如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
我使用以下代码将Yaml文件关联数组解析为对象状态。
这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。
/**
* Makes a config object from an array, making the first level keys properties a new object.
* Property values are converted to camelCase and are not set if one already exists.
* @param array $configArray Config array.
* @param boolean $strict To return an empty object if $configArray is not an array
* @return stdObject The config object
*/
public function makeConfigFromArray($configArray = [],$strict = true)
{
$object = new stdClass();
if (!is_array($configArray)) {
if(!$strict && !is_null($configArray)) {
return $configArray;
}
return $object;
}
foreach ($configArray as $name => $value) {
$_name = camel_case($name);
if(is_array($value)) {
$makeobject = true;
foreach($value as $key => $val) {
if(is_numeric(substr($key,0,1))) {
$makeobject = false;
}
if(is_array($val)) {
$value[$key] = $this->makeConfigFromArray($val,false);
}
}
if($makeobject) {
$object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
return $object;
}
这将把yaml配置为
fields:
abc:
type: formfield
something:
- a
- b
- c
- d:
foo:
bar
到由以下数组组成的数组:
array:1 [
"fields" => array:1 [
"abc" => array:2 [
"type" => "formfield"
"something" => array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => array:1 [
"d" => array:1 [
"foo" => "bar"
]
]
]
]
]
]
以…为目标:
{#325
+"fields": {#326
+"abc": {#324
+"type": "formfield"
+"something": array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => {#328
+"d": {#327
+"foo": "bar"
}
}
]
}
}
}
其他回答
你也可以通过在变量的左边添加(object)来创建一个新对象。
<?php
$a = Array
( 'status' => " text" );
var_dump($a);
$b = (object)$a;
var_dump($b);
var_dump($b->status);
http://codepad.org/9YmD1KsU
我使用以下代码将Yaml文件关联数组解析为对象状态。
这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。
/**
* Makes a config object from an array, making the first level keys properties a new object.
* Property values are converted to camelCase and are not set if one already exists.
* @param array $configArray Config array.
* @param boolean $strict To return an empty object if $configArray is not an array
* @return stdObject The config object
*/
public function makeConfigFromArray($configArray = [],$strict = true)
{
$object = new stdClass();
if (!is_array($configArray)) {
if(!$strict && !is_null($configArray)) {
return $configArray;
}
return $object;
}
foreach ($configArray as $name => $value) {
$_name = camel_case($name);
if(is_array($value)) {
$makeobject = true;
foreach($value as $key => $val) {
if(is_numeric(substr($key,0,1))) {
$makeobject = false;
}
if(is_array($val)) {
$value[$key] = $this->makeConfigFromArray($val,false);
}
}
if($makeobject) {
$object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
return $object;
}
这将把yaml配置为
fields:
abc:
type: formfield
something:
- a
- b
- c
- d:
foo:
bar
到由以下数组组成的数组:
array:1 [
"fields" => array:1 [
"abc" => array:2 [
"type" => "formfield"
"something" => array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => array:1 [
"d" => array:1 [
"foo" => "bar"
]
]
]
]
]
]
以…为目标:
{#325
+"fields": {#326
+"abc": {#324
+"type": "formfield"
+"something": array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => {#328
+"d": {#327
+"foo": "bar"
}
}
]
}
}
}
我用了很简单的方法,
$list_years = array();
$object = new stdClass();
$object->year_id = 1 ;
$object->year_name = 2001 ;
$list_years[] = $object;
通过使用(array)和(object)作为前缀,可以简单地将对象数组转换为标准数组,反之亦然
<?php
//defining an array
$a = array('a'=>'1','b'=>'2','c'=>'3','d'=>'4');
//defining an object array
$obj = new stdClass();
$obj->a = '1';
$obj->b = '2';
$obj->c = '3';
$obj->d = '4';
print_r($a);echo '<br>';
print_r($obj);echo '<br>';
//converting object array to array
$b = (array) $obj;
print_r($b);echo '<br>';
//converting array to object
$c = (object) $a;
print_r($c);echo '<br>';
?>
我也有这个问题,但我注意到json_decode将JSON数组转换为对象。
所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记
$object = json_decode(json_encode($array));
Or
$jsonString = json_encode($array);
$object = json_decode($jsonString);