为了让上面的工作(我需要一对作为字典的键)。我必须补充一句:

    public override Boolean Equals(Object o)
    {
        Pair<T, U> that = o as Pair<T, U>;
        if (that == null)
            return false;
        else
            return this.First.Equals(that.First) && this.Second.Equals(that.Second);
    }

一旦我这样做了，我还添加了

    public override Int32 GetHashCode()
    {
        return First.GetHashCode() ^ Second.GetHashCode();
    }

禁用编译器警告。

为了让上面的工作(我需要一对作为字典的键)。我必须补充一句:

    public override Boolean Equals(Object o)
    {
        Pair<T, U> that = o as Pair<T, U>;
        if (that == null)
            return false;
        else
            return this.First.Equals(that.First) && this.Second.Equals(that.Second);
    }

一旦我这样做了，我还添加了

    public override Int32 GetHashCode()
    {
        return First.GetHashCode() ^ Second.GetHashCode();
    }

禁用编译器警告。

有些答案似乎是错的，

你不能使用字典来存储(a,b)和(a,c)对。对的概念不应与键和值的关联查找相混淆 上面的许多代码似乎都是可疑的

这是我的pair类

public class Pair<X, Y>
{
    private X _x;
    private Y _y;

    public Pair(X first, Y second)
    {
        _x = first;
        _y = second;
    }

    public X first { get { return _x; } }

    public Y second { get { return _y; } }

    public override bool Equals(object obj)
    {
        if (obj == null)
            return false;
        if (obj == this)
            return true;
        Pair<X, Y> other = obj as Pair<X, Y>;
        if (other == null)
            return false;

        return
            (((first == null) && (other.first == null))
                || ((first != null) && first.Equals(other.first)))
              &&
            (((second == null) && (other.second == null))
                || ((second != null) && second.Equals(other.second)));
    }

    public override int GetHashCode()
    {
        int hashcode = 0;
        if (first != null)
            hashcode += first.GetHashCode();
        if (second != null)
            hashcode += second.GetHashCode();

        return hashcode;
    }
}

下面是一些测试代码:

[TestClass]
public class PairTest
{
    [TestMethod]
    public void pairTest()
    {
        string s = "abc";
        Pair<int, string> foo = new Pair<int, string>(10, s);
        Pair<int, string> bar = new Pair<int, string>(10, s);
        Pair<int, string> qux = new Pair<int, string>(20, s);
        Pair<int, int> aaa = new Pair<int, int>(10, 20);

        Assert.IsTrue(10 == foo.first);
        Assert.AreEqual(s, foo.second);
        Assert.AreEqual(foo, bar);
        Assert.IsTrue(foo.GetHashCode() == bar.GetHashCode());
        Assert.IsFalse(foo.Equals(qux));
        Assert.IsFalse(foo.Equals(null));
        Assert.IsFalse(foo.Equals(aaa));

        Pair<string, string> s1 = new Pair<string, string>("a", "b");
        Pair<string, string> s2 = new Pair<string, string>(null, "b");
        Pair<string, string> s3 = new Pair<string, string>("a", null);
        Pair<string, string> s4 = new Pair<string, string>(null, null);
        Assert.IsFalse(s1.Equals(s2));
        Assert.IsFalse(s1.Equals(s3));
        Assert.IsFalse(s1.Equals(s4));
        Assert.IsFalse(s2.Equals(s1));
        Assert.IsFalse(s3.Equals(s1));
        Assert.IsFalse(s2.Equals(s3));
        Assert.IsFalse(s4.Equals(s1));
        Assert.IsFalse(s1.Equals(s4));
    }
}

不幸的是，没有。你可以使用System.Collections.Generic。KeyValuePair<K, V>在许多情况下。

或者，你可以使用匿名类型来处理元组，至少在本地:

var x = new { First = "x", Second = 42 };

最后一种选择是创建自己的类。

除了自定义类或。net 4.0元组，自c# 7.0以来，有一个叫做ValueTuple的新特性，它是一个可以在这种情况下使用的结构体。而不是写:

Tuple<string, int> t = new Tuple<string, int>("Hello", 4);

并通过t.Item1和t.Item2访问值，你可以简单地这样做:

(string message, int count) = ("Hello", 4);

甚至:

(var message, var count) = ("Hello", 4);

元组从。net 4.0开始就可用了，并且支持泛型:

Tuple<string, int> t = new Tuple<string, int>("Hello", 4);

在以前的版本中，您可以使用System.Collections.Generic。KeyValuePair<K, V>或如下解:

public class Pair<T, U> {
    public Pair() {
    }

    public Pair(T first, U second) {
        this.First = first;
        this.Second = second;
    }

    public T First { get; set; }
    public U Second { get; set; }
};

像这样使用它:

Pair<String, int> pair = new Pair<String, int>("test", 2);
Console.WriteLine(pair.First);
Console.WriteLine(pair.Second);

这个输出:

test
2

或者甚至是这个链对:

Pair<Pair<String, int>, bool> pair = new Pair<Pair<String, int>, bool>();
pair.First = new Pair<String, int>();
pair.First.First = "test";
pair.First.Second = 12;
pair.Second = true;

Console.WriteLine(pair.First.First);
Console.WriteLine(pair.First.Second);
Console.WriteLine(pair.Second);

输出:

test
12
true