这个问题快把我逼疯了,我不知道怎么解决它。

    Undefined symbols for architecture armv7:
  "_deflateEnd", referenced from:
      -[ASIDataCompressor closeStream] in ASIDataCompressor.o
  "_OBJC_CLASS_$_ASIDataDecompressor", referenced from:
      objc-class-ref in ASIHTTPRequest.o
  "_deflate", referenced from:
      -[ASIDataCompressor compressBytes:length:error:shouldFinish:] in ASIDataCompressor.o
  "_deflateInit2_", referenced from:
      -[ASIDataCompressor setupStream] in ASIDataCompressor.o
ld: symbol(s) not found for architecture armv7
collect2: ld returned 1 exit status
Command /Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/gcc-4.2 failed with exit code 1

我认为这与:

ld: symbol(s) not found for architecture armv7

但是我添加了:libz.1.2.3。Dylib并没有帮助,有人有什么想法吗?


当前回答

另一个可能导致“未定义符号”链接错误的原因是试图从.mm文件调用C函数。在这种情况下,您需要使用extern“C”{…}当您导入头文件时。

从objective - c++调用C-Function链接器错误

其他回答

当我使用admob库时,我也有同样的问题,我修复了它将“架构”更改为“标准架构armv7, armv7s”,而不包括64位。

对我来说,问题是我忘记在.m(实现)中为我的常量设置值

file const kFooKey = @"Foo";

尝试实现派生类的至少一个非内联函数。如果不这样做,链接器可能会避免为该类创建类型信息。

我遇到了类似的问题,我必须在每个项目配置(调试、发布和部署)和目标的构建设置中检查“仅构建活动体系结构”。

如果您在释放模式下构建您的Flutter项目时遇到了这个问题-这对我有帮助:

Set your build system to New Build System in File > Project Settings… delete folders ios and build_ios from your project folder. create ios module by executing flutter create . from your project folder. open Xcode and: set the IOS Deployment Target to at least 9.0 in PROJECT > Runner check your Signing & Capabilities make sure your Build Configuration is set to Release in Edit Scheme... and build for Generic iOS Device execute pod install from your project folder execute flutter pub get from your project folder

现在打开你的Xcode并构建或存档它:Product > build(或archive)