在Java中是否有任何方法可以生成一个字符串的MD5哈希?


当前回答

我已经使用php,如下所示

<?php
$goodtext = "Not found";
// If there is no parameter, this code is all skipped
if ( isset($_GET['md5']) ) {
    $time_pre = microtime(true);
    $md5 = $_GET['md5'];
    // This is our alphabet
    $txt = "0123456789";
    $show = 15;
    // Outer loop go go through the alphabet for the
    // first position in our "possible" pre-hash
    // text
    for($i=0; $i<strlen($txt); $i++ ) {
        $ch1 = $txt[$i];   // The first of two characters
        // Our inner loop Note the use of new variables
        // $j and $ch2 
        for($j=0; $j<strlen($txt); $j++ ) {
            $ch2 = $txt[$j];  // Our second character
            for($k=0; $k<strlen($txt); $k++ ) {
                $ch3 = $txt[$k];
                for($l=0; $l<strlen($txt); $l++){
                    $ch4 = $txt[$l];
                    // Concatenate the two characters together to 
                    // form the "possible" pre-hash text
                    $try = $ch1.$ch2.$ch3.$ch4;
                    // Run the hash and then check to see if we match
                    $check = hash('md5', $try);
                    if ( $check == $md5 ) {
                        $goodtext = $try;
                        break;   // Exit the inner loop
                    }
                    // Debug output until $show hits 0
                    if ( $show > 0 ) {
                        print "$check $try\n";
                        $show = $show - 1;
                    }
                    if($goodtext == $try){
                        break;
                    }
                }
                if($goodtext == $try){
                    break;
                }
            }
            if($goodtext == $try) {
                break;  
            }
        }
        if($goodtext == $try){
            break;
        }
    }
    // Compute ellapsed time
    $time_post = microtime(true);
    print "Ellapsed time: ";
    print $time_post-$time_pre;
    print "\n";
}
?>

你可以参考这个资料来源

其他回答

private String hashuj(String dane) throws ServletException{
    try {
        MessageDigest m = MessageDigest.getInstance("MD5");
        byte[] bufor = dane.getBytes();
        m.update(bufor,0,bufor.length);
        BigInteger hash = new BigInteger(1,m.dige`enter code here`st());
        return String.format("%1$032X", hash);

    } catch (NoSuchAlgorithmException nsae) {
        throw new ServletException("Algorytm szyfrowania nie jest obsługiwany!");
    }
}

如果你真的想要返回一个字符串,而不是字节数组,你总是可以这样做:

String plaintext = "your text here";
MessageDigest m = MessageDigest.getInstance("MD5");
m.reset();
m.update(plaintext.getBytes());
byte[] digest = m.digest();
BigInteger bigInt = new BigInteger(1,digest);
String hashtext = bigInt.toString(16);
// Now we need to zero pad it if you actually want the full 32 chars.
while(hashtext.length() < 32 ){
  hashtext = "0"+hashtext;
}

这就是我来这里的目的-一个方便的scala函数,返回MD5哈希字符串:

def md5(text: String) : String = java.security.MessageDigest.getInstance("MD5").digest(text.getBytes()).map(0xFF & _).map { "%02x".format(_) }.foldLeft(""){_ + _}

你可以试试凯撒。

第一选择:

byte[] hash =
    new Hash(
        new ImmutableMessageDigest(
            MessageDigest.getInstance("MD5")
        ),
        new PlainText("String to hash...")
    ).asArray();

第二选择:

byte[] hash =
    new ImmutableMessageDigest(
        MessageDigest.getInstance("MD5")
    ).update(
        new PlainText("String to hash...")
    ).digest();

我的回答不是很直白:

private String md5(String s) {
    try {
        MessageDigest m = MessageDigest.getInstance("MD5");
        m.update(s.getBytes(), 0, s.length());
        BigInteger i = new BigInteger(1,m.digest());
        return String.format("%1$032x", i);         
    } catch (NoSuchAlgorithmException e) {
        e.printStackTrace();
    }
    return null;
}