我已经创建了一个自定义模型绑定器，它将任何逗号分隔的值(仅为原语、十进制、浮点数、字符串)转换为相应的数组。

public class CommaSeparatedToArrayBinder<T> : IModelBinder
    {
        public bool BindModel(HttpActionContext actionContext, ModelBindingContext bindingContext)
        {
            Type type = typeof(T);
            if (type.IsPrimitive || type == typeof(Decimal) || type == typeof(String) || type == typeof(float))
            {
                ValueProviderResult val = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);
                if (val == null) return false;

                string key = val.RawValue as string;
                if (key == null) { bindingContext.ModelState.AddModelError(bindingContext.ModelName, "Wrong value type"); return false; }

                string[] values = key.Split(',');
                IEnumerable<T> result = this.ConvertToDesiredList(values).ToArray();
                bindingContext.Model = result;
                return true;
            }

            bindingContext.ModelState.AddModelError(bindingContext.ModelName, "Only primitive, decimal, string and float data types are allowed...");
            return false;
        }

        private IEnumerable<T> ConvertToDesiredArray(string[] values)
        {
            foreach (string value in values)
            {
                var val = (T)Convert.ChangeType(value, typeof(T));
                yield return val;
            }
        }
    }

以及如何在Controller中使用:

 public IHttpActionResult Get([ModelBinder(BinderType = typeof(CommaSeparatedToArrayBinder<int>))] int[] ids)
        {
            return Ok(ids);
        }

你可以尝试这段代码来获取逗号分隔的值/一个值数组来从webAPI返回JSON

 public class CategoryController : ApiController
 {
     public List<Category> Get(String categoryIDs)
     {
         List<Category> categoryRepo = new List<Category>();

         String[] idRepo = categoryIDs.Split(',');

         foreach (var id in idRepo)
         {
             categoryRepo.Add(new Category()
             {
                 CategoryID = id,
                 CategoryName = String.Format("Category_{0}", id)
             });
         }
         return categoryRepo;
     }
 }

 public class Category
 {
     public String CategoryID { get; set; }
     public String CategoryName { get; set; }
 } 

输出:

[
{"CategoryID":"4","CategoryName":"Category_4"}, 
{"CategoryID":"5","CategoryName":"Category_5"}, 
{"CategoryID":"3","CategoryName":"Category_3"} 
]

我的解决方案是创建一个属性来验证字符串，它做了一堆额外的公共功能，包括regex验证，你可以使用它来检查数字，然后我根据需要转换为整数…

你可以这样使用:

public class MustBeListAndContainAttribute : ValidationAttribute
{
    private Regex regex = null;
    public bool RemoveDuplicates { get; }
    public string Separator { get; }
    public int MinimumItems { get; }
    public int MaximumItems { get; }

    public MustBeListAndContainAttribute(string regexEachItem,
        int minimumItems = 1,
        int maximumItems = 0,
        string separator = ",",
        bool removeDuplicates = false) : base()
    {
        this.MinimumItems = minimumItems;
        this.MaximumItems = maximumItems;
        this.Separator = separator;
        this.RemoveDuplicates = removeDuplicates;

        if (!string.IsNullOrEmpty(regexEachItem))
            regex = new Regex(regexEachItem, RegexOptions.Compiled | RegexOptions.Singleline | RegexOptions.IgnoreCase);
    }

    protected override ValidationResult IsValid(object value, ValidationContext validationContext)
    {
        var listOfdValues = (value as List<string>)?[0];

        if (string.IsNullOrWhiteSpace(listOfdValues))
        {
            if (MinimumItems > 0)
                return new ValidationResult(this.ErrorMessage);
            else
                return null;
        };

        var list = new List<string>();

        list.AddRange(listOfdValues.Split(new[] { Separator }, System.StringSplitOptions.RemoveEmptyEntries));

        if (RemoveDuplicates) list = list.Distinct().ToList();

        var prop = validationContext.ObjectType.GetProperty(validationContext.MemberName);
        prop.SetValue(validationContext.ObjectInstance, list);
        value = list;

        if (regex != null)
            if (list.Any(c => string.IsNullOrWhiteSpace(c) || !regex.IsMatch(c)))
                return new ValidationResult(this.ErrorMessage);

        return null;
    }
}

我最初使用@Mrchief这个解决方案很多年了(它工作得很好)。但是当我将Swagger添加到我的API文档项目时，我的终点并没有显示出来。

这花了我一段时间，但这是我想到的。它与Swagger一起工作，你的API方法签名看起来更干净:

最后你可以做到:

    // GET: /api/values/1,2,3,4 

    [Route("api/values/{ids}")]
    public IHttpActionResult GetIds(int[] ids)
    {
        return Ok(ids);
    }

WebApiConfig.cs

public static class WebApiConfig
{
    public static void Register(HttpConfiguration config)
    {
        // Allow WebApi to Use a Custom Parameter Binding
        config.ParameterBindingRules.Add(descriptor => descriptor.ParameterType == typeof(int[]) && descriptor.ActionDescriptor.SupportedHttpMethods.Contains(HttpMethod.Get)
                                                           ? new CommaDelimitedArrayParameterBinder(descriptor)
                                                           : null);

        // Allow ApiExplorer to understand this type (Swagger uses ApiExplorer under the hood)
        TypeDescriptor.AddAttributes(typeof(int[]), new TypeConverterAttribute(typeof(StringToIntArrayConverter)));

        // Any existing Code ..

    }
}

创建一个新类:CommaDelimitedArrayParameterBinder.cs

public class CommaDelimitedArrayParameterBinder : HttpParameterBinding, IValueProviderParameterBinding
{
    public CommaDelimitedArrayParameterBinder(HttpParameterDescriptor desc)
        : base(desc)
    {
    }

    /// <summary>
    /// Handles Binding (Converts a comma delimited string into an array of integers)
    /// </summary>
    public override Task ExecuteBindingAsync(ModelMetadataProvider metadataProvider,
                                             HttpActionContext actionContext,
                                             CancellationToken cancellationToken)
    {
        var queryString = actionContext.ControllerContext.RouteData.Values[Descriptor.ParameterName] as string;

        var ints = queryString?.Split(',').Select(int.Parse).ToArray();

        SetValue(actionContext, ints);

        return Task.CompletedTask;
    }

    public IEnumerable<ValueProviderFactory> ValueProviderFactories { get; } = new[] { new QueryStringValueProviderFactory() };
}

创建一个新类:StringToIntArrayConverter.cs

public class StringToIntArrayConverter : TypeConverter
{
    public override bool CanConvertFrom(ITypeDescriptorContext context, Type sourceType)
    {
        return sourceType == typeof(string) || base.CanConvertFrom(context, sourceType);
    }
}

注:

https://stackoverflow.com/a/47123965/862011为我指明了正确的方向 Swagger只是在使用[Route]属性时未能选择我的逗号分隔的端点

你只需要在参数前添加[FromUri]，看起来像:

GetCategories([FromUri] int[] categoryIds)

并发送请求:

/Categories?categoryids=1&categoryids=2&categoryids=3 

我最近遇到了这个需求，我决定实现一个ActionFilter来处理这个问题。

public class ArrayInputAttribute : ActionFilterAttribute
{
    private readonly string _parameterName;

    public ArrayInputAttribute(string parameterName)
    {
        _parameterName = parameterName;
        Separator = ',';
    }

    public override void OnActionExecuting(HttpActionContext actionContext)
    {
        if (actionContext.ActionArguments.ContainsKey(_parameterName))
        {
            string parameters = string.Empty;
            if (actionContext.ControllerContext.RouteData.Values.ContainsKey(_parameterName))
                parameters = (string) actionContext.ControllerContext.RouteData.Values[_parameterName];
            else if (actionContext.ControllerContext.Request.RequestUri.ParseQueryString()[_parameterName] != null)
                parameters = actionContext.ControllerContext.Request.RequestUri.ParseQueryString()[_parameterName];

            actionContext.ActionArguments[_parameterName] = parameters.Split(Separator).Select(int.Parse).ToArray();
        }
    }

    public char Separator { get; set; }
}

我像这样应用它(注意，我使用'id'，而不是'ids'，因为这是如何在我的路由中指定的):

[ArrayInput("id", Separator = ';')]
public IEnumerable<Measure> Get(int[] id)
{
    return id.Select(i => GetData(i));
}

public url是:

/api/Data/1;2;3;4

您可能必须对其进行重构以满足您的特定需求。