我如何找到一个Bash脚本位于该脚本内部的目录的路径?

我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:

$ ./application

当前回答

关键部分是,我正在减少问题的范围:我禁止通过路径间接执行脚本(如 /bin/sh [脚本路径与路径组件有关])。

这可以被检测到,因为0美元将是一个相对的路径,不解决与当前文件夹有关的任何文件。我相信使用#!机制的直接执行总是导致绝对0美元,包括当脚本在路径上找到时。

我也要求在象征性链接链接链接的任何字符和字符只包含一个合理的字符子,特别是不是 \n, >, * 或?. 这对于字符逻辑来说是必要的。

#!/bin/sh
(
    path="${0}"
    while test -n "${path}"; do
        # Make sure we have at least one slash and no leading dash.
        expr "${path}" : / > /dev/null || path="./${path}"
        # Filter out bad characters in the path name.
        expr "${path}" : ".*[*?<>\\]" > /dev/null && exit 1
        # Catch embedded new-lines and non-existing (or path-relative) files.
        # $0 should always be absolute when scripts are invoked through "#!".
        test "`ls -l -d "${path}" 2> /dev/null | wc -l`" -eq 1 || exit 1
        # Change to the folder containing the file to resolve relative links.
        folder=`expr "${path}" : "\(.*/\)[^/][^/]*/*$"` || exit 1
        path=`expr "x\`ls -l -d "${path}"\`" : "[^>]* -> \(.*\)"`
        cd "${folder}"
        # If the last path was not a link then we are in the target folder.
        test -n "${path}" || pwd
    done
)

其他回答

我用三种不同的处决尝试了追踪。

echo $(实际上是 $_)

. application         # /correct/path/to/dir or /path/to/temporary_dir
bash application      # /path/to/bash
/PATH/TO/application  # /correct/path/to/dir

echo $(相当于 $(相当于 $0))

. application         # failed with `realpath: missing operand`
bash application      # /correct/path/to/dir
/PATH/TO/application  # /correct/path/to/dir

echo $(相当于 $BASH_SOURCE)

$BASH_SOURCE 基本上与 ${BASH_SOURCE[0]} 相同。

. application         # /correct/path/to/dir
bash application      # /correct/path/to/dir
/PATH/TO/application  # /correct/path/to/dir

只有$(实际上是$BASH_SOURCE)似乎是可靠的。

如果不是由父母脚本来源,而不是同链接,0美元就足够了:

script_path="$0"

如果源于父母脚本而不是同链接,请使用 $BASH_SOURCE 或 ${BASH_SOURCE[0]}:

script_path="$BASH_SOURCE"

如果是同链接,请使用 $BASH_SOURCE 与 realpath 或 readlink -f 获取真正的文件路径:

script_path="$(realpath "$BASH_SOURCE")"

此外,路径或 readlink -f 返回绝对路径。

要获取脚本的目录,使用 dirname:

script_directory="$(dirname "$script_path")"

笔记

对于 MacOS 而言,请在这里或在这里找到一个替代路径或阅读链接 -f. 要使代码与不为 Bash 的支柱兼容,请使用 ${var-string} 参数扩展。

我相信我得到了这个一个,我迟到了派对,但我认为有些人会欣赏它在这里,如果他们通过这个条纹。

#!/bin/sh # dash bash ksh # !zsh (issues). G. Nixon, 12/2013. Public domain.

## 'linkread' or 'fullpath' or (you choose) is a little tool to recursively
## dereference symbolic links (ala 'readlink') until the originating file
## is found. This is effectively the same function provided in stdlib.h as
## 'realpath' and on the command line in GNU 'readlink -f'.

## Neither of these tools, however, are particularly accessible on the many
## systems that do not have the GNU implementation of readlink, nor ship
## with a system compiler (not to mention the requisite knowledge of C).

## This script is written with portability and (to the extent possible, speed)
## in mind, hence the use of printf for echo and case statements where they
## can be substituded for test, though I've had to scale back a bit on that.

## It is (to the best of my knowledge) written in standard POSIX shell, and
## has been tested with bash-as-bin-sh, dash, and ksh93. zsh seems to have
## issues with it, though I'm not sure why; so probably best to avoid for now.

## Particularly useful (in fact, the reason I wrote this) is the fact that
## it can be used within a shell script to find the path of the script itself.
## (I am sure the shell knows this already; but most likely for the sake of
## security it is not made readily available. The implementation of "$0"
## specificies that the $0 must be the location of **last** symbolic link in
## a chain, or wherever it resides in the path.) This can be used for some
## ...interesting things, like self-duplicating and self-modifiying scripts.

## Currently supported are three errors: whether the file specified exists
## (ala ENOENT), whether its target exists/is accessible; and the special
## case of when a sybolic link references itself "foo -> foo": a common error
## for beginners, since 'ln' does not produce an error if the order of link
## and target are reversed on the command line. (See POSIX signal ELOOP.)

## It would probably be rather simple to write to use this as a basis for
## a pure shell implementation of the 'symlinks' util included with Linux.

## As an aside, the amount of code below **completely** belies the amount
## effort it took to get this right -- but I guess that's coding for you.

##===-------------------------------------------------------------------===##

for argv; do :; done # Last parameter on command line, for options parsing.

## Error messages. Use functions so that we can sub in when the error occurs.

recurses(){ printf "Self-referential:\n\t$argv ->\n\t$argv\n" ;}
dangling(){ printf "Broken symlink:\n\t$argv ->\n\t"$(readlink "$argv")"\n" ;}
errnoent(){ printf "No such file: "$@"\n" ;} # Borrow a horrible signal name.

# Probably best not to install as 'pathfull', if you can avoid it.

pathfull(){ cd "$(dirname "$@")"; link="$(readlink "$(basename "$@")")"

## 'test and 'ls' report different status for bad symlinks, so we use this.

 if [ ! -e "$@" ]; then if $(ls -d "$@" 2>/dev/null) 2>/dev/null;  then
    errnoent 1>&2; exit 1; elif [ ! -e "$@" -a "$link" = "$@" ];   then
    recurses 1>&2; exit 1; elif [ ! -e "$@" ] && [ ! -z "$link" ]; then
    dangling 1>&2; exit 1; fi
 fi

## Not a link, but there might be one in the path, so 'cd' and 'pwd'.

 if [ -z "$link" ]; then if [ "$(dirname "$@" | cut -c1)" = '/' ]; then
   printf "$@\n"; exit 0; else printf "$(pwd)/$(basename "$@")\n"; fi; exit 0
 fi

## Walk the symlinks back to the origin. Calls itself recursivly as needed.

 while [ "$link" ]; do
   cd "$(dirname "$link")"; newlink="$(readlink "$(basename "$link")")"
   case "$newlink" in
    "$link") dangling 1>&2 && exit 1                                       ;;
         '') printf "$(pwd)/$(basename "$link")\n"; exit 0                 ;;
          *) link="$newlink" && pathfull "$link"                           ;;
   esac
 done
 printf "$(pwd)/$(basename "$newlink")\n"
}

## Demo. Install somewhere deep in the filesystem, then symlink somewhere 
## else, symlink again (maybe with a different name) elsewhere, and link
## back into the directory you started in (or something.) The absolute path
## of the script will always be reported in the usage, along with "$0".

if [ -z "$argv" ]; then scriptname="$(pathfull "$0")"

# Yay ANSI l33t codes! Fancy.
 printf "\n\033[3mfrom/as: \033[4m$0\033[0m\n\n\033[1mUSAGE:\033[0m   "
 printf "\033[4m$scriptname\033[24m [ link | file | dir ]\n\n         "
 printf "Recursive readlink for the authoritative file, symlink after "
 printf "symlink.\n\n\n         \033[4m$scriptname\033[24m\n\n        "
 printf " From within an invocation of a script, locate the script's "
 printf "own file\n         (no matter where it has been linked or "
 printf "from where it is being called).\n\n"

else pathfull "$@"
fi

以下是获取脚本信息的简短方式:

文件和文件:

    Script: "/tmp/src dir/test.sh"
    Calling folder: "/tmp/src dir/other"

使用这些命令:

    echo Script-Dir : `dirname "$(realpath $0)"`
    echo Script-Dir : $( cd ${0%/*} && pwd -P )
    echo Script-Dir : $(dirname "$(readlink -f "$0")")
    echo
    echo Script-Name : `basename "$(realpath $0)"`
    echo Script-Name : `basename $0`
    echo
    echo Script-Dir-Relative : `dirname "$BASH_SOURCE"`
    echo Script-Dir-Relative : `dirname $0`
    echo
    echo Calling-Dir : `pwd`

我得到了这个结果:

     Script-Dir : /tmp/src dir
     Script-Dir : /tmp/src dir
     Script-Dir : /tmp/src dir

     Script-Name : test.sh
     Script-Name : test.sh

     Script-Dir-Relative : ..
     Script-Dir-Relative : ..

     Calling-Dir : /tmp/src dir/other

此分類上一篇: https://pastebin.com/J8KjxrPF

这对我来说工作了,当这里的其他答案没有:

thisScriptPath=`realpath $0`
thisDirPath=`dirname $thisScriptPath`
echo $thisDirPath