我正在寻找一种方法来检测单击事件是否发生在组件之外，如本文所述。jQueryclosest（）用于查看单击事件的目标是否将dom元素作为其父元素之一。如果存在匹配项，则单击事件属于其中一个子项，因此不被视为在组件之外。
因此，在我的组件中，我想将一个单击处理程序附加到窗口。当处理程序启动时，我需要将目标与组件的dom子级进行比较。
click事件包含类似“path”的财产，它似乎保存了事件经过的dom路径。我不知道该比较什么，或者如何最好地遍历它，我想肯定有人已经把它放在了一个聪明的效用函数中。。。不
当前回答
我为所有场合制定了解决方案。
你应该使用一个高阶组件来包装你想要监听的组件。
这个组件示例只有一个属性：“onClickedOutside”，它接收函数。
ClickedOutside.js
import React, { Component } from "react";
export default class ClickedOutside extends Component {
componentDidMount() {
document.addEventListener("mousedown", this.handleClickOutside);
}
componentWillUnmount() {
document.removeEventListener("mousedown", this.handleClickOutside);
}
handleClickOutside = event => {
// IF exists the Ref of the wrapped component AND his dom children doesnt have the clicked component
if (this.wrapperRef && !this.wrapperRef.contains(event.target)) {
// A props callback for the ClikedClickedOutside
this.props.onClickedOutside();
}
};
render() {
// In this piece of code I'm trying to get to the first not functional component
// Because it wouldn't work if use a functional component (like <Fade/> from react-reveal)
let firstNotFunctionalComponent = this.props.children;
while (typeof firstNotFunctionalComponent.type === "function") {
firstNotFunctionalComponent = firstNotFunctionalComponent.props.children;
}
// Here I'm cloning the element because I have to pass a new prop, the "reference"
const children = React.cloneElement(firstNotFunctionalComponent, {
ref: node => {
this.wrapperRef = node;
},
// Keeping all the old props with the new element
...firstNotFunctionalComponent.props
});
return <React.Fragment>{children}</React.Fragment>;
}
}
其他回答
你可以用一个简单的方法来解决你的问题，我向你展示：
....
const [dropDwonStatus , setDropDownStatus] = useState(false)
const openCloseDropDown = () =>{
setDropDownStatus(prev => !prev)
}
const closeDropDown = ()=> {
if(dropDwonStatus){
setDropDownStatus(false)
}
}
.
.
.
<parent onClick={closeDropDown}>
<child onClick={openCloseDropDown} />
</parent>
这对我有用，祝你好运；）
将onClick处理程序添加到顶级容器中，并在用户单击时增加状态值。将该值传递给相关组件，每当该值发生变化时，您就可以执行操作。
在本例中，每当clickCount值更改时，我们都会调用this.closeDropdown（）。
incrementClickCount方法在.app容器中激发，而不是在下拉列表中激发，因为我们使用event.stopPropagation（）来防止事件冒泡。
您的代码可能最终看起来像这样：
class App extends Component {
constructor(props) {
super(props);
this.state = {
clickCount: 0
};
}
incrementClickCount = () => {
this.setState({
clickCount: this.state.clickCount + 1
});
}
render() {
return (
<div className="app" onClick={this.incrementClickCount}>
<Dropdown clickCount={this.state.clickCount}/>
</div>
);
}
}
class Dropdown extends Component {
constructor(props) {
super(props);
this.state = {
open: false
};
}
componentDidUpdate(prevProps) {
if (this.props.clickCount !== prevProps.clickCount) {
this.closeDropdown();
}
}
toggleDropdown = event => {
event.stopPropagation();
return (this.state.open) ? this.closeDropdown() : this.openDropdown();
}
render() {
return (
<div className="dropdown" onClick={this.toggleDropdown}>
...
</div>
);
}
}
非侵入性方式无需添加另一个DIV EL。
注意：React可能会说findDomNode已弃用，但到目前为止，我还没有遇到任何问题
@异常：单击要忽略的类
@idException:单击时忽略的id
import React from "react"
import ReactDOM from "react-dom"
type Func1<T1, R> = (a1: T1) => R
export function closest(
el: Element,
fn: (el: Element) => boolean
): Element | undefined {
let el_: Element | null = el;
while (el_) {
if (fn(el_)) {
return el_;
}
el_ = el_.parentElement;
}
}
let instances: ClickOutside[] = []
type Props = {
idException?: string,
exceptions?: (string | Func1<MouseEvent, boolean>)[]
handleClickOutside: Func1<MouseEvent, void>
}
export default class ClickOutside extends React.Component<Props> {
static defaultProps = {
exceptions: []
};
componentDidMount() {
if (instances.length === 0) {
document.addEventListener("mousedown", this.handleAll, true)
window.parent.document.addEventListener(
"mousedown",
this.handleAll,
true
)
}
instances.push(this)
}
componentWillUnmount() {
instances.splice(instances.indexOf(this), 1)
if (instances.length === 0) {
document.removeEventListener("mousedown", this.handleAll, true)
window.parent.document.removeEventListener(
"mousedown",
this.handleAll,
true
)
}
}
handleAll = (e: MouseEvent) => {
const target: HTMLElement = e.target as HTMLElement
if (!target) return
instances.forEach(instance => {
const { exceptions, handleClickOutside: onClickOutside, idException } = instance.props as Required<Props>
let exceptionsCount = 0
if (exceptions.length > 0) {
const { functionExceptions, stringExceptions } = exceptions.reduce(
(acc, exception) => {
switch (typeof exception) {
case "function":
acc.functionExceptions.push(exception)
break
case "string":
acc.stringExceptions.push(exception)
break
}
return acc
},
{ functionExceptions: [] as Func1<MouseEvent, boolean>[], stringExceptions: [] as string[] }
)
if (functionExceptions.length > 0) {
exceptionsCount += functionExceptions.filter(
exception => exception(e) === true
).length
}
if (exceptionsCount === 0 && stringExceptions.length > 0) {
const el = closest(target, (e) => stringExceptions.some(ex => e.classList.contains(ex)))
if (el) {
exceptionsCount++
}
}
}
if (idException) {
const target = e.target as HTMLDivElement
if (document.getElementById(idException)!.contains(target)) {
exceptionsCount++
}
}
if (exceptionsCount === 0) {
// eslint-disable-next-line react/no-find-dom-node
const node = ReactDOM.findDOMNode(instance)
if (node && !node.contains(target)) {
onClickOutside(e)
}
}
})
};
render() {
return React.Children.only(this.props.children)
}
}
用法
<ClickOutside {...{ handleClickOutside: () => { alert('Clicked Outside') } }}>
<div >
<div>Breathe</div>
</div>
</ClickOutside>
这是最适合我制作下拉菜单的方法：
handleClick = () => {
document.getElementById("myDrop").classList.toggle("showing");
}
render() {
return (
<div className="courses">
<div class="dropdownBody">
<button onClick={this.handleClick} onBlur={this.handleClick} class="dropbtn">Dropdown</button>
<div id="myDrop" class="dropdown-content">
<a href="#home">Home</a>
<a href="#about">About</a>
<a href="#contact">Contact</a>
</div>
</div>
</div>
)
}
您只需在主体上安装一个双击处理程序，并在此元素上安装另一个。在该元素的处理程序中，只需返回false以防止事件传播。因此，当双击发生时，如果它在元素上，它将被捕获，并且不会传播到主体上的处理程序。否则它会被身体上的处理程序抓住。
更新：如果你真的不想阻止事件传播，你只需要使用closest来检查点击是发生在你的元素还是他的一个孩子身上：
<html>
<head>
<script src="https://code.jquery.com/jquery-2.1.4.min.js"></script>
<script>
$(document).on('click', function(event) {
if (!$(event.target).closest('#div3').length) {
alert("outside");
}
});
</script>
</head>
<body>
<div style="background-color:blue;width:100px;height:100px;" id="div1"></div>
<div style="background-color:red;width:100px;height:100px;" id="div2"></div>
<div style="background-color:green;width:100px;height:100px;" id="div3"></div>
<div style="background-color:yellow;width:100px;height:100px;" id="div4"></div>
<div style="background-color:grey;width:100px;height:100px;" id="div5"></div>
</body>
</html>
更新：不带jQuery:
<html>
<head>
<script>
function findClosest (element, fn) {
if (!element) return undefined;
return fn(element) ? element : findClosest(element.parentElement, fn);
}
document.addEventListener("click", function(event) {
var target = findClosest(event.target, function(el) {
return el.id == 'div3'
});
if (!target) {
alert("outside");
}
}, false);
</script>
</head>
<body>
<div style="background-color:blue;width:100px;height:100px;" id="div1"></div>
<div style="background-color:red;width:100px;height:100px;" id="div2"></div>
<div style="background-color:green;width:100px;height:100px;" id="div3">
<div style="background-color:pink;width:50px;height:50px;" id="div6"></div>
</div>
<div style="background-color:yellow;width:100px;height:100px;" id="div4"></div>
<div style="background-color:grey;width:100px;height:100px;" id="div5"></div>
</body>
</html>
