我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。
当前回答
这里目前给出的答案都不能正确地与GMail、Outlook 2016等客户机的文件名中的非ascii符号一起工作,以及其他不支持RFC 2231的客户机(例如,参见这里)。下面的Python 3代码改编自其他一些stackoverflow的答案(对不起,没有保存原始链接)和Python 2.7的odoo/openerp代码(参见ir_mail_server.py)。它可以正确地与GMail和其他设备一起工作,并且还使用SSL。
import smtplib, ssl
from os.path import basename
from email.mime.base import MIMEBase
from mimetypes import guess_type
from email.encoders import encode_base64
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email.charset import Charset
def try_coerce_ascii(string_utf8):
"""Attempts to decode the given utf8-encoded string
as ASCII after coercing it to UTF-8, then return
the confirmed 7-bit ASCII string.
If the process fails (because the string
contains non-ASCII characters) returns ``None``.
"""
try:
string_utf8.encode('ascii')
except UnicodeEncodeError:
return
return string_utf8
def encode_header_param(param_text):
"""Returns an appropriate RFC 2047 encoded representation of the given
header parameter value, suitable for direct assignation as the
param value (e.g. via Message.set_param() or Message.add_header())
RFC 2822 assumes that headers contain only 7-bit characters,
so we ensure it is the case, using RFC 2047 encoding when needed.
:param param_text: unicode or utf-8 encoded string with header value
:rtype: string
:return: if ``param_text`` represents a plain ASCII string,
return the same 7-bit string, otherwise returns an
ASCII string containing the RFC2047 encoded text.
"""
if not param_text: return ""
param_text_ascii = try_coerce_ascii(param_text)
return param_text_ascii if param_text_ascii\
else Charset('utf8').header_encode(param_text)
smtp_server = '<someserver.com>'
smtp_port = 465 # Default port for SSL
sender_email = '<sender_email@some.com>'
sender_password = '<PASSWORD>'
receiver_emails = ['<receiver_email_1@some.com>', '<receiver_email_2@some.com>']
subject = 'Test message'
message = """\
Hello! This is a test message with attachments.
This message is sent from Python."""
files = ['<path1>/файл1.pdf', '<path2>/файл2.png']
# Create a secure SSL context
context = ssl.create_default_context()
msg = MIMEMultipart()
msg['From'] = sender_email
msg['To'] = COMMASPACE.join(receiver_emails)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(message))
for f in files:
mimetype, _ = guess_type(f)
mimetype = mimetype.split('/', 1)
with open(f, "rb") as fil:
part = MIMEBase(mimetype[0], mimetype[1])
part.set_payload(fil.read())
encode_base64(part)
filename_rfc2047 = encode_header_param(basename(f))
# The default RFC 2231 encoding of Message.add_header() works in Thunderbird but not GMail
# so we fix it by using RFC 2047 encoding for the filename instead.
part.set_param('name', filename_rfc2047)
part.add_header('Content-Disposition', 'attachment', filename=filename_rfc2047)
msg.attach(part)
with smtplib.SMTP_SSL(smtp_server, smtp_port, context=context) as server:
server.login(sender_email, sender_password)
server.sendmail(sender_email, receiver_emails, msg.as_string())
其他回答
python 3的另一种方法(如果有人正在搜索):
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "sender mail address"
toaddr = "receiver mail address"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "SUBJECT OF THE EMAIL"
body = "TEXT YOU WANT TO SEND"
msg.attach(MIMEText(body, 'plain'))
filename = "fileName"
attachment = open("path of file", "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(fromaddr, "sender mail password")
text = msg.as_string()
server.sendmail(fromaddr, toaddr, text)
server.quit()
确保在你的Gmail帐户上允许“不太安全的应用程序”
你也可以在你的电子邮件中指定你想要的附件类型,例如我使用pdf:
def send_email_pdf_figs(path_to_pdf, subject, message, destination, password_path=None):
## credits: http://linuxcursor.com/python-programming/06-how-to-send-pdf-ppt-attachment-with-html-body-in-python-script
from socket import gethostname
#import email
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
import json
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
with open(password_path) as f:
config = json.load(f)
server.login('me@gmail.com', config['password'])
# Craft message (obj)
msg = MIMEMultipart()
message = f'{message}\nSend from Hostname: {gethostname()}'
msg['Subject'] = subject
msg['From'] = 'me@gmail.com'
msg['To'] = destination
# Insert the text to the msg going by e-mail
msg.attach(MIMEText(message, "plain"))
# Attach the pdf to the msg going by e-mail
with open(path_to_pdf, "rb") as f:
#attach = email.mime.application.MIMEApplication(f.read(),_subtype="pdf")
attach = MIMEApplication(f.read(),_subtype="pdf")
attach.add_header('Content-Disposition','attachment',filename=str(path_to_pdf))
msg.attach(attach)
# send msg
server.send_message(msg)
灵感/信用:http://linuxcursor.com/python-programming/06-how-to-send-pdf-ppt- attachment-html -body-in-python脚本
这是另一个:
import smtplib
from os.path import basename
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
def send_mail(send_from, send_to, subject, text, files=None,
server="127.0.0.1"):
assert isinstance(send_to, list)
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=basename(f)
)
# After the file is closed
part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
msg.attach(part)
smtp = smtplib.SMTP(server)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
这和第一个例子差不多……但顺便来一下应该更容易些。
下面是Oli为python3编写的修改版本
import smtplib
from pathlib import Path
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email import encoders
def send_mail(send_from, send_to, subject, message, files=[],
server="localhost", port=587, username='', password='',
use_tls=True):
"""Compose and send email with provided info and attachments.
Args:
send_from (str): from name
send_to (list[str]): to name(s)
subject (str): message title
message (str): message body
files (list[str]): list of file paths to be attached to email
server (str): mail server host name
port (int): port number
username (str): server auth username
password (str): server auth password
use_tls (bool): use TLS mode
"""
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(message))
for path in files:
part = MIMEBase('application', "octet-stream")
with open(path, 'rb') as file:
part.set_payload(file.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition',
'attachment; filename={}'.format(Path(path).name))
msg.attach(part)
smtp = smtplib.SMTP(server, port)
if use_tls:
smtp.starttls()
smtp.login(username, password)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.quit()
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib
msg = MIMEMultipart()
password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()
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