互斥锁:假设我们有临界区线程T1想要访问它，然后按照以下步骤进行。 T1:

锁 使用临界区 解锁

二进制信号量:它基于信号等待和信号工作。 等待将“s”的值减少1，通常“s”的值初始化为值“1”， 信号(s)使“s”值加1。如果“s”值为1表示没有人在使用临界区，当“s”值为0时表示临界区正在使用。 假设线程T2正在使用临界区，那么它遵循以下步骤。 T2:

Wait (s)//最初的s值是1，调用Wait后，它的值减少了1，即0 利用临界区 信号(s) //现在s值增加，变成1

Main difference between Mutex and Binary semaphore is in Mutext if thread lock the critical section then it has to unlock critical section no other thread can unlock it, but in case of Binary semaphore if one thread locks critical section using wait(s) function then value of s become "0" and no one can access it until value of "s" become 1 but suppose some other thread calls signal(s) then value of "s" become 1 and it allows other function to use critical section. hence in Binary semaphore thread doesn't have ownership.

厕所的例子是一个有趣的类比:

Mutex: Is a key to a toilet. One person can have the key - occupy the toilet - at the time. When finished, the person gives (frees) the key to the next person in the queue. Officially: "Mutexes are typically used to serialise access to a section of re-entrant code that cannot be executed concurrently by more than one thread. A mutex object only allows one thread into a controlled section, forcing other threads which attempt to gain access to that section to wait until the first thread has exited from that section." Ref: Symbian Developer Library (A mutex is really a semaphore with value 1.) Semaphore: Is the number of free identical toilet keys. Example, say we have four toilets with identical locks and keys. The semaphore count - the count of keys - is set to 4 at beginning (all four toilets are free), then the count value is decremented as people are coming in. If all toilets are full, ie. there are no free keys left, the semaphore count is 0. Now, when eq. one person leaves the toilet, semaphore is increased to 1 (one free key), and given to the next person in the queue. Officially: "A semaphore restricts the number of simultaneous users of a shared resource up to a maximum number. Threads can request access to the resource (decrementing the semaphore), and can signal that they have finished using the resource (incrementing the semaphore)." Ref: Symbian Developer Library

它们的同步语义非常不同:

互斥对象允许对给定资源的序列化访问，即多个线程等待一个锁，一次一个，正如前面所说，线程拥有锁，直到锁完成:只有这个特定的线程可以解锁它。 二进制信号量是一个值为0和1的计数器:任务阻塞在它上，直到任何任务执行sem_post。信号量宣布资源可用，并提供等待机制，直到发出可用信号。

因此，可以将互斥锁视为在任务之间传递的令牌，将信号量视为交通红灯(它向某人发出信号，表示可以继续进行)。

以上几乎所有人都说对了。如果有人还有疑问，让我来澄清一下。

互斥->用于序列化 信号- >同步。

两者的目的是不同的，但是，通过精心的编程，可以实现相同的功能。

标准示例->生产者消费者问题。

initial value of SemaVar=0

Producer                           Consumer
---                                SemaWait()->decrement SemaVar   
produce data
---
SemaSignal SemaVar or SemaVar++  --->consumer unblocks as SemVar is 1 now.

希望我能澄清。

互斥锁用于阻塞关键区域，而信号量用于计数。

修改问题是-互斥量和“二进制”信号量在“Linux”中的区别是什么?

答:以下是它们的区别 i)作用域——互斥锁的作用域在创建它的进程地址空间内，用于线程同步。而信号量可以跨进程空间使用，因此它可以用于进程间同步。

ii)互斥量是轻量级的，比信号量更快。Futex甚至更快。

iii)同一线程可以成功多次获得互斥锁，条件是互斥锁释放次数相同。其他线程试图获取将阻塞。而对于信号量，如果同一个进程试图再次获取它，它会阻塞，因为它只能获得一次。