如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
这里有三种方法:
Fake a real object: class convert { public $varible; public function __construct($array) { $this = $array; } public static function toObject($array) { $array = new convert($array); return $array; } } Convert the array into an object by casting it to an object: $array = array( // ... ); $object = (object) $array; Manually convert the array into an object: $object = object; foreach ($arr as $key => $value) { $object->{$key} = $value; }
其他回答
快速攻击:
// assuming $var is a multidimensional array
$obj = json_decode (json_encode ($var), FALSE);
不漂亮，但很好用。
你可以使用反射:
<?php
$array = ['name'=>'maria','age'=>33];
class Person {
public $name;
public $age;
public function __construct(string $name, string $age){
$this->name = $name;
$this->age = $age;
}
}
function arrayToObject(array $array, string $class_name){
$r = new ReflectionClass($class_name);
$object = $r->newInstanceWithoutConstructor();
$list = $r->getProperties();
foreach($list as $prop){
$prop->setAccessible(true);
if(isset($array[$prop->name]))
$prop->setValue($object, $array[$prop->name]);
}
return $object;
}
$pessoa1 = arrayToObject($array, 'Person');
var_dump($pessoa1);
一个衬套
$object= json_decode(json_encode($result_array, JSON_FORCE_OBJECT));
简单的方法是
$object = (object)$array;
但这不是你想要的。如果你想要对象，你想要实现一些东西，但这在这个问题中是缺失的。仅仅为了使用对象而使用对象是没有意义的。
它的方法很简单，这将为递归数组创建一个对象:
$object = json_decode(json_encode((object) $yourArray), FALSE);
