给定代表某人生日的DateTime,我如何计算他们的年龄(以年为单位)?
当前回答
为什么不能简化为检查出生日期?
第一行(var year=end.year-start.year-1;):假设出生日期尚未发生在结束年份。然后检查月份和日期,看看是否发生了;再增加一年。
对闰年情景没有特殊处理。如果不是闰年,你不能创建一个日期(2月29日)作为结束日期,所以如果结束日期是3月1日,而不是28日,生日庆祝活动将被计算在内。下面的函数将将此场景作为普通日期进行描述。
static int Get_Age(DateTime start, DateTime end)
{
var year = end.Year - start.Year - 1;
if (end.Month < start.Month)
return year;
else if (end.Month == start.Month)
{
if (end.Day >= start.Day)
return ++year;
return year;
}
else
return ++year;
}
static void Test_Get_Age()
{
var start = new DateTime(2008, 4, 10); // b-date, leap year BTY
var end = new DateTime(2023, 2, 1); // end date is before the b-date
var result1 = Get_Age(start, end);
var success1 = result1 == 14; // true
end = new DateTime(2023, 4, 10); // end date is on the b-date
var result2 = Get_Age(start, end);
var success2 = result2 == 15; // true
end = new DateTime(2023, 6, 22); // end date is after the b-date
var result3 = Get_Age(start, end);
var success3 = result3 == 15; // true
start = new DateTime(2008, 2, 29); // b-date is on feb 29
end = new DateTime(2023, 2, 28); // end date is before the b-date
var result4 = Get_Age(start, end);
var success4 = result4 == 14; // true
end = new DateTime(2020, 2, 29); // end date is on the b-date, on another leap year
var result5 = Get_Age(start, end);
var success5 = result5 == 12; // true
}
其他回答
这里有一个解决方案。
DateTime dateOfBirth = new DateTime(2000, 4, 18);
DateTime currentDate = DateTime.Now;
int ageInYears = 0;
int ageInMonths = 0;
int ageInDays = 0;
ageInDays = currentDate.Day - dateOfBirth.Day;
ageInMonths = currentDate.Month - dateOfBirth.Month;
ageInYears = currentDate.Year - dateOfBirth.Year;
if (ageInDays < 0)
{
ageInDays += DateTime.DaysInMonth(currentDate.Year, currentDate.Month);
ageInMonths = ageInMonths--;
if (ageInMonths < 0)
{
ageInMonths += 12;
ageInYears--;
}
}
if (ageInMonths < 0)
{
ageInMonths += 12;
ageInYears--;
}
Console.WriteLine("{0}, {1}, {2}", ageInYears, ageInMonths, ageInDays);
我对Mark Soen的答案做了一个小小的修改:我重写了第三行,以便可以更容易地解析表达式。
public int AgeInYears(DateTime bday)
{
DateTime now = DateTime.Today;
int age = now.Year - bday.Year;
if (bday.AddYears(age) > now)
age--;
return age;
}
为了清晰起见,我还将其转换为函数。
这为这个问题提供了“更多细节”。也许这就是你要找的
DateTime birth = new DateTime(1974, 8, 29);
DateTime today = DateTime.Now;
TimeSpan span = today - birth;
DateTime age = DateTime.MinValue + span;
// Make adjustment due to MinValue equalling 1/1/1
int years = age.Year - 1;
int months = age.Month - 1;
int days = age.Day - 1;
// Print out not only how many years old they are but give months and days as well
Console.Write("{0} years, {1} months, {2} days", years, months, days);
我花了一些时间研究这个问题,并用这个来计算某人的年龄,以年、月和日为单位。我已经针对2月29日的问题和闰年进行了测试,它似乎奏效了,我希望得到任何反馈:
public void LoopAge(DateTime myDOB, DateTime FutureDate)
{
int years = 0;
int months = 0;
int days = 0;
DateTime tmpMyDOB = new DateTime(myDOB.Year, myDOB.Month, 1);
DateTime tmpFutureDate = new DateTime(FutureDate.Year, FutureDate.Month, 1);
while (tmpMyDOB.AddYears(years).AddMonths(months) < tmpFutureDate)
{
months++;
if (months > 12)
{
years++;
months = months - 12;
}
}
if (FutureDate.Day >= myDOB.Day)
{
days = days + FutureDate.Day - myDOB.Day;
}
else
{
months--;
if (months < 0)
{
years--;
months = months + 12;
}
days +=
DateTime.DaysInMonth(
FutureDate.AddMonths(-1).Year, FutureDate.AddMonths(-1).Month
) + FutureDate.Day - myDOB.Day;
}
//add an extra day if the dob is a leap day
if (DateTime.IsLeapYear(myDOB.Year) && myDOB.Month == 2 && myDOB.Day == 29)
{
//but only if the future date is less than 1st March
if (FutureDate >= new DateTime(FutureDate.Year, 3, 1))
days++;
}
}
MSDN帮助为什么没有告诉您这一点?看起来很明显:
System.DateTime birthTime = AskTheUser(myUser); // :-)
System.DateTime now = System.DateTime.Now;
System.TimeSpan age = now - birthTime; // As simple as that
double ageInDays = age.TotalDays; // Will you convert to whatever you want yourself?
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