我想暂停shell脚本中的输入,并提示用户进行选择。标准的是、否或取消类型问题。如何在典型的bash提示符中完成此操作?


当前回答

您需要:

Bash内置命令(即便携式)检查TTY默认答案超时彩色问题

一小条

do_xxxx=y                      # In batch mode => Default is Yes
[[ -t 0 ]] &&                  # If TTY => Prompt the question
read -n 1 -p $'\e[1;32m
Do xxxx? (Y/n)\e[0m ' do_xxxx  # Store the answer in $do_xxxx
if [[ $do_xxxx =~ ^(y|Y|)$ ]]  # Do if 'y' or 'Y' or empty
then
    xxxx
fi

解释

[[-t 0]]&&read…=>如果TTY,调用命令读取read-n 1=>等待一个字符$'\e[1;32m…\e[0m'=>绿色打印(绿色很好,因为在白色/黑色背景上都可以阅读)[[$do_xxxx=~^(y|y|)$]]=>bash正则表达式

超时=>默认答案为否

do_xxxx=y
[[ -t 0 ]] && {                   # Timeout 5 seconds (read -t 5)
read -t 5 -n 1 -p $'\e[1;32m
Do xxxx? (Y/n)\e[0m ' do_xxxx ||  # read 'fails' on timeout
do_xxxx=n ; }                     # Timeout => answer No
if [[ $do_xxxx =~ ^(y|Y|)$ ]]
then
    xxxx
fi

其他回答

read -p "Are you alright? (y/n) " RESP
if [ "$RESP" = "y" ]; then
  echo "Glad to hear it"
else
  echo "You need more bash programming"
fi

可以在POSIX shell中处理区域设置感知的“是/否选项”;通过使用LC_MESSAGES语言环境类别的条目,witch提供了与输入匹配的现成RegEx模式,以及本地化Yes No的字符串。

#!/usr/bin/env sh

# Getting LC_MESSAGES values into variables
# shellcheck disable=SC2046 # Intended IFS splitting
IFS='
' set -- $(locale LC_MESSAGES)

yesexpr="$1"
noexpr="$2"
yesstr="$3"
nostr="$4"
messages_codeset="$5" # unused here, but kept as documentation

# Display Yes / No ? prompt into locale
echo "$yesstr / $nostr ?"

# Read answer
read -r yn

# Test answer
case "$yn" in
# match only work with the character class from the expression
  ${yesexpr##^}) echo "answer $yesstr" ;;
  ${noexpr##^}) echo "answer $nostr" ;;
esac

编辑:正如@Urhixidur在评论中提到的:

不幸的是,POSIX只指定了前两个(yeexpr和noexpr)。在Ubuntu 16上,yestr和nostr为空。

参见:https://www.ee.ryerson.ca/~courses/ele709/susv4/xrat/V_4_xbd_chap07.html#tag_21_07_03_06

LC_消息yestr和nostr语言环境关键字以及yesstr和nostr语言信息项以前用于匹配用户的肯定和否定响应。在POSIX.1-2008中,yeexpr、noexpr、yesexpr和noexpr扩展正则表达式已取代它们。应用程序应该使用通用的基于语言环境的消息传递工具来发出包含所需响应示例的提示消息。

或者使用Bash方式的区域设置:

#!/usr/bin/env bash

IFS=$'\n' read -r -d '' yesexpr noexpr _ < <(locale LC_MESSAGES)

printf -v yes_or_no_regex "(%s)|(%s)" "$yesexpr" "$noexpr"

printf -v prompt $"Please answer Yes (%s) or No (%s): " "$yesexpr" "$noexpr"

declare -- answer=;

until [[ "$answer" =~ $yes_or_no_regex ]]; do
  read -rp "$prompt" answer
done

if [[ -n "${BASH_REMATCH[1]}" ]]; then
  echo $"You answered: Yes"
else
  echo $"No, was your answer."
fi

使用语言环境提供的regexp来匹配答案。

要翻译剩余的消息,请使用bash--dump po string scriptname输出po字符串以进行本地化:

#: scriptname:8
msgid "Please answer Yes (%s) or No (%s): "
msgstr ""
#: scriptname:17
msgid "You answered: Yes"
msgstr ""
#: scriptname:19
msgid "No, was your answer."
msgstr ""

在我的情况下,我需要从下载的脚本中读取。,

curl -Ss https://example.com/installer.sh | sh

在这种情况下,read-ryn</dev/tty行允许它读取输入。

printf "These files will be uploaded. Is this ok? (y/N) "
read -r yn </dev/tty

if [ "$yn" = "y" ]; then
   
   # Yes
else
   
   # No
fi

针对其他人:

您不需要在BASH4中指定大小写,只需使用',,'使var小写即可。此外,我强烈不喜欢将代码放在读取块内,获取结果并在读取块IMO外处理它。还包括一个“q”表示退出IMO。最后,为什么键入“yes”只需使用-n1并按y。

示例:用户可以按y/n和q退出。

ans=''
while true; do
    read -p "So is MikeQ the greatest or what (y/n/q) ?" -n1 ans
    case ${ans,,} in
        y|n|q) break;;
        *) echo "Answer y for yes / n for no  or q for quit.";;
    esac
done

echo -e "\nAnswer = $ans"

if [[ "${ans,,}" == "q" ]] ; then
        echo "OK Quitting, we will assume that he is"
        exit 0
fi

if [[ "${ans,,}" == "y" ]] ; then
        echo "MikeQ is the greatest!!"
else
        echo "No? MikeQ is not the greatest?"
fi

检查此项

read -p "Continue? (y/n): " confirm && [[ $confirm == [yY] || $confirm == [yY][eE][sS] ]] || exit 1