如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
显然,这只是对其他人答案的推断,但这里有一个递归函数,可以将任何多维数组转换为对象:
function convert_array_to_object($array){
$obj= new stdClass();
foreach ($array as $k=> $v) {
if (is_array($v)){
$v = convert_array_to_object($v);
}
$obj->{strtolower($k)} = $v;
}
return $obj;
}
记住,如果数组有数字键,它们仍然可以通过{}在结果对象中引用(例如:$obj->prop->{4}->prop)
其他回答
使用json_encode是有问题的,因为它处理非UTF-8数据的方式。值得注意的是,json_encode/json_encode方法也将非关联数组作为数组。这可能是你想要的,也可能不是。我最近需要重新创建这个解决方案的功能,但没有使用json_ functions。这是我想到的:
/**
* Returns true if the array has only integer keys
*/
function isArrayAssociative(array $array) {
return (bool)count(array_filter(array_keys($array), 'is_string'));
}
/**
* Converts an array to an object, but leaves non-associative arrays as arrays.
* This is the same logic that `json_decode(json_encode($arr), false)` uses.
*/
function arrayToObject(array $array, $maxDepth = 10) {
if($maxDepth == 0) {
return $array;
}
if(isArrayAssociative($array)) {
$newObject = new \stdClass;
foreach ($array as $key => $value) {
if(is_array($value)) {
$newObject->{$key} = arrayToObject($value, $maxDepth - 1);
} else {
$newObject->{$key} = $value;
}
}
return $newObject;
} else {
$newArray = array();
foreach ($array as $value) {
if(is_array($value)) {
$newArray[] = arrayToObject($value, $maxDepth - 1);
} else {
$newArray[] = $value;
}
}
return $newArray;
}
}
这个方法对我很管用
function array_to_obj($array, &$obj)
{
foreach ($array as $key => $value)
{
if (is_array($value))
{
$obj->$key = new stdClass();
array_to_obj($value, $obj->$key);
}
else
{
$obj->$key = $value;
}
}
return $obj;
}
function arrayToObject($array)
{
$object= new stdClass();
return array_to_obj($array,$object);
}
用法:
$myobject = arrayToObject($array);
print_r($myobject);
返回:
[127] => stdClass Object
(
[status] => Have you ever created a really great looking website design
)
[128] => stdClass Object
(
[status] => Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution.
)
[129] => stdClass Object
(
[status] => The other day at work, I had some spare time
)
像往常一样,你可以这样循环:
foreach($myobject as $obj)
{
echo $obj->status;
}
function object_to_array($data)
{
if (is_array($data) || is_object($data))
{
$result = array();
foreach ($data as $key => $value)
{
$result[$key] = object_to_array($value);
}
return $result;
}
return $data;
}
function array_to_object($data)
{
if (is_array($data) || is_object($data))
{
$result= new stdClass();
foreach ($data as $key => $value)
{
$result->$key = array_to_object($value);
}
return $result;
}
return $data;
}
我也有这个问题,但我注意到json_decode将JSON数组转换为对象。
所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记
$object = json_decode(json_encode($array));
Or
$jsonString = json_encode($array);
$object = json_decode($jsonString);
简单的方法是
$object = (object)$array;
但这不是你想要的。如果你想要对象,你想要实现一些东西,但这在这个问题中是缺失的。仅仅为了使用对象而使用对象是没有意义的。