我需要能够在运行时合并两个(非常简单)JavaScript对象。例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
是否有一种内置的方法来实现这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法。
我需要能够在运行时合并两个(非常简单)JavaScript对象。例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
是否有一种内置的方法来实现这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法。
当前回答
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
// result
result: {food: "pizza", car: "ford", animal: "dog"}
使用jQuery.exde()-Link
// Merge obj1 & obj2 to result
var result1 = $.extend( {}, obj1, obj2 );
使用_.merge()-链接
// Merge obj1 & obj2 to result
var result2 = _.merge( {}, obj1, obj2 );
使用_.exde()-链接
// Merge obj1 & obj2 to result
var result3 = _.extend( {}, obj1, obj2 );
使用Object.assign()ECMAScript 2015(ES6)-Link
// Merge obj1 & obj2 to result
var result4 = Object.assign( {}, obj1, obj2 );
全部输出
obj1: { animal: 'dog' }
obj2: { food: 'pizza', car: 'ford' }
result1: {food: "pizza", car: "ford", animal: "dog"}
result2: {food: "pizza", car: "ford", animal: "dog"}
result3: {food: "pizza", car: "ford", animal: "dog"}
result4: {food: "pizza", car: "ford", animal: "dog"}
其他回答
函数扩展(o,o1,o2){如果(!(o instanceof Object))o={};副本(o,o1);如果(o2)副本(o,o2)函数isObject(obj){var type=Object.protype.toString.call(obj);return obj===对象(obj)&&type!='[object Array]'&&type!='[object函数]';};功能副本(a,b){//将o2复制到ofor(b中的var键)if(b.hasOwnProperty(键)){if(isObject(b[key])){if(!isObject(a[key]))a[key]=Object.assign({},b[key]);其他副本(a[key],b[key])}其他的a[key]=b[key];}}返回o;};变量o1={a:{foo:1},b:1},o2={a:{bar:2},b:[1],c:()=>{}},newMerged=扩展({},o1,o2);console.log(newMerged)控制台日志(o1)控制台日志(o2)
您可以为每个对象分配一个默认的合并(也许“继承”一个更好的名称)方法:
它应该使用对象或实例化函数。
如果需要,下面的代码处理重写合并值:
Object.prototype.merge = function(obj, override) {
// Don't override by default
for (var key in obj) {
var n = obj[key];
var t = this[key];
this[key] = (override && t) ? n : t;
};
};
测试数据如下:
var Mammal = function () {
this.eyes = 2;
this.thinking_brain = false;
this.say = function () {
console.log('screaming like a mammal')};
}
var Human = function () {
this.thinking_brain = true;
this.say = function() {console.log('shouting like a human')};
}
john = new Human();
// Extend mammal, but do not override from mammal
john.merge(new Mammal());
john.say();
// Extend mammal and override from mammal
john.merge(new Mammal(), true);
john.say();
我的方式:
function mergeObjects(defaults, settings) {
Object.keys(defaults).forEach(function(key_default) {
if (typeof settings[key_default] == "undefined") {
settings[key_default] = defaults[key_default];
} else if (isObject(defaults[key_default]) && isObject(settings[key_default])) {
mergeObjects(defaults[key_default], settings[key_default]);
}
});
function isObject(object) {
return Object.prototype.toString.call(object) === '[object Object]';
}
return settings;
}
:)
使用jQuery库尝试这种方式
let obj1 = { food: 'pizza', car: 'ford' }
let obj2 = { animal: 'dog' }
console.log(jQuery.extend(obj1, obj2))
以下两个可能是一个很好的起点。lodash还为那些特殊需求提供定制功能!
_.延伸(http://underscorejs.org/#extend) _.合并(https://lodash.com/docs#merge)