我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。
当前回答
下面是Python 3.6及更新版本的更新版本,使用Python标准库中经过大修的电子邮件模块的EmailMessage类。
import mimetypes
import os
import smtplib
from email.message import EmailMessage
username = "user@example.com"
password = "password"
smtp_url = "smtp.example.com"
port = 587
def send_mail(subject: str, send_from: str, send_to: str, message: str, directory: str, filename: str):
# Create the email message
msg = EmailMessage()
msg['Subject'] = subject
msg['From'] = send_from
msg['To'] = send_to
# Set email content
msg.set_content(message)
path = directory + filename
if os.path.exists(path):
ctype, encoding = mimetypes.guess_type(path)
if ctype is None or encoding is not None:
# No guess could be made, or the file is encoded (compressed), so
# use a generic bag-of-bits type.
ctype = 'application/octet-stream'
maintype, subtype = ctype.split('/', 1)
# Add email attachment
with open(path, 'rb') as fp:
msg.add_attachment(fp.read(),
maintype=maintype,
subtype=subtype,
filename=filename)
smtp = smtplib.SMTP(smtp_url, port)
smtp.starttls() # for using port 587
smtp.login(username, password)
smtp.send_message(msg)
smtp.quit()
你可以在这里找到更多的例子。
其他回答
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEImage import MIMEImage
import smtplib
msg = MIMEMultipart()
msg.attach(MIMEText(file("text.txt").read()))
msg.attach(MIMEImage(file("image.png").read()))
# to send
mailer = smtplib.SMTP()
mailer.connect()
mailer.sendmail(from_, to, msg.as_string())
mailer.close()
从这里改编。
试试这个我希望这可能会有帮助
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "youremailhere"
toaddr = input("Enter The Email Adress You want to send to: ")
# instance of MIMEMultipart
msg = MIMEMultipart()
# storing the senders email address
msg['From'] = fromaddr
# storing the receivers email address
msg['To'] = toaddr
# storing the subject
msg['Subject'] = input("What is the Subject:\t")
# string to store the body of the mail
body = input("What is the body:\t")
# attach the body with the msg instance
msg.attach(MIMEText(body, 'plain'))
# open the file to be sent
filename = input("filename:")
attachment = open(filename, "rb")
# instance of MIMEBase and named as p
p = MIMEBase('application', 'octet-stream')
# To change the payload into encoded form
p.set_payload((attachment).read())
# encode into base64
encoders.encode_base64(p)
p.add_header('Content-Disposition', "attachment; filename= %s" % filename)
# attach the instance 'p' to instance 'msg'
msg.attach(p)
# creates SMTP session
s = smtplib.SMTP('smtp.gmail.com', 587)
# start TLS for security
s.starttls()
# Authentication
s.login(fromaddr, "yourpaswordhere)
# Converts the Multipart msg into a string
text = msg.as_string()
# sending the mail
s.sendmail(fromaddr, toaddr, text)
# terminating the session
s.quit()
这是另一个:
import smtplib
from os.path import basename
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
def send_mail(send_from, send_to, subject, text, files=None,
server="127.0.0.1"):
assert isinstance(send_to, list)
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=basename(f)
)
# After the file is closed
part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
msg.attach(part)
smtp = smtplib.SMTP(server)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
这和第一个例子差不多……但顺便来一下应该更容易些。
python 3的另一种方法(如果有人正在搜索):
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "sender mail address"
toaddr = "receiver mail address"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "SUBJECT OF THE EMAIL"
body = "TEXT YOU WANT TO SEND"
msg.attach(MIMEText(body, 'plain'))
filename = "fileName"
attachment = open("path of file", "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(fromaddr, "sender mail password")
text = msg.as_string()
server.sendmail(fromaddr, toaddr, text)
server.quit()
确保在你的Gmail帐户上允许“不太安全的应用程序”
这是我最终使用的代码:
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email import Encoders
SUBJECT = "Email Data"
msg = MIMEMultipart()
msg['Subject'] = SUBJECT
msg['From'] = self.EMAIL_FROM
msg['To'] = ', '.join(self.EMAIL_TO)
part = MIMEBase('application', "octet-stream")
part.set_payload(open("text.txt", "rb").read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="text.txt"')
msg.attach(part)
server = smtplib.SMTP(self.EMAIL_SERVER)
server.sendmail(self.EMAIL_FROM, self.EMAIL_TO, msg.as_string())
代码与Oli的帖子大致相同。
代码基于二进制文件电子邮件附件问题的帖子。
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