如何在Python中漂亮地打印深度为~4的字典?我尝试用pprint()进行漂亮的打印,但它不起作用:
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(mydict)
我只是想要一个缩进(“\t”)为每个嵌套,这样我就会得到这样的东西:
key1
value1
value2
key2
value1
value2
等。
我该怎么做呢?
如何在Python中漂亮地打印深度为~4的字典?我尝试用pprint()进行漂亮的打印,但它不起作用:
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(mydict)
我只是想要一个缩进(“\t”)为每个嵌套,这样我就会得到这样的东西:
key1
value1
value2
key2
value1
value2
等。
我该怎么做呢?
当前回答
这是我在编写一个需要在.txt文件中编写字典的类时想到的:
@staticmethod
def _pretty_write_dict(dictionary):
def _nested(obj, level=1):
indentation_values = "\t" * level
indentation_braces = "\t" * (level - 1)
if isinstance(obj, dict):
return "{\n%(body)s%(indent_braces)s}" % {
"body": "".join("%(indent_values)s\'%(key)s\': %(value)s,\n" % {
"key": str(key),
"value": _nested(value, level + 1),
"indent_values": indentation_values
} for key, value in obj.items()),
"indent_braces": indentation_braces
}
if isinstance(obj, list):
return "[\n%(body)s\n%(indent_braces)s]" % {
"body": "".join("%(indent_values)s%(value)s,\n" % {
"value": _nested(value, level + 1),
"indent_values": indentation_values
} for value in obj),
"indent_braces": indentation_braces
}
else:
return "\'%(value)s\'" % {"value": str(obj)}
dict_text = _nested(dictionary)
return dict_text
现在,如果我们有一个这样的字典:
some_dict = {'default': {'ENGINE': [1, 2, 3, {'some_key': {'some_other_key': 'some_value'}}], 'NAME': 'some_db_name', 'PORT': '', 'HOST': 'localhost', 'USER': 'some_user_name', 'PASSWORD': 'some_password', 'OPTIONS': {'init_command': 'SET foreign_key_checks = 0;'}}}
我们这样做:
print(_pretty_write_dict(some_dict))
我们得到:
{
'default': {
'ENGINE': [
'1',
'2',
'3',
{
'some_key': {
'some_other_key': 'some_value',
},
},
],
'NAME': 'some_db_name',
'OPTIONS': {
'init_command': 'SET foreign_key_checks = 0;',
},
'HOST': 'localhost',
'USER': 'some_user_name',
'PASSWORD': 'some_password',
'PORT': '',
},
}
其他回答
我把sth的答案稍微修改一下,以适应我的嵌套字典和列表的需要:
def pretty(d, indent=0):
if isinstance(d, dict):
for key, value in d.iteritems():
print '\t' * indent + str(key)
if isinstance(value, dict) or isinstance(value, list):
pretty(value, indent+1)
else:
print '\t' * (indent+1) + str(value)
elif isinstance(d, list):
for item in d:
if isinstance(item, dict) or isinstance(item, list):
pretty(item, indent+1)
else:
print '\t' * (indent+1) + str(item)
else:
pass
然后输出如下:
>>>
xs:schema
@xmlns:xs
http://www.w3.org/2001/XMLSchema
xs:redefine
@schemaLocation
base.xsd
xs:complexType
@name
Extension
xs:complexContent
xs:restriction
@base
Extension
xs:sequence
xs:element
@name
Policy
@minOccurs
1
xs:complexType
xs:sequence
xs:element
...
晚了,但是这个答案不需要任何额外的库。类似于STH的答案,但在格式上更健壮一点,并返回一个完整的字符串,然后可以打印:
def pretty_print_dict(
input_dictionary,
indent=1,
depth=0
):
# Bool flag to add comma's after first item in dict.
needs_comma = False
# String for any dict will start with a '{'
return_string = '\t' * depth + '{\n'
# Iterate over keys and values, building the full string out.
for key, value in input_dictionary.items():
# Start with key. If key follows a previous item, add comma.
if needs_comma:
return_string = return_string + ',\n' + '\t' * (depth + 1) + str(key) + ': '
else:
return_string = return_string + '\t' * (depth + 1) + str(key) + ': '
# If the value is a dict, recursively call function.
if isinstance(value, dict):
return_string = return_string + '\n' + pretty_print_dict(value, depth=depth+2)
else:
return_string = return_string + '\t' * indent + str(value)
# After first line, flip bool to True to make sure commas make it.
needs_comma = True
# Complete the dict with a '}'
return_string = return_string + '\n' + '\t' * depth + '}'
# Return dict string.
return return_string
让我们看看它如何处理像test_dict={1,2,3:{4:{5:6}, 7:8}, 9:10}这样的字典。
字符串的样子:“{\ n \ t1: \ t2, t3: \ n \ \ n \ t \ {\ n \ t \ \ t4: \ n \ t \ t \ \ {\ n \ t \ t \ \ \ t5: \ t6 \ n \ t \ t \ \ t}, \ n \ t \ \ t7: \ t8 \ n \ t \ t}, \ n \ t9: \ t10 \ n}”。
打印该字符串会得到:
{
1: 2,
3:
{
4:
{
5: 6
},
7: 8
},
9: 10
}
这里的现代解决方案是使用富。安装与
pip install rich
使用as
from rich import print
d = {
"Alabama": "Montgomery",
"Alaska": "Juneau",
"Arizona": "Phoenix",
"Arkansas": "Little Rock",
"California": "Sacramento",
"Colorado": "Denver",
"Connecticut": "Hartford",
"Delaware": "Dover",
"Florida": "Tallahassee",
"Georgia": "Atlanta",
"Hawaii": "Honolulu",
"Idaho": "Boise",
}
print(d)
输出很好地缩进:
最简单的方法是安装IPython并使用如下所示的方法
from IPython.lib.pretty import pretty
class MyClass:
__repr__(self):
return pretty(data) # replace data with what makes sense
在你的情况下
print(pretty(mydict))
我必须传递默认参数,就像这样:
print(json.dumps(my_dictionary, indent=4, default=str))
如果你想要键排序,你可以这样做:
print(json.dumps(my_dictionary, sort_keys=True, indent=4, default=str))
为了修复此类型错误:
TypeError: Object of type 'datetime' is not JSON serializable
这是由于datetimes是字典中的一些值。