSWORD HERE___"
def sendMail(to, subject, text, files=[]):
assert type(to)==list
assert type(files)==list
msg = MIMEMultipart()
msg['From'] = USERNAME
msg['To'] = COMMASPACE.join(to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach( MIMEText(text) )
for file in files:
part = MIMEBase('application', "octet-stream")
part.set_payload( open(file,"rb").read() )
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="%s"'
% os.path.basename(file))
msg.attach(part)
server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo_or_helo_if_needed()
server.starttls()
server.ehlo_or_helo_if_needed()
server.login(USERNAME,PASSWORD)
server.sendmail(USERNAME, to, msg.as_string())
server.quit()
sendMail( ["___EMAIL TO RECEIVE THE MESSAGE__"],
"Alarm notification",
"Someone has entered the room, picture attached",
["/home/pi/webcam.jpg"] )
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib
msg = MIMEMultipart()
password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()
下面是Python 3.6及更新版本的更新版本,使用Python标准库中经过大修的电子邮件模块的EmailMessage类。
import mimetypes
import os
import smtplib
from email.message import EmailMessage
username = "user@example.com"
password = "password"
smtp_url = "smtp.example.com"
port = 587
def send_mail(subject: str, send_from: str, send_to: str, message: str, directory: str, filename: str):
# Create the email message
msg = EmailMessage()
msg['Subject'] = subject
msg['From'] = send_from
msg['To'] = send_to
# Set email content
msg.set_content(message)
path = directory + filename
if os.path.exists(path):
ctype, encoding = mimetypes.guess_type(path)
if ctype is None or encoding is not None:
# No guess could be made, or the file is encoded (compressed), so
# use a generic bag-of-bits type.
ctype = 'application/octet-stream'
maintype, subtype = ctype.split('/', 1)
# Add email attachment
with open(path, 'rb') as fp:
msg.add_attachment(fp.read(),
maintype=maintype,
subtype=subtype,
filename=filename)
smtp = smtplib.SMTP(smtp_url, port)
smtp.starttls() # for using port 587
smtp.login(username, password)
smtp.send_message(msg)
smtp.quit()
你可以在这里找到更多的例子。
python 3的另一种方法(如果有人正在搜索):
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "sender mail address"
toaddr = "receiver mail address"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "SUBJECT OF THE EMAIL"
body = "TEXT YOU WANT TO SEND"
msg.attach(MIMEText(body, 'plain'))
filename = "fileName"
attachment = open("path of file", "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(fromaddr, "sender mail password")
text = msg.as_string()
server.sendmail(fromaddr, toaddr, text)
server.quit()
确保在你的Gmail帐户上允许“不太安全的应用程序”