在Java中是否有任何方法可以生成一个字符串的MD5哈希?


当前回答

我的回答不是很直白:

private String md5(String s) {
    try {
        MessageDigest m = MessageDigest.getInstance("MD5");
        m.update(s.getBytes(), 0, s.length());
        BigInteger i = new BigInteger(1,m.digest());
        return String.format("%1$032x", i);         
    } catch (NoSuchAlgorithmException e) {
        e.printStackTrace();
    }
    return null;
}

其他回答

你可以试着跟着走。查看详细信息和下载代码:http://jkssweetlife.com/java-hashgenerator-md5-sha-1/

import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;

public class MD5Example {

public static void main(String[] args) throws Exception {

    final String inputString = "Hello MD5";

    System.out.println("MD5 hex for '" + inputString + "' :");
    System.out.println(getMD5Hex(inputString));
}

public static String getMD5Hex(final String inputString) throws NoSuchAlgorithmException {

    MessageDigest md = MessageDigest.getInstance("MD5");
    md.update(inputString.getBytes());

    byte[] digest = md.digest();

    return convertByteToHex(digest);
}

private static String convertByteToHex(byte[] byteData) {

    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < byteData.length; i++) {
        sb.append(Integer.toString((byteData[i] & 0xff) + 0x100, 16).substring(1));
    }

    return sb.toString();
}
}

我已经使用php,如下所示

<?php
$goodtext = "Not found";
// If there is no parameter, this code is all skipped
if ( isset($_GET['md5']) ) {
    $time_pre = microtime(true);
    $md5 = $_GET['md5'];
    // This is our alphabet
    $txt = "0123456789";
    $show = 15;
    // Outer loop go go through the alphabet for the
    // first position in our "possible" pre-hash
    // text
    for($i=0; $i<strlen($txt); $i++ ) {
        $ch1 = $txt[$i];   // The first of two characters
        // Our inner loop Note the use of new variables
        // $j and $ch2 
        for($j=0; $j<strlen($txt); $j++ ) {
            $ch2 = $txt[$j];  // Our second character
            for($k=0; $k<strlen($txt); $k++ ) {
                $ch3 = $txt[$k];
                for($l=0; $l<strlen($txt); $l++){
                    $ch4 = $txt[$l];
                    // Concatenate the two characters together to 
                    // form the "possible" pre-hash text
                    $try = $ch1.$ch2.$ch3.$ch4;
                    // Run the hash and then check to see if we match
                    $check = hash('md5', $try);
                    if ( $check == $md5 ) {
                        $goodtext = $try;
                        break;   // Exit the inner loop
                    }
                    // Debug output until $show hits 0
                    if ( $show > 0 ) {
                        print "$check $try\n";
                        $show = $show - 1;
                    }
                    if($goodtext == $try){
                        break;
                    }
                }
                if($goodtext == $try){
                    break;
                }
            }
            if($goodtext == $try) {
                break;  
            }
        }
        if($goodtext == $try){
            break;
        }
    }
    // Compute ellapsed time
    $time_post = microtime(true);
    print "Ellapsed time: ";
    print $time_post-$time_pre;
    print "\n";
}
?>

你可以参考这个资料来源

这就是我来这里的目的-一个方便的scala函数,返回MD5哈希字符串:

def md5(text: String) : String = java.security.MessageDigest.getInstance("MD5").digest(text.getBytes()).map(0xFF & _).map { "%02x".format(_) }.foldLeft(""){_ + _}

我发现这是最清晰和简洁的方法:

MessageDigest md5 = MessageDigest.getInstance("MD5");
md5.update(StandardCharsets.UTF_8.encode(string));
return String.format("%032x", new BigInteger(1, md5.digest()));

Bombe的答案是正确的,但请注意,除非你绝对必须使用MD5(例如,为了互操作性而被迫使用),否则更好的选择是SHA1,因为MD5长期使用有缺点。

我应该补充一点,SHA1也有理论上的漏洞,但没有那么严重。目前的哈希技术水平是,有许多候选替换哈希函数,但还没有一个成为取代SHA1的标准最佳实践。因此,根据您的需要,建议您使您的哈希算法可配置,以便将来可以替换它。