如果你想列出/数组的整数，最简单的方法是接受逗号(，)分隔的字符串列表，并将其转换为整数列表。不要忘记提到[FromUri]属性。你的url看起来像:

... ?ID = 71&accountID = 1,2,3,289,56

public HttpResponseMessage test([FromUri]int ID, [FromUri]string accountID)
{
    List<int> accountIdList = new List<int>();
    string[] arrAccountId = accountId.Split(new char[] { ',' });
    for (var i = 0; i < arrAccountId.Length; i++)
    {
        try
        {
           accountIdList.Add(Int32.Parse(arrAccountId[i]));
        }
        catch (Exception)
        {
        }
    }
}

我已经创建了一个自定义模型绑定器，它将任何逗号分隔的值(仅为原语、十进制、浮点数、字符串)转换为相应的数组。

public class CommaSeparatedToArrayBinder<T> : IModelBinder
    {
        public bool BindModel(HttpActionContext actionContext, ModelBindingContext bindingContext)
        {
            Type type = typeof(T);
            if (type.IsPrimitive || type == typeof(Decimal) || type == typeof(String) || type == typeof(float))
            {
                ValueProviderResult val = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);
                if (val == null) return false;

                string key = val.RawValue as string;
                if (key == null) { bindingContext.ModelState.AddModelError(bindingContext.ModelName, "Wrong value type"); return false; }

                string[] values = key.Split(',');
                IEnumerable<T> result = this.ConvertToDesiredList(values).ToArray();
                bindingContext.Model = result;
                return true;
            }

            bindingContext.ModelState.AddModelError(bindingContext.ModelName, "Only primitive, decimal, string and float data types are allowed...");
            return false;
        }

        private IEnumerable<T> ConvertToDesiredArray(string[] values)
        {
            foreach (string value in values)
            {
                var val = (T)Convert.ChangeType(value, typeof(T));
                yield return val;
            }
        }
    }

以及如何在Controller中使用:

 public IHttpActionResult Get([ModelBinder(BinderType = typeof(CommaSeparatedToArrayBinder<int>))] int[] ids)
        {
            return Ok(ids);
        }

或者，您可以只传递一串分隔项，并将其放入接收端的数组或列表中。

正如Filip W指出的那样，你可能不得不求助于这样的自定义模型绑定器(修改为绑定到实际的参数类型):

public IEnumerable<Category> GetCategories([ModelBinder(typeof(CommaDelimitedArrayModelBinder))]long[] categoryIds) 
{
    // do your thing
}

public class CommaDelimitedArrayModelBinder : IModelBinder
{
    public bool BindModel(HttpActionContext actionContext, ModelBindingContext bindingContext)
    {
        var key = bindingContext.ModelName;
        var val = bindingContext.ValueProvider.GetValue(key);
        if (val != null)
        {
            var s = val.AttemptedValue;
            if (s != null)
            {
                var elementType = bindingContext.ModelType.GetElementType();
                var converter = TypeDescriptor.GetConverter(elementType);
                var values = Array.ConvertAll(s.Split(new[] { ","},StringSplitOptions.RemoveEmptyEntries),
                    x => { return converter.ConvertFromString(x != null ? x.Trim() : x); });

                var typedValues = Array.CreateInstance(elementType, values.Length);

                values.CopyTo(typedValues, 0);

                bindingContext.Model = typedValues;
            }
            else
            {
                // change this line to null if you prefer nulls to empty arrays 
                bindingContext.Model = Array.CreateInstance(bindingContext.ModelType.GetElementType(), 0);
            }
            return true;
        }
        return false;
    }
}

然后你可以说:

/类别?categoryids=1,2,3,4和ASP。NET Web API将正确绑定您的categoryIds数组。

简单的方法发送数组参数到web api

API

public IEnumerable<Category> GetCategories([FromUri]int[] categoryIds){
 // code to retrieve categories from database
}

Jquery:发送JSON对象作为请求参数

$.get('api/categories/GetCategories',{categoryIds:[1,2,3,4]}).done(function(response){
console.log(response);
//success response
});

它会生成你的请求URL . . / api /类别/ GetCategories吗?categoryid = 1 &categoryids = 2 &categoryids = 3 &categoryids = 4

将方法类型设置为[HttpPost]，创建一个有一个int[]参数的模型，并使用json post:

/* Model */
public class CategoryRequestModel 
{
    public int[] Categories { get; set; }
}

/* WebApi */
[HttpPost]
public HttpResponseMessage GetCategories(CategoryRequestModel model)
{
    HttpResponseMessage resp = null;

    try
    {
        var categories = //your code to get categories

        resp = Request.CreateResponse(HttpStatusCode.OK, categories);

    }
    catch(Exception ex)
    {
        resp = Request.CreateErrorResponse(HttpStatusCode.InternalServerError, ex);
    }

    return resp;
}

/* jQuery */
var ajaxSettings = {
    type: 'POST',
    url: '/Categories',
    data: JSON.serialize({Categories: [1,2,3,4]}),
    contentType: 'application/json',
    success: function(data, textStatus, jqXHR)
    {
        //get categories from data
    }
};

$.ajax(ajaxSettings);