我有一门课叫问题(复数)。在这个类中有一个名为Question(单数)的枚举,看起来像这样。

public enum Question
{
    Role = 2,
    ProjectFunding = 3,
    TotalEmployee = 4,
    NumberOfServers = 5,
    TopBusinessConcern = 6
}

在Questions类中,我有一个get(intfoo)函数,它为该foo返回Questions对象。有没有一种简单的方法可以从枚举中获取整数值,这样我就可以执行类似于Questions.get(Questions.Role)的操作?


当前回答

我提出了包含当前语言特性的扩展方法。通过使用dynamic,我不需要将其作为泛型方法并指定使调用更简单和一致的类型:

public static class EnumEx
{
    public static dynamic Value(this Enum e)
    {
        switch (e.GetTypeCode())
        {
            case TypeCode.Byte:
            {
                return (byte) (IConvertible) e;
            }

            case TypeCode.Int16:
            {
                return (short) (IConvertible) e;
            }

            case TypeCode.Int32:
            {
                return (int) (IConvertible) e;
            }

            case TypeCode.Int64:
            {
                return (long) (IConvertible) e;
            }

            case TypeCode.UInt16:
            {
                return (ushort) (IConvertible) e;
            }

            case TypeCode.UInt32:
            {
                return (uint) (IConvertible) e;
            }

            case TypeCode.UInt64:
            {
                return (ulong) (IConvertible) e;
            }

            case TypeCode.SByte:
            {
                return (sbyte) (IConvertible) e;
            }
        }

        return 0;
    }

其他回答

public enum Suit : int
{
    Spades = 0,
    Hearts = 1,
    Clubs = 2,
    Diamonds = 3
}

Console.WriteLine((int)(Suit)Enum.Parse(typeof(Suit), "Clubs"));

// From int
Console.WriteLine((Suit)1);

// From a number you can also
Console.WriteLine((Suit)Enum.ToObject(typeof(Suit), 1));

if (typeof(Suit).IsEnumDefined("Spades"))
{
    var res = (int)(Suit)Enum.Parse(typeof(Suit), "Spades");
    Console.Out.WriteLine("{0}", res);
}
Question question = Question.Role;
int value = (int) question;

将导致值==2。

只需转换枚举,例如。

int something = (int) Question.Role;

以上内容适用于您在野外看到的绝大多数枚举,因为枚举的默认基础类型是int。

然而,正如cecilphilip所指出的,遗尿症可能有不同的潜在类型。如果枚举声明为uint、long或ulong,则应将其强制转换为枚举的类型;例如,用于

enum StarsInMilkyWay:long {Sun = 1, V645Centauri = 2 .. Wolf424B = 2147483649};

你应该使用

long something = (long)StarsInMilkyWay.Wolf424B;

在一个相关的注释中,如果你想从System.Enum中获取int值,那么在这里给出e:

Enum e = Question.Role;

您可以使用:

int i = Convert.ToInt32(e);
int i = (int)(object)e;
int i = (int)Enum.Parse(e.GetType(), e.ToString());
int i = (int)Enum.ToObject(e.GetType(), e);

最后两个很难看。我更喜欢第一个。

最近,我不再在代码中使用枚举,而是使用带有受保护构造函数和预定义静态实例的类(感谢Roelof-C#确保有效枚举值-Futureproof方法)。

鉴于此,下面是我现在如何处理这个问题(包括隐式转换为int或从int转换)。

public class Question
{
    // Attributes
    protected int index;
    protected string name;
    // Go with a dictionary to enforce unique index
    //protected static readonly ICollection<Question> values = new Collection<Question>();
    protected static readonly IDictionary<int,Question> values = new Dictionary<int,Question>();

    // Define the "enum" values
    public static readonly Question Role = new Question(2,"Role");
    public static readonly Question ProjectFunding = new Question(3, "Project Funding");
    public static readonly Question TotalEmployee = new Question(4, "Total Employee");
    public static readonly Question NumberOfServers = new Question(5, "Number of Servers");
    public static readonly Question TopBusinessConcern = new Question(6, "Top Business Concern");

    // Constructors
    protected Question(int index, string name)
    {
        this.index = index;
        this.name = name;
        values.Add(index, this);
    }

    // Easy int conversion
    public static implicit operator int(Question question) =>
        question.index; //nb: if question is null this will return a null pointer exception

    public static implicit operator Question(int index) =>        
        values.TryGetValue(index, out var question) ? question : null;

    // Easy string conversion (also update ToString for the same effect)
    public override string ToString() =>
        this.name;

    public static implicit operator string(Question question) =>
        question?.ToString();

    public static implicit operator Question(string name) =>
        name == null ? null : values.Values.FirstOrDefault(item => name.Equals(item.name, StringComparison.CurrentCultureIgnoreCase));


    // If you specifically want a Get(int x) function (though not required given the implicit converstion)
    public Question Get(int foo) =>
        foo; //(implicit conversion will take care of the conversion for you)
}

这种方法的优点是你可以从枚举中得到所有的东西,但是你的代码现在更灵活了,所以如果你需要根据Question的值执行不同的操作,你可以将逻辑放入Question本身(即以首选的OO方式),而不是在代码中放入大量的case语句来处理每个场景。


注意:2018-04-27更新了答案,以利用C#6功能;即声明表达式和lambda表达式体定义。原始代码参见修订历史。这样做的好处是使定义不那么冗长;这是对这个答案方法的主要抱怨之一。