如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
你可以使用反射:
<?php
$array = ['name'=>'maria','age'=>33];
class Person {
public $name;
public $age;
public function __construct(string $name, string $age){
$this->name = $name;
$this->age = $age;
}
}
function arrayToObject(array $array, string $class_name){
$r = new ReflectionClass($class_name);
$object = $r->newInstanceWithoutConstructor();
$list = $r->getProperties();
foreach($list as $prop){
$prop->setAccessible(true);
if(isset($array[$prop->name]))
$prop->setValue($object, $array[$prop->name]);
}
return $object;
}
$pessoa1 = arrayToObject($array, 'Person');
var_dump($pessoa1);
其他回答
快速攻击:
// assuming $var is a multidimensional array
$obj = json_decode (json_encode ($var), FALSE);
不漂亮,但很好用。
容易:
$object = json_decode(json_encode($array));
例子:
$array = array(
'key' => array(
'k' => 'value',
),
'group' => array('a', 'b', 'c')
);
$object = json_decode(json_encode($array));
那么,以下是正确的:
$object->key->k === 'value';
$object->group === array('a', 'b', 'c')
如果你需要将一个数组强制转换为一个特定的类(在我的例子中,我需要对象类型为Google_Service_AndroidPublisher_Resource_Inappproducts),你可以像这样从stdClass中将类名str_replace为预期的类:
function castArrayToClass(array $array, string $className)
{
//first cast the array to stdClass
$subject = serialize((object)$array);
//then change the class name
$converted = str_replace(
'O:8:"stdClass"',
'O:'.strlen($className).':"'.$className.'"',
$subject
);
unset($subject);
return unserialize($converted);
}
使用json_encode是有问题的,因为它处理非UTF-8数据的方式。值得注意的是,json_encode/json_encode方法也将非关联数组作为数组。这可能是你想要的,也可能不是。我最近需要重新创建这个解决方案的功能,但没有使用json_ functions。这是我想到的:
/**
* Returns true if the array has only integer keys
*/
function isArrayAssociative(array $array) {
return (bool)count(array_filter(array_keys($array), 'is_string'));
}
/**
* Converts an array to an object, but leaves non-associative arrays as arrays.
* This is the same logic that `json_decode(json_encode($arr), false)` uses.
*/
function arrayToObject(array $array, $maxDepth = 10) {
if($maxDepth == 0) {
return $array;
}
if(isArrayAssociative($array)) {
$newObject = new \stdClass;
foreach ($array as $key => $value) {
if(is_array($value)) {
$newObject->{$key} = arrayToObject($value, $maxDepth - 1);
} else {
$newObject->{$key} = $value;
}
}
return $newObject;
} else {
$newArray = array();
foreach ($array as $value) {
if(is_array($value)) {
$newArray[] = arrayToObject($value, $maxDepth - 1);
} else {
$newArray[] = $value;
}
}
return $newArray;
}
}
我也有这个问题,但我注意到json_decode将JSON数组转换为对象。
所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记
$object = json_decode(json_encode($array));
Or
$jsonString = json_encode($array);
$object = json_decode($jsonString);