当所选项目发生变化时,如何为微调器设置事件侦听器?

基本上我想做的是类似这样的事情:

spinner1.onSelectionChange = handleSelectionChange;

void handleSelectionChange(Object sender){
    //handle event
}

当前回答

找到你的微调器名称和id,然后实现这个方法。

spinnername.setOnItemSelectedListener(new OnItemSelectedListener() {

    @Override
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        // your code here
    }

    @Override
    public void onNothingSelected(AdapterView<?> parentView) {
        // your code here
    }
});

其他回答

如果你想要一个true onChangedListener()。将初始值存储在处理程序中,并检查它是否已更改。它很简单,不需要全局变量。如果页面上有多个转轮,则有效。

String initialValue = // get from Database or your object
mySpinner.setOnItemSelectedListener(new SpinnerSelectedListener(initialValue));

...

protected class SpinnerSelectedListener implements AdapterView.OnItemSelectedListener {

        private SpinnerSelectedListener() {
            super();
        }

        public SpinnerSelectedListener(String initialValue) {
            this();
            this.initialValue = initialValue;
        }

        private String initialValue;

        // getter and setter removed.  

        @Override
        public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
            final String newValue = (String) spinHeight.getItemAtPosition(position);
            if (newValue.equals(initialValue) == false) {
               // Add your code here.  The spinner has changed value. 

               // Maybe useful.   
               // initialValue = newValue;
            }

        }

        @Override
        public void onNothingSelected(AdapterView<?> parent) {
               // Maybe useful.   
               // initialValue = null; 
        }
    }

对象是你的朋友,使用它们。

这是可行的 初始化旋转器和findviewbyid并使用它将工作

    Spinner schemeStatusSpinner;

  schemeStatusSpinner = (Spinner) dialog.findViewById(R.id.spinner);

schemeStatusSpinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
            // your code here
            if(schemeStatusSpinner.getSelectedItemId()==4){
                reasonll.setVisibility(View.VISIBLE);
            }
            else {
                reasonll.setVisibility(View.GONE);
            }
        }

        @Override
        public void onNothingSelected(AdapterView<?> parentView) {
            // your code here
        }

    });

spinner-widget的文档说

旋转器不支持项目单击事件。

您应该使用setOnItemSelectedListener来处理您的问题。

spinner.setOnItemSelectedListener(
            new AdapterView.OnItemSelectedListener() {

                @Override
                public void onItemSelected(AdapterView<?> arg0, View arg1,
                        int arg2, long arg3) {

                    // TODO Auto-generated method stub
                }

                @Override
                public void onNothingSelected(AdapterView<?> arg0) {
                    // TODO Auto-generated method stub

                }
                //add some code here
            }
        );

默认情况下,您将获得旋转器数组的第一项

value = spinner.getSelectedItem().toString();

无论何时你在旋转器中选择值,它都会给你选择的值

如果你想要选定项目的位置,然后这样做

pos = spinner.getSelectedItemPosition();

以上两个答案均为不应用监听器的情况