我一直在使用ES6 Promise。

通常,Promise是这样构造和使用的

new Promise(function(resolve, reject){
    if (someCondition){
        resolve();
    } else {
        reject();
    } 
});

但我一直在做下面这样的事情,为了灵活起见,把决心放在外面。

var outsideResolve;
var outsideReject;
new Promise(function(resolve, reject) { 
    outsideResolve = resolve; 
    outsideReject = reject; 
});

后来

onClick = function(){
    outsideResolve();
}

这很好,但是否有更简单的方法来做到这一点?如果不是,这是一个好的实践吗?


当前回答

如果(像我一样)你不喜欢增强本地实例,也不笨重”。承诺“属性……但是如果你喜欢代理和破坏类,那么这个是给你的:

class GroovyPromise {
  constructor() {
    return new Proxy(new Promise((resolve, reject) => {
      this.resolve = resolve;
      this.reject = reject;
    }), {
      get: (target, prop) =>
        this[prop] || target[prop].bind(target),
    });
  }
}

这样用:

const groovypromise = new GroovyPromise();
setTimeout(() => groovypromise.resolve('groovy'), 1000);
console.log(await groovypromise);

当然,你也可以将类重命名为“Deferred”

其他回答

如何创建一个函数劫持拒绝并返回它?

function createRejectablePromise(handler) {
  let _reject;

  const promise = new Promise((resolve, reject) => {
    _reject = reject;

    handler(resolve, reject);
  })

  promise.reject = _reject;
  return promise;
}

// Usage
const { reject } = createRejectablePromise((resolve) => {
  setTimeout(() => {
    console.log('resolved')
    resolve();
  }, 2000)

});

reject();

我们的解决方案是使用闭包来存储解析/拒绝函数,并附加一个函数来扩展承诺本身。

模式如下:

function getPromise() {

    var _resolve, _reject;

    var promise = new Promise((resolve, reject) => {
        _reject = reject;
        _resolve = resolve;
    });

    promise.resolve_ex = (value) => {
       _resolve(value);
    };

    promise.reject_ex = (value) => {
       _reject(value);
    };

    return promise;
}

使用它:

var promise = getPromise();

promise.then(value => {
    console.info('The promise has been fulfilled: ' + value);
});

promise.resolve_ex('hello');  
// or the reject version 
//promise.reject_ex('goodbye');

以防有人来找简化这个任务的util的typescript版本:

export const deferred = <T>() => {
  let resolve!: (value: T | PromiseLike<T>) => void;
  let reject!: (reason?: any) => void;
  const promise = new Promise<T>((res, rej) => {
    resolve = res;
    reject = rej;
  });

  return {
    resolve,
    reject,
    promise,
  };
};

这可以用在。如:

const {promise, resolve} = deferred<string>();

promise.then((value) => console.log(value)); // nothing

resolve('foo'); // console.log: foo

我想分享一些不同的东西,这是这个话题的延伸。

有时,您希望“任务承诺”在解析时自动在相同的地址(属性或变量)重新创建。可以创建一个外部解析器来完成这个任务。

一个带有外部解析器的重复承诺的例子。无论何时调用解析器,都会在相同的地址/变量/属性处创建一个新的承诺。

let resolvePromise;
let thePromise;

const setPromise = (resolve) => {
  resolvePromise = () => {
    resolve();
    thePromise = new Promise(setPromise);   
  }
}
thePromise = new Promise(setPromise);

(async () => {
  let i = 0;
  while (true) {
    let msg = (i % 2 === 0) ? 'Tick' : 'Tock';
    document.body.innerHTML = msg;
    setTimeout(resolvePromise, 1000);
    await thePromise;
    i++;
  }
})();

https://jsfiddle.net/h3zvw5xr

类版本,在Typescript中:

export class Deferred<T> {
    public readonly promise: Promise<T>
    private resolveFn!: (value: T | PromiseLike<T>) => void
    private rejectFn!: (reason?: any) => void

    public constructor() {
        this.promise = new Promise<T>((resolve, reject) => {
            this.resolveFn = resolve
            this.rejectFn = reject
        })
    }

    public reject(reason?: any): void {
        this.rejectFn(reason)
    }

    public resolve(param: T): void {
        this.resolveFn(param)
    }
}