我有一个很长的疑问。我想用Python将它分成几行。在JavaScript中实现这一点的一种方法是使用几个句子并用+运算符将它们连接起来(我知道,也许这不是最有效的方法,但我并不真正关心这个阶段的性能,只是代码的可读性)。例子:

var long_string = 'some text not important. just garbage to' +
                      'illustrate my example';

我尝试在Python中做类似的事情,但没有成功,所以我使用了\来拆分长字符串。然而,我不确定这是否是唯一/最好/最蟒蛇的做法。看起来很尴尬。实际代码:

query = 'SELECT action.descr as "action", '\
    'role.id as role_id,'\
    'role.descr as role'\
    'FROM '\
    'public.role_action_def,'\
    'public.role,'\
    'public.record_def, '\
    'public.action'\
    'WHERE role.id = role_action_def.role_id AND'\
    'record_def.id = role_action_def.def_id AND'\
    'action.id = role_action_def.action_id AND'\
    'role_action_def.account_id = ' + account_id + ' AND'\
    'record_def.account_id=' + account_id + ' AND'\
    'def_id=' + def_id

当前回答

tl;dr:使用“”和“”来换行字符串,如中所示

string = """\
This is a long string
spanning multiple lines.
"""

从Python官方文档中:

字符串文本可以跨越多行。一种方法是使用三引号:“”“…”“”或“”“”…“”。行的结束是自动的包含在字符串中,但可以通过添加\在线路的末端。以下示例:

print("""\
Usage: thingy [OPTIONS]
     -h                        Display this usage message
     -H hostname               Hostname to connect to
""")

生成以下输出(注意,初始换行符不是包括在内):

Usage: thingy [OPTIONS]
     -h                        Display this usage message
     -H hostname               Hostname to connect to

其他回答

通常,我对多行注释/string使用list和join。

lines = list()
lines.append('SELECT action.enter code here descr as "action", ')
lines.append('role.id as role_id,')
lines.append('role.descr as role')
lines.append('FROM ')
lines.append('public.role_action_def,')
lines.append('public.role,')
lines.append('public.record_def, ')
lines.append('public.action')
query = " ".join(lines)

您可以使用任何字符串连接所有这些列表元素,如“\n”(换行符)或“,”(逗号)或“”(空格)。

“la”Scala方式(但我认为这是OP要求的最具Python风格的方式):

description = """
            | The intention of this module is to provide a method to
            | pass meta information in markdown_ header files for
            | using it in jinja_ templates.
            |
            | Also, to provide a method to use markdown files as jinja
            | templates. Maybe you prefer to see the code than
            | to install it.""".replace('\n            | \n','\n').replace('            | ',' ')

如果您希望最后的str没有跳转行,只需将\n放在第二个替换的第一个参数的开头:

.replace('\n            | ',' ')`.

注意:“…templates.”和“另外,…”之间的白线需要在|后面加一个空格。

其他人已经提到了圆括号方法,但我想补充一点,使用圆括号时,允许内联注释。

对每个片段的注释:

nursery_rhyme = (
    'Mary had a little lamb,'          # Comments are great!
    'its fleece was white as snow.'
    'And everywhere that Mary went,'
    'her sheep would surely go.'       # What a pesky sheep.
)

继续后不允许注释:

使用反斜杠行延续符(\)时,不允许使用注释。您将收到一个SyntaxError:一行接一行的连续字符错误。

nursery_rhyme = 'Mary had a little lamb,' \  # These comments
    'its fleece was white as snow.'       \  # are invalid!
    'And everywhere that Mary went,'      \
    'her sheep would surely go.'
# => SyntaxError: unexpected character after line continuation character

Regex字符串的更好注释:

基于以下示例https://docs.python.org/3/library/re.html#re.VERBOSE,

a = re.compile(
    r'\d+'  # the integral part
    r'\.'   # the decimal point
    r'\d*'  # some fractional digits
)
# Using VERBOSE flag, IDE usually can't syntax highight the string comment.
a = re.compile(r"""\d +  # the integral part
                   \.    # the decimal point
                   \d *  # some fractional digits""", re.X)

添加@Levon的答案。。。。

1.创建如下多行字符串:

paragraph = """this is a very
        long string if I had the
        energy to type more and more ..."""

print(paragraph)

输出:

'this is a very\n        long string if I had the\n        energy to type more and more ...'

此字符串将包含换行符和空格。因此,请移除它们。

2.使用正则表达式删除多余的空格

paragraph = re.sub('\s+', ' ', paragraph)
print(paragraph)

输出:

'this is a very long string if I had the energy to type more and more ...'

我使用递归函数来构建复杂的SQL查询。此技术通常可用于构建大型字符串,同时保持代码可读性。

# Utility function to recursively resolve SQL statements.
# CAUTION: Use this function carefully, Pass correct SQL parameters {},
# TODO: This should never happen but check for infinite loops
def resolveSQL(sql_seed, sqlparams):
    sql = sql_seed % (sqlparams)
    if sql == sql_seed:
        return ' '.join([x.strip() for x in sql.split()])
    else:
        return resolveSQL(sql, sqlparams)

P.S.:看看很棒的python-sqlparse库,如果需要,可以打印SQL查询。