我目前正在为“A”生成一个8字符伪随机大写字符串。。“Z”:

value = ""; 8.times{value  << (65 + rand(25)).chr}

但它看起来不干净,而且不能作为参数传递,因为它不是一个单独的语句。要获取混合大小写字符串“a”。。“z”加“A”。。“Z”,我将其更改为:

value = ""; 8.times{value << ((rand(2)==1?65:97) + rand(25)).chr}

但它看起来像垃圾。

有人有更好的方法吗?


当前回答

以下内容对我很有用

def generate_random_password(min_length, max_length)
    length = SecureRandom.random_number(max_length - min_length) + min_length
    character_sets = [ 
      ('a'..'z').to_a,
      ('A'..'Z').to_a,
      ('0'..'9').to_a,
      "~!@^&*()_-+=[]|:;<,>.?".split('')
    ]   
    retval = []
    #   
    # Add one character from each set
    #   
    character_sets.each do |character_set|
      character = character_set[SecureRandom.random_number(character_set.count)]
      retval.push character
    end 
    #   
    # Fill the rest of the password with a random character from a random set
    #   
    i = character_sets.count - 1 
    while i < length
      character_set = character_sets[SecureRandom.random_number(character_sets.count)]
      character = character_set[SecureRandom.random_number(character_set.count)]
      retval.push character
      i += 1
    end
    retval.shuffle.join
  end

其他回答

使用此方法,您可以传入一个很短的长度。默认设置为6。

def generate_random_string(length=6)
  string = ""
  chars = ("A".."Z").to_a
  length.times do
    string << chars[rand(chars.length-1)]
  end
  string
end

下面是一个长度为8的随机密码的简单代码:

rand_password=('0'..'z').to_a.shuffle.first(8).join

请注意:rand对于攻击者来说是可预测的,因此可能不安全。如果这是用于生成密码的,则绝对应该使用SecureRandom。我用的是这样的东西:

length = 10
characters = ('A'..'Z').to_a + ('a'..'z').to_a + ('0'..'9').to_a

password = SecureRandom.random_bytes(length).each_char.map do |char|
  characters[(char.ord % characters.length)]
end.join

您可以使用Ruby Gem Facets中的String#随机。

它基本上做到了这一点:

class String
  def self.random(len=32, character_set = ["A".."Z", "a".."z", "0".."9"])
    characters = character_set.map { |i| i.to_a }.flatten
    characters_len = characters.length
    (0...len).map{ characters[rand(characters_len)] }.join
  end
end

在这里加上我的美分。。。

def random_string(length = 8)
  rand(32**length).to_s(32)
end