我知道如何创建一个有String参数并返回int的方法的引用，它是:
Function<String, Integer>
然而，如果函数抛出异常，比如它被定义为:
Integer myMethod(String s) throws IOException
我该如何定义这个引用呢?
当前回答
使用Function包装器的另一种解决方案是返回结果包装器的实例，如果一切正常，则返回成功，或者返回失败。
一些代码来澄清事情:
public interface ThrowableFunction<A, B> {
B apply(A a) throws Exception;
}
public abstract class Try<A> {
public static boolean isSuccess(Try tryy) {
return tryy instanceof Success;
}
public static <A, B> Function<A, Try<B>> tryOf(ThrowableFunction<A, B> function) {
return a -> {
try {
B result = function.apply(a);
return new Success<B>(result);
} catch (Exception e) {
return new Failure<>(e);
}
};
}
public abstract boolean isSuccess();
public boolean isError() {
return !isSuccess();
}
public abstract A getResult();
public abstract Exception getError();
}
public class Success<A> extends Try<A> {
private final A result;
public Success(A result) {
this.result = result;
}
@Override
public boolean isSuccess() {
return true;
}
@Override
public A getResult() {
return result;
}
@Override
public Exception getError() {
return new UnsupportedOperationException();
}
@Override
public boolean equals(Object that) {
if(!(that instanceof Success)) {
return false;
}
return Objects.equal(result, ((Success) that).getResult());
}
}
public class Failure<A> extends Try<A> {
private final Exception exception;
public Failure(Exception exception) {
this.exception = exception;
}
@Override
public boolean isSuccess() {
return false;
}
@Override
public A getResult() {
throw new UnsupportedOperationException();
}
@Override
public Exception getError() {
return exception;
}
}
一个简单的用例:
List<Try<Integer>> result = Lists.newArrayList(1, 2, 3).stream().
map(Try.<Integer, Integer>tryOf(i -> someMethodThrowingAnException(i))).
collect(Collectors.toList());
其他回答
使用Function包装器的另一种解决方案是返回结果包装器的实例，如果一切正常，则返回成功，或者返回失败。
一些代码来澄清事情:
public interface ThrowableFunction<A, B> {
B apply(A a) throws Exception;
}
public abstract class Try<A> {
public static boolean isSuccess(Try tryy) {
return tryy instanceof Success;
}
public static <A, B> Function<A, Try<B>> tryOf(ThrowableFunction<A, B> function) {
return a -> {
try {
B result = function.apply(a);
return new Success<B>(result);
} catch (Exception e) {
return new Failure<>(e);
}
};
}
public abstract boolean isSuccess();
public boolean isError() {
return !isSuccess();
}
public abstract A getResult();
public abstract Exception getError();
}
public class Success<A> extends Try<A> {
private final A result;
public Success(A result) {
this.result = result;
}
@Override
public boolean isSuccess() {
return true;
}
@Override
public A getResult() {
return result;
}
@Override
public Exception getError() {
return new UnsupportedOperationException();
}
@Override
public boolean equals(Object that) {
if(!(that instanceof Success)) {
return false;
}
return Objects.equal(result, ((Success) that).getResult());
}
}
public class Failure<A> extends Try<A> {
private final Exception exception;
public Failure(Exception exception) {
this.exception = exception;
}
@Override
public boolean isSuccess() {
return false;
}
@Override
public A getResult() {
throw new UnsupportedOperationException();
}
@Override
public Exception getError() {
return exception;
}
}
一个简单的用例:
List<Try<Integer>> result = Lists.newArrayList(1, 2, 3).stream().
map(Try.<Integer, Integer>tryOf(i -> someMethodThrowingAnException(i))).
collect(Collectors.toList());
这个问题也一直困扰着我;这就是我创建这个项目的原因。
用它你可以做:
final ThrowingFunction<String, Integer> f = yourMethodReferenceHere;
JDK总共定义了39个接口，它们都有类似的抛出功能;这些都是流中使用的@ functionalinterface(基本流，还有IntStream, LongStream和DoubleStream)。
当它们中的每一个都扩展了它们的非抛出对应对象时，你也可以直接在lambdas中使用它们:
myStringStream.map(f) // <-- works
默认行为是，当您抛出lambda抛出一个检查异常时，抛出一个ThrownByLambdaException，并将检查异常作为原因。因此，您可以捕捉到它并得到原因。
其他特性也可用。
您需要执行以下操作之一。
If it's your code, then define your own functional interface that declares the checked exception: @FunctionalInterface public interface CheckedFunction<T, R> { R apply(T t) throws IOException; } and use it: void foo (CheckedFunction f) { ... } Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception: public Integer myWrappedMethod(String s) { try { return myMethod(s); } catch(IOException e) { throw new UncheckedIOException(e); } } and then: Function<String, Integer> f = (String t) -> myWrappedMethod(t); or: Function<String, Integer> f = (String t) -> { try { return myMethod(t); } catch(IOException e) { throw new UncheckedIOException(e); } };
然而，你可以创建自己的FunctionalInterface，抛出如下..
@FunctionalInterface
public interface UseInstance<T, X extends Throwable> {
void accept(T instance) throws X;
}
然后使用Lambdas或引用实现它，如下所示。
import java.io.FileWriter;
import java.io.IOException;
//lambda expressions and the execute around method (EAM) pattern to
//manage resources
public class FileWriterEAM {
private final FileWriter writer;
private FileWriterEAM(final String fileName) throws IOException {
writer = new FileWriter(fileName);
}
private void close() throws IOException {
System.out.println("close called automatically...");
writer.close();
}
public void writeStuff(final String message) throws IOException {
writer.write(message);
}
//...
public static void use(final String fileName, final UseInstance<FileWriterEAM, IOException> block) throws IOException {
final FileWriterEAM writerEAM = new FileWriterEAM(fileName);
try {
block.accept(writerEAM);
} finally {
writerEAM.close();
}
}
public static void main(final String[] args) throws IOException {
FileWriterEAM.use("eam.txt", writerEAM -> writerEAM.writeStuff("sweet"));
FileWriterEAM.use("eam2.txt", writerEAM -> {
writerEAM.writeStuff("how");
writerEAM.writeStuff("sweet");
});
FileWriterEAM.use("eam3.txt", FileWriterEAM::writeIt);
}
void writeIt() throws IOException{
this.writeStuff("How ");
this.writeStuff("sweet ");
this.writeStuff("it is");
}
}
免责声明:我还没有使用过Java 8，只是阅读过它。
Function<String, Integer>不抛出IOException，所以你不能在其中放入任何抛出IOException的代码。如果你正在调用一个期望Function<String, Integer>的方法，那么你传递给该方法的lambda不能抛出IOException，句号。你可以这样写一个lambda(我认为这是lambda语法，不确定):
(String s) -> {
try {
return myMethod(s);
} catch (IOException ex) {
throw new RuntimeException(ex);
// (Or do something else with it...)
}
}
或者，如果你传递lambda的方法是你自己写的，你可以定义一个新的函数接口，并使用它作为参数类型，而不是Function<String, Integer>:
public interface FunctionThatThrowsIOException<I, O> {
O apply(I input) throws IOException;
}
推荐文章
- JavaFX应用程序图标
- Java:强/软/弱/幻影引用的区别
- 在序列化和反序列化期间JSON属性的不同名称
- 获取Android设备名称
- Gradle代理配置
- 如何获得具有已知资源名称的资源id ?
- 在Android上将字符串转换为整数
- 为什么“System.out。”println“工作在Android?
- 不能在lambda表达式中使用ref或out参数
- 在Java中什么时候使用可变参数?
- Mockito的argumentCaptor的例子
- 是否有可能键入提示一个lambda函数?
- 我如何告诉Spring Boot哪个主类用于可执行jar?
- 如何将Java8流的元素添加到现有的列表中
- 在Java 8中是否可以转换流?
