如何将这样的数组转换为对象?

[128] => Array
    (
        [status] => "Figure A.
 Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
    )

[129] => Array
    (
        [status] => "The other day at work, I had some spare time"
    )

当前回答

我使用以下代码将Yaml文件关联数组解析为对象状态。

这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。

    /**
     * Makes a config object from an array, making the first level keys properties a new object.
     * Property values are converted to camelCase and are not set if one already exists.
     * @param array $configArray Config array.
     * @param boolean $strict To return an empty object if $configArray is not an array
     * @return stdObject The config object
     */
    public function makeConfigFromArray($configArray = [],$strict = true)
    {
        $object = new stdClass();

        if (!is_array($configArray)) {
            if(!$strict && !is_null($configArray)) {
                return $configArray;
            }
            return $object;
        }

        foreach ($configArray as $name => $value) {
            $_name = camel_case($name);
            if(is_array($value)) {
                $makeobject = true;
                foreach($value as $key => $val) {
                    if(is_numeric(substr($key,0,1))) {
                        $makeobject = false;
                    }
                    if(is_array($val)) {
                        $value[$key] = $this->makeConfigFromArray($val,false);
                    }
                }
                if($makeobject) {
                    $object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
                }
                else {
                    $object->{$name} = $object->{$_name} = $value;
                }

            }
            else {
                $object->{$name} = $object->{$_name} = $value;
            }
        }

        return $object;
    }

这将把yaml配置为

fields:
    abc:
        type: formfield
        something:
            - a
            - b
            - c
            - d:
                foo: 
                   bar

到由以下数组组成的数组:

array:1 [
  "fields" => array:1 [
    "abc" => array:2 [
      "type" => "formfield"
      "something" => array:4 [
        0 => "a"
        1 => "b"
        2 => "c"
        3 => array:1 [
          "d" => array:1 [
            "foo" => "bar"
          ]
        ]
      ]
    ]
  ]
]

以…为目标:

{#325
  +"fields": {#326
    +"abc": {#324
      +"type": "formfield"
      +"something": array:4 [
        0 => "a"
        1 => "b"
        2 => "c"
        3 => {#328
          +"d": {#327
            +"foo": "bar"
          }
        }
      ]
    }
  }
}

其他回答

你也可以通过在变量的左边添加(object)来创建一个新对象。

<?php
$a = Array
    ( 'status' => " text" );
var_dump($a);
$b = (object)$a;
var_dump($b);
var_dump($b->status);

http://codepad.org/9YmD1KsU

我使用以下代码将Yaml文件关联数组解析为对象状态。

这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。

    /**
     * Makes a config object from an array, making the first level keys properties a new object.
     * Property values are converted to camelCase and are not set if one already exists.
     * @param array $configArray Config array.
     * @param boolean $strict To return an empty object if $configArray is not an array
     * @return stdObject The config object
     */
    public function makeConfigFromArray($configArray = [],$strict = true)
    {
        $object = new stdClass();

        if (!is_array($configArray)) {
            if(!$strict && !is_null($configArray)) {
                return $configArray;
            }
            return $object;
        }

        foreach ($configArray as $name => $value) {
            $_name = camel_case($name);
            if(is_array($value)) {
                $makeobject = true;
                foreach($value as $key => $val) {
                    if(is_numeric(substr($key,0,1))) {
                        $makeobject = false;
                    }
                    if(is_array($val)) {
                        $value[$key] = $this->makeConfigFromArray($val,false);
                    }
                }
                if($makeobject) {
                    $object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
                }
                else {
                    $object->{$name} = $object->{$_name} = $value;
                }

            }
            else {
                $object->{$name} = $object->{$_name} = $value;
            }
        }

        return $object;
    }

这将把yaml配置为

fields:
    abc:
        type: formfield
        something:
            - a
            - b
            - c
            - d:
                foo: 
                   bar

到由以下数组组成的数组:

array:1 [
  "fields" => array:1 [
    "abc" => array:2 [
      "type" => "formfield"
      "something" => array:4 [
        0 => "a"
        1 => "b"
        2 => "c"
        3 => array:1 [
          "d" => array:1 [
            "foo" => "bar"
          ]
        ]
      ]
    ]
  ]
]

以…为目标:

{#325
  +"fields": {#326
    +"abc": {#324
      +"type": "formfield"
      +"something": array:4 [
        0 => "a"
        1 => "b"
        2 => "c"
        3 => {#328
          +"d": {#327
            +"foo": "bar"
          }
        }
      ]
    }
  }
}

我用了很简单的方法,

    $list_years         = array();
    $object             = new stdClass();

    $object->year_id   = 1 ;
    $object->year_name = 2001 ;
    $list_years[]       = $object;

通过使用(array)和(object)作为前缀,可以简单地将对象数组转换为标准数组,反之亦然

<?php
//defining an array
$a = array('a'=>'1','b'=>'2','c'=>'3','d'=>'4');

//defining an object array
$obj = new stdClass();
$obj->a = '1';
$obj->b = '2';
$obj->c = '3';
$obj->d = '4';

print_r($a);echo '<br>';
print_r($obj);echo '<br>';

//converting object array to array
$b = (array) $obj;
print_r($b);echo '<br>';

//converting array to object
$c = (object) $a;
print_r($c);echo '<br>';
?>

我也有这个问题,但我注意到json_decode将JSON数组转换为对象。

所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记

$object = json_decode(json_encode($array));

Or

$jsonString = json_encode($array);
$object = json_decode($jsonString);