是否可以使用新的Firebase数据库Cloud Firestore来计算一个集合有多少项?
如果是,我该怎么做?
是否可以使用新的Firebase数据库Cloud Firestore来计算一个集合有多少项?
如果是,我该怎么做?
当前回答
除了上面我的npm包adv-firestore-functions,你还可以使用firestore规则来强制一个好的计数器:
Firestore规则
function counter() {
let docPath = /databases/$(database)/documents/_counters/$(request.path[3]);
let afterCount = getAfter(docPath).data.count;
let beforeCount = get(docPath).data.count;
let addCount = afterCount == beforeCount + 1;
let subCount = afterCount == beforeCount - 1;
let newId = getAfter(docPath).data.docId == request.path[4];
let deleteDoc = request.method == 'delete';
let createDoc = request.method == 'create';
return (newId && subCount && deleteDoc) || (newId && addCount && createDoc);
}
function counterDoc() {
let doc = request.path[4];
let docId = request.resource.data.docId;
let afterCount = request.resource.data.count;
let beforeCount = resource.data.count;
let docPath = /databases/$(database)/documents/$(doc)/$(docId);
let createIdDoc = existsAfter(docPath) && !exists(docPath);
let deleteIdDoc = !existsAfter(docPath) && exists(docPath);
let addCount = afterCount == beforeCount + 1;
let subCount = afterCount == beforeCount - 1;
return (createIdDoc && addCount) || (deleteIdDoc && subCount);
}
像这样使用它们:
match /posts/{document} {
allow read;
allow update;
allow create: if counter();
allow delete: if counter();
}
match /_counters/{document} {
allow read;
allow write: if counterDoc();
}
前端
用以下函数替换你的set和delete函数:
set
async setDocWithCounter(
ref: DocumentReference<DocumentData>,
data: {
[x: string]: any;
},
options: SetOptions): Promise<void> {
// counter collection
const counterCol = '_counters';
const col = ref.path.split('/').slice(0, -1).join('/');
const countRef = doc(this.afs, counterCol, col);
const countSnap = await getDoc(countRef);
const refSnap = await getDoc(ref);
// don't increase count if edit
if (refSnap.exists()) {
await setDoc(ref, data, options);
// increase count
} else {
const batch = writeBatch(this.afs);
batch.set(ref, data, options);
// if count exists
if (countSnap.exists()) {
batch.update(countRef, {
count: increment(1),
docId: ref.id
});
// create count
} else {
// will only run once, should not use
// for mature apps
const colRef = collection(this.afs, col);
const colSnap = await getDocs(colRef);
batch.set(countRef, {
count: colSnap.size + 1,
docId: ref.id
});
}
batch.commit();
}
}
删除
async delWithCounter(
ref: DocumentReference<DocumentData>
): Promise<void> {
// counter collection
const counterCol = '_counters';
const col = ref.path.split('/').slice(0, -1).join('/');
const countRef = doc(this.afs, counterCol, col);
const countSnap = await getDoc(countRef);
const batch = writeBatch(this.afs);
// if count exists
batch.delete(ref);
if (countSnap.exists()) {
batch.update(countRef, {
count: increment(-1),
docId: ref.id
});
}
/*
if ((countSnap.data() as any).count == 1) {
batch.delete(countRef);
}*/
batch.commit();
}
更多信息请看这里…
J
其他回答
在2020年,Firebase SDK中还没有这个功能,但Firebase扩展(Beta)中有,不过设置和使用起来相当复杂……
合理的方法
帮手……(创建/删除似乎是多余的,但比onUpdate便宜)
export const onCreateCounter = () => async (
change,
context
) => {
const collectionPath = change.ref.parent.path;
const statsDoc = db.doc("counters/" + collectionPath);
const countDoc = {};
countDoc["count"] = admin.firestore.FieldValue.increment(1);
await statsDoc.set(countDoc, { merge: true });
};
export const onDeleteCounter = () => async (
change,
context
) => {
const collectionPath = change.ref.parent.path;
const statsDoc = db.doc("counters/" + collectionPath);
const countDoc = {};
countDoc["count"] = admin.firestore.FieldValue.increment(-1);
await statsDoc.set(countDoc, { merge: true });
};
export interface CounterPath {
watch: string;
name: string;
}
出口消防钩
export const Counters: CounterPath[] = [
{
name: "count_buildings",
watch: "buildings/{id2}"
},
{
name: "count_buildings_subcollections",
watch: "buildings/{id2}/{id3}/{id4}"
}
];
Counters.forEach(item => {
exports[item.name + '_create'] = functions.firestore
.document(item.watch)
.onCreate(onCreateCounter());
exports[item.name + '_delete'] = functions.firestore
.document(item.watch)
.onDelete(onDeleteCounter());
});
在行动
将跟踪构建根集合和所有子集合。
在/counters/ root路径下
现在收集计数将自动更新,最终!如果需要计数,只需使用收集路径并在其前面加上计数器即可。
const collectionPath = 'buildings/138faicnjasjoa89/buildingContacts';
const collectionCount = await db
.doc('counters/' + collectionPath)
.get()
.then(snap => snap.get('count'));
限制
由于此方法使用单个数据库和文档,因此每个计数器的Firestore约束为每秒更新1次。它最终将是一致的,但在添加/删除大量文档的情况下,计数器将落后于实际收集计数。
不,目前还没有内置的聚合查询支持。然而,有几件事你可以做。
这里记录了第一个。您可以使用事务或云函数来维护聚合信息:
这个例子展示了如何使用一个函数来跟踪子集合中的评级数量,以及平均评级。
exports.aggregateRatings = firestore
.document('restaurants/{restId}/ratings/{ratingId}')
.onWrite(event => {
// Get value of the newly added rating
var ratingVal = event.data.get('rating');
// Get a reference to the restaurant
var restRef = db.collection('restaurants').document(event.params.restId);
// Update aggregations in a transaction
return db.transaction(transaction => {
return transaction.get(restRef).then(restDoc => {
// Compute new number of ratings
var newNumRatings = restDoc.data('numRatings') + 1;
// Compute new average rating
var oldRatingTotal = restDoc.data('avgRating') * restDoc.data('numRatings');
var newAvgRating = (oldRatingTotal + ratingVal) / newNumRatings;
// Update restaurant info
return transaction.update(restRef, {
avgRating: newAvgRating,
numRatings: newNumRatings
});
});
});
});
jbb提到的解决方案在您只想不频繁地计数文档时也很有用。确保使用select()语句来避免下载所有文档(当您只需要一个计数时,这是很大的带宽)。select()目前仅在服务器sdk中可用,因此该解决方案不适用于移动应用程序。
聚合计数查询刚刚在Firestore中预览。
在2022年Firebase峰会上宣布:https://firebase.blog/posts/2022/10/whats-new-at-Firebase-Sumit-2022
摘录:
[开发人员预览]Count()函数:与新的计数函数 Firstore[原文],你现在可以得到匹配文件的计数当你 运行查询或从集合中读取,而不加载实际的 文件,这为你节省了很多时间。
他们在峰会上展示的代码示例:
在问答环节中,有人问了汇总查询的定价问题,Firebase团队给出的答案是,它的成本是读取价格的1 / 1000(四舍四入到最近的读取,详情见下面的评论),但将计算汇总的所有记录。
除了上面我的npm包adv-firestore-functions,你还可以使用firestore规则来强制一个好的计数器:
Firestore规则
function counter() {
let docPath = /databases/$(database)/documents/_counters/$(request.path[3]);
let afterCount = getAfter(docPath).data.count;
let beforeCount = get(docPath).data.count;
let addCount = afterCount == beforeCount + 1;
let subCount = afterCount == beforeCount - 1;
let newId = getAfter(docPath).data.docId == request.path[4];
let deleteDoc = request.method == 'delete';
let createDoc = request.method == 'create';
return (newId && subCount && deleteDoc) || (newId && addCount && createDoc);
}
function counterDoc() {
let doc = request.path[4];
let docId = request.resource.data.docId;
let afterCount = request.resource.data.count;
let beforeCount = resource.data.count;
let docPath = /databases/$(database)/documents/$(doc)/$(docId);
let createIdDoc = existsAfter(docPath) && !exists(docPath);
let deleteIdDoc = !existsAfter(docPath) && exists(docPath);
let addCount = afterCount == beforeCount + 1;
let subCount = afterCount == beforeCount - 1;
return (createIdDoc && addCount) || (deleteIdDoc && subCount);
}
像这样使用它们:
match /posts/{document} {
allow read;
allow update;
allow create: if counter();
allow delete: if counter();
}
match /_counters/{document} {
allow read;
allow write: if counterDoc();
}
前端
用以下函数替换你的set和delete函数:
set
async setDocWithCounter(
ref: DocumentReference<DocumentData>,
data: {
[x: string]: any;
},
options: SetOptions): Promise<void> {
// counter collection
const counterCol = '_counters';
const col = ref.path.split('/').slice(0, -1).join('/');
const countRef = doc(this.afs, counterCol, col);
const countSnap = await getDoc(countRef);
const refSnap = await getDoc(ref);
// don't increase count if edit
if (refSnap.exists()) {
await setDoc(ref, data, options);
// increase count
} else {
const batch = writeBatch(this.afs);
batch.set(ref, data, options);
// if count exists
if (countSnap.exists()) {
batch.update(countRef, {
count: increment(1),
docId: ref.id
});
// create count
} else {
// will only run once, should not use
// for mature apps
const colRef = collection(this.afs, col);
const colSnap = await getDocs(colRef);
batch.set(countRef, {
count: colSnap.size + 1,
docId: ref.id
});
}
batch.commit();
}
}
删除
async delWithCounter(
ref: DocumentReference<DocumentData>
): Promise<void> {
// counter collection
const counterCol = '_counters';
const col = ref.path.split('/').slice(0, -1).join('/');
const countRef = doc(this.afs, counterCol, col);
const countSnap = await getDoc(countRef);
const batch = writeBatch(this.afs);
// if count exists
batch.delete(ref);
if (countSnap.exists()) {
batch.update(countRef, {
count: increment(-1),
docId: ref.id
});
}
/*
if ((countSnap.data() as any).count == 1) {
batch.delete(countRef);
}*/
batch.commit();
}
更多信息请看这里…
J
这使用计数来创建数字唯一ID。在我的使用中,我将永远不会递减,即使需要ID的文档被删除。
在需要唯一数值的集合创建时
用一个文档指定一个集合appData,只设置.doc id 在firebase防火控制台中将uniqueNumericIDAmount设置为0 使用doc.data()。uniqueNumericIDAmount + 1作为唯一的数字id 更新appData收集uniqueNumericIDAmount与firebase.firestore.FieldValue.increment(1)
firebase
.firestore()
.collection("appData")
.doc("only")
.get()
.then(doc => {
var foo = doc.data();
foo.id = doc.id;
// your collection that needs a unique ID
firebase
.firestore()
.collection("uniqueNumericIDs")
.doc(user.uid)// user id in my case
.set({// I use this in login, so this document doesn't
// exist yet, otherwise use update instead of set
phone: this.state.phone,// whatever else you need
uniqueNumericID: foo.uniqueNumericIDAmount + 1
})
.then(() => {
// upon success of new ID, increment uniqueNumericIDAmount
firebase
.firestore()
.collection("appData")
.doc("only")
.update({
uniqueNumericIDAmount: firebase.firestore.FieldValue.increment(
1
)
})
.catch(err => {
console.log(err);
});
})
.catch(err => {
console.log(err);
});
});