你可以用两种方法去除

var output = from x in authorsList
             where x.firstname != "Bob"
             select x;

or

var authors = from x in authorsList
              where x.firstname == "Bob"
              select x;

var output = from x in authorsList
             where !authors.Contains(x) 
             select x;

我也有同样的问题，如果你想根据你的where条件简单输出，那么第一个解决方案更好。

LINQ起源于函数式编程，它强调对象的不可变性，因此它不提供内置的方式来就地更新原始列表。

关于不可变性的注意事项(来自另一个SO答案):

这是维基百科对不变性的定义。

在面向对象和函数式编程中，不可变对象是 创建后状态不可修改的对象。

为了保持代码流畅(如果代码优化不是关键)，你需要对列表做一些进一步的操作:

authorsList = authorsList.Where(x => x.FirstName != "Bob").<do_some_further_Linq>;

or

authorsList = authorsList.Where(x => !setToRemove.Contains(x)).<do_some_further_Linq>;

你可以用两种方法去除

var output = from x in authorsList
             where x.firstname != "Bob"
             select x;

or

var authors = from x in authorsList
              where x.firstname == "Bob"
              select x;

var output = from x in authorsList
             where !authors.Contains(x) 
             select x;

我也有同样的问题，如果你想根据你的where条件简单输出，那么第一个解决方案更好。

我认为你只需要将作者列表中的项目分配到一个新的列表中就可以了。

//assume oldAuthor is the old list
Author newAuthorList = (select x from oldAuthor where x.firstname!="Bob" select x).ToList();
oldAuthor = newAuthorList;
newAuthorList = null;

我想知道，RemoveAll和Except之间是否有任何区别，以及使用HashSet的优点，所以我已经做了快速性能检查:)

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;

namespace ListRemoveTest
{
    class Program
    {
        private static Random random = new Random( (int)DateTime.Now.Ticks );

        static void Main( string[] args )
        {
            Console.WriteLine( "Be patient, generating data..." );

            List<string> list = new List<string>();
            List<string> toRemove = new List<string>();
            for( int x=0; x < 1000000; x++ )
            {
                string randString = RandomString( random.Next( 100 ) );
                list.Add( randString );
                if( random.Next( 1000 ) == 0 )
                    toRemove.Insert( 0, randString );
            }

            List<string> l1 = new List<string>( list );
            List<string> l2 = new List<string>( list );
            List<string> l3 = new List<string>( list );
            List<string> l4 = new List<string>( list );

            Console.WriteLine( "Be patient, testing..." );

            Stopwatch sw1 = Stopwatch.StartNew();
            l1.RemoveAll( toRemove.Contains );
            sw1.Stop();

            Stopwatch sw2 = Stopwatch.StartNew();
            l2.RemoveAll( new HashSet<string>( toRemove ).Contains );
            sw2.Stop();

            Stopwatch sw3 = Stopwatch.StartNew();
            l3 = l3.Except( toRemove ).ToList();
            sw3.Stop();

            Stopwatch sw4 = Stopwatch.StartNew();
            l4 = l4.Except( new HashSet<string>( toRemove ) ).ToList();
            sw3.Stop();


            Console.WriteLine( "L1.Len = {0}, Time taken: {1}ms", l1.Count, sw1.Elapsed.TotalMilliseconds );
            Console.WriteLine( "L2.Len = {0}, Time taken: {1}ms", l1.Count, sw2.Elapsed.TotalMilliseconds );
            Console.WriteLine( "L3.Len = {0}, Time taken: {1}ms", l1.Count, sw3.Elapsed.TotalMilliseconds );
            Console.WriteLine( "L4.Len = {0}, Time taken: {1}ms", l1.Count, sw3.Elapsed.TotalMilliseconds );

            Console.ReadKey();
        }


        private static string RandomString( int size )
        {
            StringBuilder builder = new StringBuilder();
            char ch;
            for( int i = 0; i < size; i++ )
            {
                ch = Convert.ToChar( Convert.ToInt32( Math.Floor( 26 * random.NextDouble() + 65 ) ) );
                builder.Append( ch );
            }

            return builder.ToString();
        }
    }
}

结果如下:

Be patient, generating data...
Be patient, testing...
L1.Len = 985263, Time taken: 13411.8648ms
L2.Len = 985263, Time taken: 76.4042ms
L3.Len = 985263, Time taken: 340.6933ms
L4.Len = 985263, Time taken: 340.6933ms

如我们所见，这种情况下最好的选择是使用RemoveAll(HashSet)