你只需要在参数前添加[FromUri]，看起来像:

GetCategories([FromUri] int[] categoryIds)

并发送请求:

/Categories?categoryids=1&categoryids=2&categoryids=3 

public class ArrayInputAttribute : ActionFilterAttribute
{
    private readonly string[] _ParameterNames;
    /// <summary>
    /// 
    /// </summary>
    public string Separator { get; set; }
    /// <summary>
    /// cons
    /// </summary>
    /// <param name="parameterName"></param>
    public ArrayInputAttribute(params string[] parameterName)
    {
        _ParameterNames = parameterName;
        Separator = ",";
    }

    /// <summary>
    /// 
    /// </summary>
    public void ProcessArrayInput(HttpActionContext actionContext, string parameterName)
    {
        if (actionContext.ActionArguments.ContainsKey(parameterName))
        {
            var parameterDescriptor = actionContext.ActionDescriptor.GetParameters().FirstOrDefault(p => p.ParameterName == parameterName);
            if (parameterDescriptor != null && parameterDescriptor.ParameterType.IsArray)
            {
                var type = parameterDescriptor.ParameterType.GetElementType();
                var parameters = String.Empty;
                if (actionContext.ControllerContext.RouteData.Values.ContainsKey(parameterName))
                {
                    parameters = (string)actionContext.ControllerContext.RouteData.Values[parameterName];
                }
                else
                {
                    var queryString = actionContext.ControllerContext.Request.RequestUri.ParseQueryString();
                    if (queryString[parameterName] != null)
                    {
                        parameters = queryString[parameterName];
                    }
                }

                var values = parameters.Split(new[] { Separator }, StringSplitOptions.RemoveEmptyEntries)
                    .Select(TypeDescriptor.GetConverter(type).ConvertFromString).ToArray();
                var typedValues = Array.CreateInstance(type, values.Length);
                values.CopyTo(typedValues, 0);
                actionContext.ActionArguments[parameterName] = typedValues;
            }
        }
    }

    public override void OnActionExecuting(HttpActionContext actionContext)
    {
        _ParameterNames.ForEach(parameterName => ProcessArrayInput(actionContext, parameterName));
    }
}

用法:

    [HttpDelete]
    [ArrayInput("tagIDs")]
    [Route("api/v1/files/{fileID}/tags/{tagIDs}")]
    public HttpResponseMessage RemoveFileTags(Guid fileID, Guid[] tagIDs)
    {
        _FileRepository.RemoveFileTags(fileID, tagIDs);
        return Request.CreateResponse(HttpStatusCode.OK);
    }

请求uri

http://localhost/api/v1/files/2a9937c7-8201-59b7-bc8d-11a9178895d0/tags/BBA5CD5D-F07D-47A9-8DEE-D19F5FA65F63,BBA5CD5D-F07D-47A9-8DEE-D19F5FA65F63

如果你想列出/数组的整数，最简单的方法是接受逗号(，)分隔的字符串列表，并将其转换为整数列表。不要忘记提到[FromUri]属性。你的url看起来像:

... ?ID = 71&accountID = 1,2,3,289,56

public HttpResponseMessage test([FromUri]int ID, [FromUri]string accountID)
{
    List<int> accountIdList = new List<int>();
    string[] arrAccountId = accountId.Split(new char[] { ',' });
    for (var i = 0; i < arrAccountId.Length; i++)
    {
        try
        {
           accountIdList.Add(Int32.Parse(arrAccountId[i]));
        }
        catch (Exception)
        {
        }
    }
}

除了使用自定义ModelBinder，还可以使用带有TypeConverter的自定义类型。

[TypeConverter(typeof(StrListConverter))]
public class StrList : List<string>
{
    public StrList(IEnumerable<string> collection) : base(collection) {}
}

public class StrListConverter : TypeConverter
{
    public override bool CanConvertFrom(ITypeDescriptorContext context, Type sourceType)
    {
        return sourceType == typeof(string) || base.CanConvertFrom(context, sourceType);
    }

    public override object ConvertFrom(ITypeDescriptorContext context, CultureInfo culture, object value)
    {
        if (value == null)
            return null;

        if (value is string s)
        {
            if (string.IsNullOrEmpty(s))
                return null;
            return new StrList(s.Split(','));
        }
        return base.ConvertFrom(context, culture, value);
    }
}

它的优点是使Web API方法的参数非常简单。你甚至不需要指定[FromUri]。

public IEnumerable<Category> GetCategories(StrList categoryIds) {
  // code to retrieve categories from database
}

这个例子是一个字符串列表，但你可以使用categoryIds.Select(int.Parse)或简单地编写一个IntList代替。

所有其他解决方案都需要大量的工作。我试图在HttpGet方法参数中使用IEnumerable<long>或long[]，但我认为没有必要做所有的工作，只是为了使处理程序方法参数的签名long[]。我最终只是把它变成字符串，然后在处理程序中把它分开。我只说了一句。

public async Task<IActionResult> SomeHandler(string idsString)
{
    var ids = idsString.Split(',').Select(x => long.Parse(x));

现在你可以传递这些数字

.../SomeHandler?idsString=123,456,789,012

将方法类型设置为[HttpPost]，创建一个有一个int[]参数的模型，并使用json post:

/* Model */
public class CategoryRequestModel 
{
    public int[] Categories { get; set; }
}

/* WebApi */
[HttpPost]
public HttpResponseMessage GetCategories(CategoryRequestModel model)
{
    HttpResponseMessage resp = null;

    try
    {
        var categories = //your code to get categories

        resp = Request.CreateResponse(HttpStatusCode.OK, categories);

    }
    catch(Exception ex)
    {
        resp = Request.CreateErrorResponse(HttpStatusCode.InternalServerError, ex);
    }

    return resp;
}

/* jQuery */
var ajaxSettings = {
    type: 'POST',
    url: '/Categories',
    data: JSON.serialize({Categories: [1,2,3,4]}),
    contentType: 'application/json',
    success: function(data, textStatus, jqXHR)
    {
        //get categories from data
    }
};

$.ajax(ajaxSettings);