LSP的这种形式太强大了:

如果对于每个类型为S的对象o1，都有一个类型为T的对象o2，使得对于所有用T定义的程序P，当o1取代o2时，P的行为不变，那么S是T的子类型。

这基本上意味着S是t的另一个完全封装的实现，我可以大胆地认为性能是P行为的一部分……

因此，基本上，任何延迟绑定的使用都违反了LSP。当我们用一种类型的对象替换另一种类型的对象时，获得不同的行为是OO的全部意义所在!

维基百科引用的公式更好，因为属性取决于上下文，并不一定包括程序的整个行为。

LSP是关于类的契约的规则:如果基类满足契约，则LSP派生的类也必须满足该契约。

在Pseudo-python

class Base:
   def Foo(self, arg): 
       # *... do stuff*

class Derived(Base):
   def Foo(self, arg):
       # *... do stuff*

如果每次在派生对象上调用Foo，它给出的结果与在Base对象上调用Foo完全相同，只要arg是相同的。

简单来说，LSP是指同一超类的对象应该能够在不破坏任何东西的情况下相互交换。

例如，如果我们有一个从Animal类派生的Cat和Dog类，那么任何使用Animal类的函数都应该能够使用Cat或Dog，并且行为正常。

在一个非常简单的句子中，我们可以说:

子类不能违背它的基类特征。它必须有能力。我们可以说这和子类型是一样的。

Liskov's Substitution Principle(LSP) All the time we design a program module and we create some class hierarchies. Then we extend some classes creating some derived classes. We must make sure that the new derived classes just extend without replacing the functionality of old classes. Otherwise, the new classes can produce undesired effects when they are used in existing program modules. Liskov's Substitution Principle states that if a program module is using a Base class, then the reference to the Base class can be replaced with a Derived class without affecting the functionality of the program module.

例子:

Below is the classic example for which the Liskov's Substitution Principle is violated. In the example, 2 classes are used: Rectangle and Square. Let's assume that the Rectangle object is used somewhere in the application. We extend the application and add the Square class. The square class is returned by a factory pattern, based on some conditions and we don't know the exact what type of object will be returned. But we know it's a Rectangle. We get the rectangle object, set the width to 5 and height to 10 and get the area. For a rectangle with width 5 and height 10, the area should be 50. Instead, the result will be 100

    // Violation of Likov's Substitution Principle
class Rectangle {
    protected int m_width;
    protected int m_height;

    public void setWidth(int width) {
        m_width = width;
    }

    public void setHeight(int height) {
        m_height = height;
    }

    public int getWidth() {
        return m_width;
    }

    public int getHeight() {
        return m_height;
    }

    public int getArea() {
        return m_width * m_height;
    }
}

class Square extends Rectangle {
    public void setWidth(int width) {
        m_width = width;
        m_height = width;
    }

    public void setHeight(int height) {
        m_width = height;
        m_height = height;
    }

}

class LspTest {
    private static Rectangle getNewRectangle() {
        // it can be an object returned by some factory ...
        return new Square();
    }

    public static void main(String args[]) {
        Rectangle r = LspTest.getNewRectangle();

        r.setWidth(5);
        r.setHeight(10);
        // user knows that r it's a rectangle.
        // It assumes that he's able to set the width and height as for the base
        // class

        System.out.println(r.getArea());
        // now he's surprised to see that the area is 100 instead of 50.
    }
}

结论: 这个原则只是开闭原则的延伸 意味着我们必须确保新的派生类正在扩展 基类而不改变它们的行为。

参见:开闭原则

对于更好的结构，还有一些类似的概念:约定优于配置

LSP关注不变量。

经典示例由以下伪代码声明给出(实现略):

class Rectangle {
    int getHeight()
    void setHeight(int value) {
        postcondition: width didn’t change
    }
    int getWidth()
    void setWidth(int value) {
        postcondition: height didn’t change
    }
}

class Square extends Rectangle { }

现在我们有一个问题，尽管接口匹配。原因是我们违反了源自正方形和矩形数学定义的不变量。getter和setter的工作方式，矩形应该满足以下不变量:

void invariant(Rectangle r) {
    r.setHeight(200)
    r.setWidth(100)
    assert(r.getHeight() == 200 and r.getWidth() == 100)
}

然而，Square的正确实现必须违反这个不变量(以及显式后置条件)，因此它不是Rectangle的有效替代品。