当星期一为0，星期日为6时，使用date.weekday（）

or

date.isoweekday（），当周一是1，周日是7

当星期一为0，星期日为6时，使用date.weekday（）

or

date.isoweekday（），当周一是1，周日是7

要让星期天1点到星期六7点，这是解决问题的最简单方法：

datetime.date.today().toordinal()%7 + 1

所有这些：

import datetime

today = datetime.date.today()
sunday = today - datetime.timedelta(today.weekday()+1)

for i in range(7):
    tmp_date = sunday + datetime.timedelta(i)
    print tmp_date.toordinal()%7 + 1, '==', tmp_date.strftime('%A')

输出：

1 == Sunday
2 == Monday
3 == Tuesday
4 == Wednesday
5 == Thursday
6 == Friday
7 == Saturday

使用以下代码：

import pandas as pd
from datetime import datetime
print(pd.DatetimeIndex(df['give_date']).day)

一个简单、直接但尚未提及的选项：

import datetime
...
givenDateObj = datetime.date(2017, 10, 20)
weekday      = givenDateObj.isocalendar()[2] # 5
weeknumber   = givenDateObj.isocalendar()[1] # 42

import numpy as np

def date(df):
    df['weekday'] = df['date'].dt.day_name()

    conditions = [(df['weekday'] == 'Sunday'),
              (df['weekday'] == 'Monday'),
              (df['weekday'] == 'Tuesday'),
              (df['weekday'] == 'Wednesday'),
              (df['weekday'] == 'Thursday'),
              (df['weekday'] == 'Friday'),
              (df['weekday'] == 'Saturday')]

    choices = [0, 1, 2, 3, 4, 5, 6]

    df['week'] = np.select(conditions, choices)

    return df