我试图创建一个计算器,但我不能让它工作,因为我不知道如何获得用户输入。
如何在Java中获得用户输入?
我试图创建一个计算器,但我不能让它工作,因为我不知道如何获得用户输入。
如何在Java中获得用户输入?
当前回答
下面是使用java.util.Scanner的问题中的程序:
import java.util.Scanner;
public class Example {
public static void main(String[] args) {
int input = 0;
System.out.println("The super insano calculator");
System.out.println("enter the corrosponding number:");
Scanner reader3 = new Scanner(System.in);
System.out.println(
"1. Add | 2. Subtract | 3. Divide | 4. Multiply");
input = reader3.nextInt();
int a = 0, b = 0;
Scanner reader = new Scanner(System.in);
System.out.println("Enter the first number");
// get user input for a
a = reader.nextInt();
Scanner reader1 = new Scanner(System.in);
System.out.println("Enter the scend number");
// get user input for b
b = reader1.nextInt();
switch (input){
case 1: System.out.println(a + " + " + b + " = " + add(a, b));
break;
case 2: System.out.println(a + " - " + b + " = " + subtract(a, b));
break;
case 3: System.out.println(a + " / " + b + " = " + divide(a, b));
break;
case 4: System.out.println(a + " * " + b + " = " + multiply(a, b));
break;
default: System.out.println("your input is invalid!");
break;
}
}
static int add(int lhs, int rhs) { return lhs + rhs; }
static int subtract(int lhs, int rhs) { return lhs - rhs; }
static int divide(int lhs, int rhs) { return lhs / rhs; }
static int multiply(int lhs, int rhs) { return lhs * rhs; }
}
其他回答
您可以使用Scanner获取用户输入。您可以使用正确的方法对不同的数据类型使用正确的输入验证,例如对String使用next(),对Integer使用nextInt()。
import java.util.Scanner;
Scanner scanner = new Scanner(System.in);
//reads the input until it reaches the space
System.out.println("Enter a string: ");
String str = scanner.next();
System.out.println("str = " + str);
//reads until the end of line
String aLine = scanner.nextLine();
//reads the integer
System.out.println("Enter an integer num: ");
int num = scanner.nextInt();
System.out.println("num = " + num);
//reads the double value
System.out.println("Enter a double: ");
double aDouble = scanner.nextDouble();
System.out.println("double = " + aDouble);
//reads the float value, long value, boolean value, byte and short
double aFloat = scanner.nextFloat();
long aLong = scanner.nextLong();
boolean aBoolean = scanner.nextBoolean();
byte aByte = scanner.nextByte();
short aShort = scanner.nextShort();
scanner.close();
要读取一行或字符串,你可以使用BufferedReader对象和InputStreamReader对象结合使用,如下所示:
BufferedReader bufferReader = new BufferedReader(new InputStreamReader(System.in));
String inputLine = bufferReader.readLine();
您可以使用BufferedReader获取用户输入。
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String accStr;
System.out.println("Enter your Account number: ");
accStr = br.readLine();
它将在accStr中存储一个String值,因此您必须使用Integer.parseInt将其解析为int。
int accInt = Integer.parseInt(accStr);
你可以做一个简单的程序,要求用户的名字和打印任何回复使用输入。
或者让用户输入两个数字,你可以加、乘、减或除这些数字,并打印出用户输入的答案,就像计算器的行为一样。
你需要Scanner类。你必须导入java。util。scanner;在你需要使用的代码中
Scanner input = new Scanner(System.in);
Input是一个变量名。
Scanner input = new Scanner(System.in);
System.out.println("Please enter your name : ");
s = input.next(); // getting a String value
System.out.println("Please enter your age : ");
i = input.nextInt(); // getting an integer
System.out.println("Please enter your salary : ");
d = input.nextDouble(); // getting a double
看看这有什么不同:input.next();, i = input.nextInt();, d = input.nextDouble();
根据String类型,int和double类型以同样的方式变化。不要忘记代码顶部的import语句。
请参见博客文章“扫描器类和获取用户输入”。
import java.util.Scanner;
public class userinput {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Name : ");
String name = input.next();
System.out.print("Last Name : ");
String lname = input.next();
System.out.print("Age : ");
byte age = input.nextByte();
System.out.println(" " );
System.out.println(" " );
System.out.println("Firt Name: " + name);
System.out.println("Last Name: " + lname);
System.out.println(" Age: " + age);
}
}