我认为所选择的答案并没有提供一个令人满意的结果。我写了自己的函数，它有两个字符串;全文和要加粗的文本部分。

它返回一个SpannableStringBuilder，带有从'text'中粗体的'textToBold'。

我发现使子字符串加粗而不用标签包装的能力很有用。

    /**
     * Makes a substring of a string bold.
     * @param text          Full text
     * @param textToBold    Text you want to make bold
     * @return              String with bold substring
     */

    public static SpannableStringBuilder makeSectionOfTextBold(String text, String textToBold){

        SpannableStringBuilder builder=new SpannableStringBuilder();

        if(textToBold.length() > 0 && !textToBold.trim().equals("")){

            //for counting start/end indexes
            String testText = text.toLowerCase(Locale.US);
            String testTextToBold = textToBold.toLowerCase(Locale.US);
            int startingIndex = testText.indexOf(testTextToBold);
            int endingIndex = startingIndex + testTextToBold.length();
            //for counting start/end indexes

            if(startingIndex < 0 || endingIndex <0){
                return builder.append(text);
            }
            else if(startingIndex >= 0 && endingIndex >=0){

                builder.append(text);
                builder.setSpan(new StyleSpan(Typeface.BOLD), startingIndex, endingIndex, 0);
            }
        }else{
            return builder.append(text);
        }

        return builder;
  }

我认为所选择的答案并没有提供一个令人满意的结果。我写了自己的函数，它有两个字符串;全文和要加粗的文本部分。

它返回一个SpannableStringBuilder，带有从'text'中粗体的'textToBold'。

我发现使子字符串加粗而不用标签包装的能力很有用。

    /**
     * Makes a substring of a string bold.
     * @param text          Full text
     * @param textToBold    Text you want to make bold
     * @return              String with bold substring
     */

    public static SpannableStringBuilder makeSectionOfTextBold(String text, String textToBold){

        SpannableStringBuilder builder=new SpannableStringBuilder();

        if(textToBold.length() > 0 && !textToBold.trim().equals("")){

            //for counting start/end indexes
            String testText = text.toLowerCase(Locale.US);
            String testTextToBold = textToBold.toLowerCase(Locale.US);
            int startingIndex = testText.indexOf(testTextToBold);
            int endingIndex = startingIndex + testTextToBold.length();
            //for counting start/end indexes

            if(startingIndex < 0 || endingIndex <0){
                return builder.append(text);
            }
            else if(startingIndex >= 0 && endingIndex >=0){

                builder.append(text);
                builder.setSpan(new StyleSpan(Typeface.BOLD), startingIndex, endingIndex, 0);
            }
        }else{
            return builder.append(text);
        }

        return builder;
  }

字符串资源

<resources>
   <string name="your_string_resource_name">This is normal text<![CDATA[<b> but this is bold </b>]]> and <![CDATA[<u> but this is underline text</u>]]></string>
</resources> 

您的Java类

yourtextView.setText(getString(R.string.your_string_resource_name));

这不是最简单的解决方案吗?

<string name="string">Please provide your <b>Name</b> properly</string>

只要使用你想要的字符串:)

结果如下所示:

请填写您的姓名

当在list/recycler中搜索char时，使字符串的第一个char可扩展

拉维和阿杰

以前突出显示像这样，但我想像下面

ravi和ajay OR ravi和ajay

为此，我搜索单词长度，如果它等于1，我将主字符串分离成单词并计算单词开始位置，然后我搜索单词以char开头。

 public static SpannableString colorString(int color, String text, String... wordsToColor) {
    SpannableString coloredString = new SpannableString(text);

    for (String word : wordsToColor) {

        Log.e("tokentoken", "-wrd len-" + word.length());
        if (word.length() !=1) {
            int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
            int endColorIndex = startColorIndex + word.length();
            try {
                coloredString.setSpan(new ForegroundColorSpan(color), startColorIndex, endColorIndex,
                        Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

            } catch (Exception e) {
                e.getMessage();
            }
        } else {
            int start = 0;

            for (String token : text.split("[\u00A0 \n]")) {
                if (token.length() > 0) {
                    start = text.indexOf(token, start);
                   // Log.e("tokentoken", "-token-" + token + "   --start--" + start);
                    char x = token.toLowerCase().charAt(0);
                    char w = word.toLowerCase().charAt(0);
                   // Log.e("tokentoken", "-w-" + w + "   --x--" + x);

                    if (x == w) {
                        // int startColorIndex = text.toLowerCase().indexOf(word.toLowerCase());
                        int endColorIndex = start + word.length();
                        try {
                            coloredString.setSpan(new ForegroundColorSpan(color), start, endColorIndex,
                                    Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

                        } catch (Exception e) {
                            e.getMessage();
                        }
                    }
                }
            }

        }

    }

    return coloredString;
}

下面是我如何使用正则表达式和Kotlin来做到这一点

val BOLD_SPAN = StyleSpan(Typeface.BOLD)

    fun TextView.boldMatches(regexString: String) {
        this.applyStyleSpanToMatches(regexString, BOLD_SPAN)
    }
    

fun TextView.applyStyleSpanToMatches(regexString: String, span: StyleSpan){
        this.text = this.text.toString().applyStyleSpanToMatches(regexString, span)
        }

        fun String.applyStyleSpanToMatches(regexString: String, span: StyleSpan): Spannable {
            val result = SpannableString.valueOf(this)
            if(regexString.isEmpty()) return result
            val pattern = try{
                Pattern.compile(regexString)
            } catch (e: PatternSyntaxException){
                return result
            }
            val matcher = pattern.matcher(result)
            while (matcher.find()) {
                val start = matcher.start()
                val end = matcher.end()
                result.setSpan(span, start, end, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE)
            }
            return result
        }

使用问句 它可以这样应用:

txtResult.boldMatches(id)