例如，在输入框中给定两个日期:
<input id="first" value="1/1/2000"/>
<input id="second" value="1/1/2001"/>
<script>
alert(datediff("day", first, second)); // what goes here?
</script>
如何在JavaScript中获得两个日期之间的天数?
当前回答
使用Moment.js
Var future = moment('05/02/2015'); Var start = moment('04/23/2015'); Var d =未来。diff(开始,“天”);/ / 9 console.log (d); < script src = " https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.17.1/moment-with-locales.min.js " > < /脚本>
其他回答
如果我们想计算我们的年龄，这是一个有点不同的答案
{
birthday: 'April 22, 1993',
names: {
first: 'Keith',
last: 'Buckley'
}
},
{
birthday: 'January 3, 1975',
names: {
first: 'Larry',
last: 'Heep'
}
},
{
birthday: 'February 12, 1944',
names: {
first: 'Linda',
last: 'Bermeer'
}
}
];
const cleanPeople = people.map(function ({birthday, names:{first, last}}) {
// birthday, age, fullName;
const now = new Date();
var age = Math.floor(( Date.parse(now) - Date.parse(birthday)) / 31536000000);
return {
age,
fullName:`${first} ${last}`
}
});
console.log(cleanPeople);
console.table(cleanPeople);
简单、容易、复杂。此函数将每1秒调用一次以更新时间。
const year = (new Date().getFullYear());
const bdayDate = new Date("04,11,2019").getTime(); //mmddyyyy
// countdown
let timer = setInterval(function () {
// get today's date
const today = new Date().getTime();
// get the difference
const diff = bdayDate - today;
// math
let days = Math.floor(diff / (1000 * 60 * 60 * 24));
let hours = Math.floor((diff % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
let minutes = Math.floor((diff % (1000 * 60 * 60)) / (1000 * 60));
let seconds = Math.floor((diff % (1000 * 60)) / 1000);
}, 1000);
我最近也有同样的问题，因为我来自Java世界，所以我立即开始搜索JavaScript的JSR 310实现。JSR 310是Java的日期和时间API (Java 8的标准版本)。我认为这个API设计得很好。
幸运的是，有一个直接的Javascript端口，称为js-joda。
首先，在<head>中包含js-joda:
<script
src="https://cdnjs.cloudflare.com/ajax/libs/js-joda/1.11.0/js-joda.min.js"
integrity="sha512-piLlO+P2f15QHjUv0DEXBd4HvkL03Orhi30Ur5n1E4Gk2LE4BxiBAP/AD+dxhxpW66DiMY2wZqQWHAuS53RFDg=="
crossorigin="anonymous"></script>
然后简单地这样做:
let date1 = JSJoda.LocalDate.of(2020, 12, 1);
let date2 = JSJoda.LocalDate.of(2021, 1, 1);
let daysBetween = JSJoda.ChronoUnit.DAYS.between(date1, date2);
现在daysBetween包含了间隔的天数。注意，结束日期是独占的。
1970-01-01之前和2038-01-19之后的贡献
function DateDiff(aDate1, aDate2) {
let dDay = 0;
this.isBissexto = (aYear) => {
return (aYear % 4 == 0 && aYear % 100 != 0) || (aYear % 400 == 0);
};
this.getDayOfYear = (aDate) => {
let count = 0;
for (let m = 0; m < aDate.getUTCMonth(); m++) {
count += m == 1 ? this.isBissexto(aDate.getUTCFullYear()) ? 29 : 28 : /(3|5|8|10)/.test(m) ? 30 : 31;
}
count += aDate.getUTCDate();
return count;
};
this.toDays = () => {
return dDay;
};
(() => {
let startDate = aDate1.getTime() <= aDate2.getTime() ? new Date(aDate1.toISOString()) : new Date(aDate2.toISOString());
let endDate = aDate1.getTime() <= aDate2.getTime() ? new Date(aDate2.toISOString()) : new Date(aDate1.toISOString());
while (startDate.getUTCFullYear() != endDate.getUTCFullYear()) {
dDay += (this.isBissexto(startDate.getFullYear())? 366 : 365) - this.getDayOfYear(startDate) + 1;
startDate = new Date(startDate.getUTCFullYear()+1, 0, 1);
}
dDay += this.getDayOfYear(endDate) - this.getDayOfYear(startDate);
})();
}
当我想在两个日期上做一些计算时，我发现了这个问题，但是日期有小时和分钟的值，我修改了@michael-liu的答案来满足我的要求，它通过了我的测试。
差异日期2012-12-31 23:00和2013-01-01 01:00应该等于1。(2小时) 差异日期2012-12-31 01:00和2013-01-01 23:00应该等于1。(46个小时)
function treatAsUTC(date) {
var result = new Date(date);
result.setMinutes(result.getMinutes() - result.getTimezoneOffset());
return result;
}
var millisecondsPerDay = 24 * 60 * 60 * 1000;
function diffDays(startDate, endDate) {
return Math.floor(treatAsUTC(endDate) / millisecondsPerDay) - Math.floor(treatAsUTC(startDate) / millisecondsPerDay);
}
