如何在两个datetime对象之间以分钟为单位区分时间?
当前回答
Python 2.7新增了timedelta实例方法.total_seconds()。在Python文档中,这相当于(td。微秒+ (td。秒+ td。天* 24 * 3600)* 10**6)/ 10**6。
参考:http://docs.python.org/2/library/datetime.html # datetime.timedelta.total_seconds
>>> import datetime
>>> time1 = datetime.datetime.now()
>>> time2 = datetime.datetime.now() # waited a few minutes before pressing enter
>>> elapsedTime = time2 - time1
>>> elapsedTime
datetime.timedelta(0, 125, 749430)
>>> divmod(elapsedTime.total_seconds(), 60)
(2.0, 5.749430000000004) # divmod returns quotient and remainder
# 2 minutes, 5.74943 seconds
其他回答
我利用时差进行了连续集成测试,以检查和完善我的功能。如果有人需要,这里有一些简单的代码
from datetime import datetime
class TimeLogger:
time_cursor = None
def pin_time(self):
global time_cursor
time_cursor = datetime.now()
def log(self, text=None) -> float:
global time_cursor
if not time_cursor:
time_cursor = datetime.now()
now = datetime.now()
t_delta = now - time_cursor
seconds = t_delta.total_seconds()
result = str(now) + ' tl -----------> %.5f' % seconds
if text:
result += " " + text
print(result)
self.pin_time()
return seconds
time_logger = TimeLogger()
使用:
from .tests_time_logger import time_logger
class Tests(TestCase):
def test_workflow(self):
time_logger.pin_time()
... my functions here ...
time_logger.log()
... other function(s) ...
time_logger.log(text='Tests finished')
我在log输出中有类似的东西
2019-12-20 17:19:23.635297 tl -----------> 0.00007
2019-12-20 17:19:28.147656 tl -----------> 4.51234 Tests finished
使用divmod:
now = int(time.time()) # epoch seconds
then = now - 90000 # some time in the past
d = divmod(now-then,86400) # days
h = divmod(d[1],3600) # hours
m = divmod(h[1],60) # minutes
s = m[1] # seconds
print '%d days, %d hours, %d minutes, %d seconds' % (d[0],h[0],m[0],s)
你可能会发现这个快速的片段在不那么长的时间间隔里很有用:
from datetime import datetime as dttm
time_ago = dttm(2017, 3, 1, 1, 1, 1, 1348)
delta = dttm.now() - time_ago
days = delta.days # can be converted into years which complicates a bit…
hours, minutes, seconds = map(int, delta.__format__('').split('.')[0].split(' ')[-1].split(':'))
在Python v.3.8.6上测试
这里有一个很容易概括或转化为函数的答案,它合理紧凑,易于遵循。
ts_start=datetime(2020, 12, 1, 3, 9, 45)
ts_end=datetime.now()
ts_diff=ts_end-ts_start
secs=ts_diff.total_seconds()
days,secs=divmod(secs,secs_per_day:=60*60*24)
hrs,secs=divmod(secs,secs_per_hr:=60*60)
mins,secs=divmod(secs,secs_per_min:=60)
secs=round(secs, 2)
answer='Duration={} days, {} hrs, {} mins and {} secs'.format(int(days),int(hrs),int(mins),secs)
print(answer)
它给出的答案是“持续时间=270天10小时32分42.13秒”
要查找天数:timedelta有一个'days'属性。你可以简单地查询一下。
>>>from datetime import datetime, timedelta
>>>d1 = datetime(2015, 9, 12, 13, 9, 45)
>>>d2 = datetime(2015, 8, 29, 21, 10, 12)
>>>d3 = d1- d2
>>>print d3
13 days, 15:59:33
>>>print d3.days
13
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