试试这个

let today = new Date(). toisostring()。片(0,10) const startDate = '2021-04-15'; const endDate = today; const diffInMs = new Date(endDate) - new Date(startDate) const diffInDays = diffInMs / (1000 * 60 * 60 * 24); alert(diffInDays);

这个答案基于另一个答案(链接在最后)，是关于两个日期之间的差异。 你可以看到它是如何工作的，因为它很简单，它还包括将差异分成 时间单位(我做的一个函数)并转换为UTC以停止时区问题。

function date_units_diff(a, b, unit_amounts) { var split_to_whole_units = function (milliseconds, unit_amounts) { // unit_amounts = list/array of amounts of milliseconds in a // second, seconds in a minute, etc., for example "[1000, 60]". time_data = [milliseconds]; for (i = 0; i < unit_amounts.length; i++) { time_data.push(parseInt(time_data[i] / unit_amounts[i])); time_data[i] = time_data[i] % unit_amounts[i]; }; return time_data.reverse(); }; if (unit_amounts == undefined) { unit_amounts = [1000, 60, 60, 24]; }; var utc_a = new Date(a.toUTCString()); var utc_b = new Date(b.toUTCString()); var diff = (utc_b - utc_a); return split_to_whole_units(diff, unit_amounts); } // Example of use: var d = date_units_diff(new Date(2010, 0, 1, 0, 0, 0, 0), new Date()).slice(0,-2); document.write("In difference: 0 days, 1 hours, 2 minutes.".replace( /0|1|2/g, function (x) {return String( d[Number(x)] );} ));

我上面的代码是如何工作的

日期/时间差异，以毫秒为单位，可以使用date对象计算:

var a = new Date(); // Current date now.
var b = new Date(2010, 0, 1, 0, 0, 0, 0); // Start of 2010.

var utc_a = new Date(a.toUTCString());
var utc_b = new Date(b.toUTCString());
var diff = (utc_b - utc_a); // The difference as milliseconds.

然后算出这个差值的秒数，将其除以1000进行换算 毫秒到秒，然后将结果更改为整数(整数)以删除 毫秒数(小数的小数部分):var seconds = parseInt(diff/1000)。 此外，我可以使用相同的过程获得更长的时间单位，例如: -(整)分钟，秒除以60，结果变为整数， —hours，分钟除以60，返回结果为整数。

我创建了一个函数来完成这个过程，把差值分成 整个时间单位，命名为split_to_whole_units，演示如下:

console.log(split_to_whole_units(72000, [1000, 60]));
// -> [1,12,0] # 1 (whole) minute, 12 seconds, 0 milliseconds.

这个答案是基于另一个答案的。

我认为解决方案不是100%正确的，我会使用天花板而不是地板，圆形将工作，但这不是正确的操作。

function dateDiff(str1, str2){
    var diff = Date.parse(str2) - Date.parse(str1); 
    return isNaN(diff) ? NaN : {
        diff: diff,
        ms: Math.ceil(diff % 1000),
        s: Math.ceil(diff / 1000 % 60),
        m: Math.ceil(diff / 60000 % 60),
        h: Math.ceil(diff / 3600000 % 24),
        d: Math.ceil(diff / 86400000)
    };
}

从DatePicker小部件使用formatDate怎么样?您可以使用它来转换时间戳格式的日期(从01/01/1970开始的毫秒)，然后做一个简单的减法。

function timeDifference(date1, date2) { var oneDay = 24 * 60 * 60; // hours*minutes*seconds var oneHour = 60 * 60; // minutes*seconds var oneMinute = 60; // 60 seconds var firstDate = date1.getTime(); // convert to milliseconds var secondDate = date2.getTime(); // convert to milliseconds var seconds = Math.round(Math.abs(firstDate - secondDate) / 1000); //calculate the diffrence in seconds // the difference object var difference = { "days": 0, "hours": 0, "minutes": 0, "seconds": 0, } //calculate all the days and substract it from the total while (seconds >= oneDay) { difference.days++; seconds -= oneDay; } //calculate all the remaining hours then substract it from the total while (seconds >= oneHour) { difference.hours++; seconds -= oneHour; } //calculate all the remaining minutes then substract it from the total while (seconds >= oneMinute) { difference.minutes++; seconds -= oneMinute; } //the remaining seconds : difference.seconds = seconds; //return the difference object return difference; } console.log(timeDifference(new Date(2017,0,1,0,0,0),new Date()));

这可能不是最优雅的解决方案，但我认为它似乎用一段相对简单的代码就回答了这个问题。你不能用这样的词吗?

function dayDiff(startdate, enddate) {
  var dayCount = 0;

  while(enddate >= startdate) {
    dayCount++;
    startdate.setDate(startdate.getDate() + 1);
  }

return dayCount; 
}

这是假设您将日期对象作为参数传递。