结合以下观点：

Levon或Jesse、Faheel和ddrscott

根据我的格式建议，您可以将查询写成：

query = ('SELECT'
             ' action.descr as "action"'
             ',role.id as role_id'
             ',role.descr as role'
         ' FROM'
             ' public.role_action_def'
             ',public.role'
             ',public.record_def'
             ',public.action'
         ' WHERE'
             ' role.id = role_action_def.role_id'
             ' AND'
             ' record_def.id = role_action_def.def_id'
             ' AND'
             ' action.id = role_action_def.action_id'
             ' AND'
             ' role_action_def.account_id = ?' # account_id
             ' AND'
             ' record_def.account_id = ?'      # account_id
             ' AND'
             ' def_id = ?'                     # def_id
         )

 vars = (account_id, account_id, def_id)     # A tuple of the query variables
 cursor.execute(query, vars)                 # Using Python's sqlite3 module

或类似：

vars = []
query = ('SELECT'
             ' action.descr as "action"'
             ',role.id as role_id'
             ',role.descr as role'
         ' FROM'
             ' public.role_action_def'
             ',public.role'
             ',public.record_def'
             ',public.action'
         ' WHERE'
             ' role.id = role_action_def.role_id'
             ' AND'
             ' record_def.id = role_action_def.def_id'
             ' AND'
             ' action.id = role_action_def.action_id'
             ' AND'
             ' role_action_def.account_id = '
                 vars.append(account_id) or '?'
             ' AND'
             ' record_def.account_id = '
                 vars.append(account_id) or '?'
             ' AND'
             ' def_id = '
                 vars.append(def_id) or '?'
         )

 cursor.execute(query, tuple(vars))  # Using Python's sqlite3 module

与“IN”和“vars.extend（options）”或“n_options（len（option））”一起使用可能很有趣，其中：

def n_options(count):
    return '(' + ','.join(count*'?') + ')'

或者从darkcaline那里得到的提示是，您可能仍然会在使用前导空格和分隔符以及命名占位符时出错：

SPACE_SEP = ' '
COMMA_SEP = ', '
AND_SEP   = ' AND '

query = SPACE_SEP.join((
    'SELECT',
        COMMA_SEP.join((
        'action.descr as "action"',
        'role.id as role_id',
        'role.descr as role',
        )),
    'FROM',
        COMMA_SEP.join((
        'public.role_action_def',
        'public.role',
        'public.record_def',
        'public.action',
        )),
    'WHERE',
        AND_SEP.join((
        'role.id = role_action_def.role_id',
        'record_def.id = role_action_def.def_id',
        'action.id = role_action_def.action_id',
        'role_action_def.account_id = :account_id',
        'record_def.account_id = :account_id',
        'def_id = :def_id',
        )),
    ))

vars = {'account_id':account_id,'def_id':def_id}  # A dictionary of the query variables
cursor.execute(query, vars)                       # Using Python's sqlite3 module

请参阅Cursor.execute-function的文档。

“这是[最Python]的方式！”-。。。

该方法使用：

使用三引号字符串几乎没有内部标点符号使用检查模块去除局部压痕account_id和def_id变量使用Python 3.6格式的字符串插值（'f'）。

这种方式在我看来是最有蟒蛇风格的。

import inspect

query = inspect.cleandoc(f'''
    SELECT action.descr as "action",
    role.id as role_id,
    role.descr as role
    FROM
    public.role_action_def,
    public.role,
    public.record_def,
    public.action
    WHERE role.id = role_action_def.role_id AND
    record_def.id = role_action_def.def_id AND
    action.id = role_action_def.action_id AND
    role_action_def.account_id = {account_id} AND
    record_def.account_id={account_id} AND
    def_id={def_id}'''
)

我使用递归函数来构建复杂的SQL查询。此技术通常可用于构建大型字符串，同时保持代码可读性。

# Utility function to recursively resolve SQL statements.
# CAUTION: Use this function carefully, Pass correct SQL parameters {},
# TODO: This should never happen but check for infinite loops
def resolveSQL(sql_seed, sqlparams):
    sql = sql_seed % (sqlparams)
    if sql == sql_seed:
        return ' '.join([x.strip() for x in sql.split()])
    else:
        return resolveSQL(sql, sqlparams)

P.S.：看看很棒的python-sqlparse库，如果需要，可以打印SQL查询。

例如：

sql = ("select field1, field2, field3, field4 "
       "from table "
       "where condition1={} "
       "and condition2={}").format(1, 2)

Output: 'select field1, field2, field3, field4 from table
         where condition1=1 and condition2=2'

如果条件的值应该是字符串，可以这样做：

sql = ("select field1, field2, field3, field4 "
       "from table "
       "where condition1='{0}' "
       "and condition2='{1}'").format('2016-10-12', '2017-10-12')

Output: "select field1, field2, field3, field4 from table where
         condition1='2016-10-12' and condition2='2017-10-12'"

我发现textwrap.dedent最适合长字符串，如下所述：

def create_snippet():
    code_snippet = textwrap.dedent("""\
        int main(int argc, char* argv[]) {
            return 0;
        }
    """)
    do_something(code_snippet)

你说的是多行字符串吗？简单，使用三引号开始和结束它们。

s = """ this is a very
        long string if I had the
        energy to type more and more ..."""

您也可以使用单引号（当然，在开始和结束处有3个引号），并像对待任何其他字符串一样对待生成的字符串。

注意：与任何字符串一样，起始引号和结束引号之间的任何内容都将成为字符串的一部分，因此本示例有一个前导空格（如@root45所指出的）。此字符串还将包含空格和换行符。

即。，：

' this is a very\n        long string if I had the\n        energy to type more and more ...'

最后，您还可以在Python中构造如下的长行：

 s = ("this is a very"
      "long string too"
      "for sure ..."
     )

这将不包括任何额外的空格或换行符（这是一个故意的示例，显示跳过空格的效果）：

'this is a verylong string toofor sure ...'

不需要逗号，只需将要连接在一起的字符串放入一对括号中，并确保考虑到任何需要的空格和换行符。