我知道如何创建一个有String参数并返回int的方法的引用,它是:

Function<String, Integer>

然而,如果函数抛出异常,比如它被定义为:

Integer myMethod(String s) throws IOException

我该如何定义这个引用呢?


当前回答

然而,你可以创建自己的FunctionalInterface,抛出如下..

@FunctionalInterface
public interface UseInstance<T, X extends Throwable> {
  void accept(T instance) throws X;
}

然后使用Lambdas或引用实现它,如下所示。

import java.io.FileWriter;
import java.io.IOException;

//lambda expressions and the execute around method (EAM) pattern to
//manage resources

public class FileWriterEAM  {
  private final FileWriter writer;

  private FileWriterEAM(final String fileName) throws IOException {
    writer = new FileWriter(fileName);
  }
  private void close() throws IOException {
    System.out.println("close called automatically...");
    writer.close();
  }
  public void writeStuff(final String message) throws IOException {
    writer.write(message);
  }
  //...

  public static void use(final String fileName, final UseInstance<FileWriterEAM, IOException> block) throws IOException {

    final FileWriterEAM writerEAM = new FileWriterEAM(fileName);    
    try {
      block.accept(writerEAM);
    } finally {
      writerEAM.close();
    }
  }

  public static void main(final String[] args) throws IOException {

    FileWriterEAM.use("eam.txt", writerEAM -> writerEAM.writeStuff("sweet"));

    FileWriterEAM.use("eam2.txt", writerEAM -> {
        writerEAM.writeStuff("how");
        writerEAM.writeStuff("sweet");      
      });

    FileWriterEAM.use("eam3.txt", FileWriterEAM::writeIt);     

  }


 void writeIt() throws IOException{
     this.writeStuff("How ");
     this.writeStuff("sweet ");
     this.writeStuff("it is");

 }

}

其他回答

public void frankTest() {
    int pageId= -1;

    List<Book> users= null;
    try {
        //Does Not Compile:  Object page=DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> new Portal(rw.getInt("id"), "", users.parallelStream().filter(uu -> uu.getVbid() == rw.getString("user_id")).findFirst().get(), rw.getString("name")));

        //Compiles:
        Object page= DatabaseConnection.getSpringConnection().queryForObject("SELECT * FROM bookmark_page", (rw, n) -> { 
            try {
                final Book bk= users.stream().filter(bp -> { 
                    String name= null;
                    try {
                        name = rw.getString("name");
                    } catch (Exception e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }
                    return bp.getTitle().equals(name); 
                }).limit(1).collect(Collectors.toList()).get(0);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return new Portal(rw.getInt("id"), "", users.get(0), rw.getString("name")); 
        } );
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

我认为榴莲的错误课程结合了上面各种建议的许多优点。

将抛出函数包装到标准Java 8函数接口。 轻松指定各种处理错误的策略 在包装返回值的方法时,指定默认值和重新抛出RuntimeException之间有重要区别。 抛出Java 8的函数接口版本 类似于fge的答案 用于抛出特定异常的标准接口 这解决了Zoltán的问题

在你的项目中加入榴莲,你可以:

从jcenter或maven中心com.diffplug.durian:durian:3.3.0获取 或者只是复制粘贴两个小类到你的代码中:throws .java和Errors.java

你可以使用ET。ET是一个用于异常转换/转换的小型Java 8库。

对于ET,它看起来是这样的:

// Do this once
ExceptionTranslator et = ET.newConfiguration().done();

...

// if your method returns something
Function<String, Integer> f = (t) -> et.withReturningTranslation(() -> myMethod(t));

// if your method returns nothing
Consumer<String> c = (t) -> et.withTranslation(() -> myMethod(t));

ExceptionTranslator实例是线程安全的,可以由多个组件共享。如果你喜欢,你可以配置更具体的异常转换规则(例如FooCheckedException -> BarRuntimeException)。 如果没有其他可用的规则,被检查的异常将自动转换为RuntimeException。

(声明:我是ET的作者)

免责声明:我还没有使用过Java 8,只是阅读过它。

Function<String, Integer>不抛出IOException,所以你不能在其中放入任何抛出IOException的代码。如果你正在调用一个期望Function<String, Integer>的方法,那么你传递给该方法的lambda不能抛出IOException,句号。你可以这样写一个lambda(我认为这是lambda语法,不确定):

(String s) -> {
    try {
        return myMethod(s);
    } catch (IOException ex) {
        throw new RuntimeException(ex);
        // (Or do something else with it...)
    }
}

或者,如果你传递lambda的方法是你自己写的,你可以定义一个新的函数接口,并使用它作为参数类型,而不是Function<String, Integer>:

public interface FunctionThatThrowsIOException<I, O> {
    O apply(I input) throws IOException;
}

您需要执行以下操作之一。

If it's your code, then define your own functional interface that declares the checked exception: @FunctionalInterface public interface CheckedFunction<T, R> { R apply(T t) throws IOException; } and use it: void foo (CheckedFunction f) { ... } Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception: public Integer myWrappedMethod(String s) { try { return myMethod(s); } catch(IOException e) { throw new UncheckedIOException(e); } } and then: Function<String, Integer> f = (String t) -> myWrappedMethod(t); or: Function<String, Integer> f = (String t) -> { try { return myMethod(t); } catch(IOException e) { throw new UncheckedIOException(e); } };