试试这个我希望这可能会有帮助

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
   
fromaddr = "youremailhere"
toaddr = input("Enter The Email Adress You want to send to: ")
   
# instance of MIMEMultipart
msg = MIMEMultipart()
  
# storing the senders email address  
msg['From'] = fromaddr
  
# storing the receivers email address 
msg['To'] = toaddr
  
# storing the subject 
msg['Subject'] = input("What is the Subject:\t")
# string to store the body of the mail
body = input("What is the body:\t")
  
# attach the body with the msg instance
msg.attach(MIMEText(body, 'plain'))
  
# open the file to be sent 
filename = input("filename:")
attachment = open(filename, "rb")
  
# instance of MIMEBase and named as p
p = MIMEBase('application', 'octet-stream')
  
# To change the payload into encoded form
p.set_payload((attachment).read())
  
# encode into base64
encoders.encode_base64(p)
   
p.add_header('Content-Disposition', "attachment; filename= %s" % filename)
  
# attach the instance 'p' to instance 'msg'
msg.attach(p)
  
# creates SMTP session
s = smtplib.SMTP('smtp.gmail.com', 587)
  
# start TLS for security
s.starttls()
  
# Authentication
s.login(fromaddr, "yourpaswordhere)
  
# Converts the Multipart msg into a string
text = msg.as_string()
  
# sending the mail
s.sendmail(fromaddr, toaddr, text)
  
# terminating the session
s.quit()

下面是Oli为python3编写的修改版本

import smtplib
from pathlib import Path
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email import encoders


def send_mail(send_from, send_to, subject, message, files=[],
              server="localhost", port=587, username='', password='',
              use_tls=True):
    """Compose and send email with provided info and attachments.

    Args:
        send_from (str): from name
        send_to (list[str]): to name(s)
        subject (str): message title
        message (str): message body
        files (list[str]): list of file paths to be attached to email
        server (str): mail server host name
        port (int): port number
        username (str): server auth username
        password (str): server auth password
        use_tls (bool): use TLS mode
    """
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = COMMASPACE.join(send_to)
    msg['Date'] = formatdate(localtime=True)
    msg['Subject'] = subject

    msg.attach(MIMEText(message))

    for path in files:
        part = MIMEBase('application', "octet-stream")
        with open(path, 'rb') as file:
            part.set_payload(file.read())
        encoders.encode_base64(part)
        part.add_header('Content-Disposition',
                        'attachment; filename={}'.format(Path(path).name))
        msg.attach(part)

    smtp = smtplib.SMTP(server, port)
    if use_tls:
        smtp.starttls()
    smtp.login(username, password)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.quit()

试试这个我希望这可能会有帮助

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
   
fromaddr = "youremailhere"
toaddr = input("Enter The Email Adress You want to send to: ")
   
# instance of MIMEMultipart
msg = MIMEMultipart()
  
# storing the senders email address  
msg['From'] = fromaddr
  
# storing the receivers email address 
msg['To'] = toaddr
  
# storing the subject 
msg['Subject'] = input("What is the Subject:\t")
# string to store the body of the mail
body = input("What is the body:\t")
  
# attach the body with the msg instance
msg.attach(MIMEText(body, 'plain'))
  
# open the file to be sent 
filename = input("filename:")
attachment = open(filename, "rb")
  
# instance of MIMEBase and named as p
p = MIMEBase('application', 'octet-stream')
  
# To change the payload into encoded form
p.set_payload((attachment).read())
  
# encode into base64
encoders.encode_base64(p)
   
p.add_header('Content-Disposition', "attachment; filename= %s" % filename)
  
# attach the instance 'p' to instance 'msg'
msg.attach(p)
  
# creates SMTP session
s = smtplib.SMTP('smtp.gmail.com', 587)
  
# start TLS for security
s.starttls()
  
# Authentication
s.login(fromaddr, "yourpaswordhere)
  
# Converts the Multipart msg into a string
text = msg.as_string()
  
# sending the mail
s.sendmail(fromaddr, toaddr, text)
  
# terminating the session
s.quit()

其他的答案也很好，但我还是想分享一种不同的方法，以防有人正在寻找替代方案。

主要的区别是，使用这种方法，你可以使用HTML/CSS来格式化你的邮件，所以你可以有创意，给你的电子邮件一些样式。虽然没有强制使用HTML，但仍然可以只使用纯文本。

注意，该函数接受将电子邮件发送给多个收件人，也允许附加多个文件。

我只在python2上尝试过，但我认为它在python3上也能正常工作:

import os.path
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication

def send_email(subject, message, from_email, to_email=[], attachment=[]):
    """
    :param subject: email subject
    :param message: Body content of the email (string), can be HTML/CSS or plain text
    :param from_email: Email address from where the email is sent
    :param to_email: List of email recipients, example: ["a@a.com", "b@b.com"]
    :param attachment: List of attachments, exmaple: ["file1.txt", "file2.txt"]
    """
    msg = MIMEMultipart()
    msg['Subject'] = subject
    msg['From'] = from_email
    msg['To'] = ", ".join(to_email)
    msg.attach(MIMEText(message, 'html'))

    for f in attachment:
        with open(f, 'rb') as a_file:
            basename = os.path.basename(f)
            part = MIMEApplication(a_file.read(), Name=basename)

        part['Content-Disposition'] = 'attachment; filename="%s"' % basename
        msg.attach(part)

    email = smtplib.SMTP('your-smtp-host-name.com')
    email.sendmail(from_email, to_email, msg.as_string())

我希望这能有所帮助!: -)

from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib

msg = MIMEMultipart()

password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()

我知道这是一个老问题，但我认为一定有一种比其他例子更简单的方法来做到这一点，因此我做了一个库，在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:

from redmail import EmailSender
from pathlib import Path

# Configure an email sender
email = EmailSender(
    host="<SMTP HOST>", port=0,
    user_name="me@example.com", password="<PASSWORD>"
)

# Send an email
email.send(
    sender="me@example.com",
    receivers=["you@example.com"],
    subject="An example email"
    attachments={
        "myfile.txt": Path("path/to/a_file.txt"),
        "myfile.html": "<h1>Content of a HTML attachment</h1>"
    }
)

你也可以直接附加字节，Pandas DataFrame(根据键中的文件扩展名转换为格式)，Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。

如何安装:

pip install redmail

你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/