如何将这样的数组转换为对象?

[128] => Array
    (
        [status] => "Figure A.
 Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
    )

[129] => Array
    (
        [status] => "The other day at work, I had some spare time"
    )

当前回答

你可以使用反射:

<?php

$array = ['name'=>'maria','age'=>33];

class Person {

    public $name;
    public $age;

    public function __construct(string $name, string $age){
        $this->name  = $name;
        $this->age = $age;
    }
}

function arrayToObject(array $array, string $class_name){

    $r = new ReflectionClass($class_name);
    $object = $r->newInstanceWithoutConstructor();
    $list = $r->getProperties();
    foreach($list as $prop){
      $prop->setAccessible(true);
      if(isset($array[$prop->name]))
        $prop->setValue($object, $array[$prop->name]);
    } 

    return $object;

}

$pessoa1 = arrayToObject($array, 'Person');
var_dump($pessoa1);

其他回答

快速攻击:

// assuming $var is a multidimensional array
$obj = json_decode (json_encode ($var), FALSE);

不漂亮,但很好用。

容易:

$object = json_decode(json_encode($array));

例子:

$array = array(
    'key' => array(
        'k' => 'value',
    ),
    'group' => array('a', 'b', 'c')
);

$object = json_decode(json_encode($array));

那么,以下是正确的:

$object->key->k === 'value';
$object->group === array('a', 'b', 'c')

如果你需要将一个数组强制转换为一个特定的类(在我的例子中,我需要对象类型为Google_Service_AndroidPublisher_Resource_Inappproducts),你可以像这样从stdClass中将类名str_replace为预期的类:

function castArrayToClass(array $array, string $className)
{
    //first cast the array to stdClass
    $subject = serialize((object)$array);
    //then change the class name
    $converted = str_replace(
        'O:8:"stdClass"',
        'O:'.strlen($className).':"'.$className.'"',
        $subject
    );
    unset($subject);

    return unserialize($converted);
}

使用json_encode是有问题的,因为它处理非UTF-8数据的方式。值得注意的是,json_encode/json_encode方法也将非关联数组作为数组。这可能是你想要的,也可能不是。我最近需要重新创建这个解决方案的功能,但没有使用json_ functions。这是我想到的:

/**
 * Returns true if the array has only integer keys
 */
function isArrayAssociative(array $array) {
    return (bool)count(array_filter(array_keys($array), 'is_string'));
}

/**
 * Converts an array to an object, but leaves non-associative arrays as arrays. 
 * This is the same logic that `json_decode(json_encode($arr), false)` uses.
 */
function arrayToObject(array $array, $maxDepth = 10) {
    if($maxDepth == 0) {
        return $array;
    }

    if(isArrayAssociative($array)) {
        $newObject = new \stdClass;
        foreach ($array as $key => $value) {
            if(is_array($value)) {
                $newObject->{$key} = arrayToObject($value, $maxDepth - 1);
            } else {
                $newObject->{$key} = $value;
            }
        }
        return $newObject;
    } else {

        $newArray = array();
        foreach ($array as $value) {
            if(is_array($value)) {
                $newArray[] = arrayToObject($value, $maxDepth - 1);
            } else {
                $newArray[] = $value;
            }                
        }
        return $newArray;
    }
}

我也有这个问题,但我注意到json_decode将JSON数组转换为对象。

所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记

$object = json_decode(json_encode($array));

Or

$jsonString = json_encode($array);
$object = json_decode($jsonString);