如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
这里有三种方法:
Fake a real object: class convert { public $varible; public function __construct($array) { $this = $array; } public static function toObject($array) { $array = new convert($array); return $array; } } Convert the array into an object by casting it to an object: $array = array( // ... ); $object = (object) $array; Manually convert the array into an object: $object = object; foreach ($arr as $key => $value) { $object->{$key} = $value; }
其他回答
这里有三种方法:
Fake a real object: class convert { public $varible; public function __construct($array) { $this = $array; } public static function toObject($array) { $array = new convert($array); return $array; } } Convert the array into an object by casting it to an object: $array = array( // ... ); $object = (object) $array; Manually convert the array into an object: $object = object; foreach ($arr as $key => $value) { $object->{$key} = $value; }
我肯定会用这样一种干净的方式:
<?php
class Person {
private $name;
private $age;
private $sexe;
function __construct ($payload)
{
if (is_array($payload))
$this->from_array($payload);
}
public function from_array($array)
{
foreach(get_object_vars($this) as $attrName => $attrValue)
$this->{$attrName} = $array[$attrName];
}
public function say_hi ()
{
print "hi my name is {$this->name}";
}
}
print_r($_POST);
$mike = new Person($_POST);
$mike->say_hi();
?>
如果你提交:
你会得到这个:
我发现这更符合逻辑的比较以上的答案从对象应该用于他们的目的(封装可爱的小对象)。
此外,使用get_object_vars确保在被操纵的对象中没有创建额外的属性(您不希望汽车有姓,也不希望人有4个轮子)。
在最简单的情况下,将数组“强制转换”为对象可能就足够了:
$object = (object) $array;
另一个选择是实例化一个标准类作为一个变量,循环遍历你的数组,同时重新分配值:
$object = new stdClass();
foreach ($array as $key => $value)
{
$object->$key = $value;
}
正如Edson Medina指出的,一个真正干净的解决方案是使用内置的json_函数:
$object = json_decode(json_encode($array), FALSE);
这也(递归地)将所有子数组转换为对象,这可能是你想要的,也可能不是。不幸的是,它比循环方法有2-3倍的性能损失。
警告!(感谢Ultra的评论):
不同环境上的json_decode以不同的方式转换UTF-8数据。我最终在当地得到了“240.00”的值,在生产中得到了“240”——巨大的灾难。此外,如果转换失败,字符串get返回为NULL
您可以简单地使用类型强制转换将数组转换为对象。
// *convert array to object* Array([id]=> 321313[username]=>shahbaz)
$object = (object) $array_name;
//now it is converted to object and you can access it.
echo $object->username;
容易:
$object = json_decode(json_encode($array));
例子:
$array = array(
'key' => array(
'k' => 'value',
),
'group' => array('a', 'b', 'c')
);
$object = json_decode(json_encode($array));
那么,以下是正确的:
$object->key->k === 'value';
$object->group === array('a', 'b', 'c')