是否可以使用新的Firebase数据库Cloud Firestore来计算一个集合有多少项?

如果是,我该怎么做?


当前回答

FireStore现在支持该功能,尽管是Beta版。 下面是Firebase的官方文档

其他回答

这使用计数来创建数字唯一ID。在我的使用中,我将永远不会递减,即使需要ID的文档被删除。

在需要唯一数值的集合创建时

用一个文档指定一个集合appData,只设置.doc id 在firebase防火控制台中将uniqueNumericIDAmount设置为0 使用doc.data()。uniqueNumericIDAmount + 1作为唯一的数字id 更新appData收集uniqueNumericIDAmount与firebase.firestore.FieldValue.increment(1)

firebase
    .firestore()
    .collection("appData")
    .doc("only")
    .get()
    .then(doc => {
        var foo = doc.data();
        foo.id = doc.id;

        // your collection that needs a unique ID
        firebase
            .firestore()
            .collection("uniqueNumericIDs")
            .doc(user.uid)// user id in my case
            .set({// I use this in login, so this document doesn't
                  // exist yet, otherwise use update instead of set
                phone: this.state.phone,// whatever else you need
                uniqueNumericID: foo.uniqueNumericIDAmount + 1
            })
            .then(() => {

                // upon success of new ID, increment uniqueNumericIDAmount
                firebase
                    .firestore()
                    .collection("appData")
                    .doc("only")
                    .update({
                        uniqueNumericIDAmount: firebase.firestore.FieldValue.increment(
                            1
                        )
                    })
                    .catch(err => {
                        console.log(err);
                    });
            })
            .catch(err => {
                console.log(err);
            });
    });

根据上面的一些答案,我花了一段时间才让它工作,所以我想把它分享给其他人使用。希望对大家有用。

'use strict';

const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
const db = admin.firestore();

exports.countDocumentsChange = functions.firestore.document('library/{categoryId}/documents/{documentId}').onWrite((change, context) => {

    const categoryId = context.params.categoryId;
    const categoryRef = db.collection('library').doc(categoryId)
    let FieldValue = require('firebase-admin').firestore.FieldValue;

    if (!change.before.exists) {

        // new document created : add one to count
        categoryRef.update({numberOfDocs: FieldValue.increment(1)});
        console.log("%s numberOfDocs incremented by 1", categoryId);

    } else if (change.before.exists && change.after.exists) {

        // updating existing document : Do nothing

    } else if (!change.after.exists) {

        // deleting document : subtract one from count
        categoryRef.update({numberOfDocs: FieldValue.increment(-1)});
        console.log("%s numberOfDocs decremented by 1", categoryId);

    }

    return 0;
});

Firebase/Firestore中的新功能提供了集合中的文档计数:

请参阅本线程以了解如何实现它,并提供了一个示例。

如何计算在一个集合中的Firebase Firestore与WHERE查询在react.js文档的数量

我尝试了很多不同的方法。 最后,我改进了其中一种方法。 首先,您需要创建一个单独的集合并保存其中的所有事件。 其次,您需要创建一个由时间触发的新lambda。此lambda将计数事件集合中的事件并清除事件文档。 代码细节见文章。 https://medium.com/@ihor.malaniuk/how-to-count-documents-in-google-cloud-firestore-b0e65863aeca

除了上面我的npm包adv-firestore-functions,你还可以使用firestore规则来强制一个好的计数器:

Firestore规则

function counter() {
  let docPath = /databases/$(database)/documents/_counters/$(request.path[3]);
  let afterCount = getAfter(docPath).data.count;
  let beforeCount = get(docPath).data.count;
  let addCount = afterCount == beforeCount + 1;
  let subCount = afterCount == beforeCount - 1;
  let newId = getAfter(docPath).data.docId == request.path[4];
  let deleteDoc = request.method == 'delete';
  let createDoc = request.method == 'create';
  return (newId && subCount && deleteDoc) || (newId && addCount && createDoc);
}

function counterDoc() {
  let doc = request.path[4];
  let docId = request.resource.data.docId;
  let afterCount = request.resource.data.count;
  let beforeCount = resource.data.count;
  let docPath = /databases/$(database)/documents/$(doc)/$(docId);
  let createIdDoc = existsAfter(docPath) && !exists(docPath);
  let deleteIdDoc = !existsAfter(docPath) && exists(docPath);
  let addCount = afterCount == beforeCount + 1;
  let subCount = afterCount == beforeCount - 1;
  return (createIdDoc && addCount) || (deleteIdDoc && subCount);
}

像这样使用它们:

match /posts/{document} {
  allow read;
  allow update;
  allow create: if counter();
  allow delete: if counter();
}
match /_counters/{document} {
  allow read;
  allow write: if counterDoc();
}

前端

用以下函数替换你的set和delete函数:

set

async setDocWithCounter(
  ref: DocumentReference<DocumentData>,
  data: {
    [x: string]: any;
  },
  options: SetOptions): Promise<void> {

  // counter collection
  const counterCol = '_counters';

  const col = ref.path.split('/').slice(0, -1).join('/');
  const countRef = doc(this.afs, counterCol, col);
  const countSnap = await getDoc(countRef);
  const refSnap = await getDoc(ref);

  // don't increase count if edit
  if (refSnap.exists()) {
    await setDoc(ref, data, options);

    // increase count
  } else {
    const batch = writeBatch(this.afs);
    batch.set(ref, data, options);

    // if count exists
    if (countSnap.exists()) {
      batch.update(countRef, {
        count: increment(1),
        docId: ref.id
      });
      // create count
    } else {
      // will only run once, should not use
      // for mature apps
      const colRef = collection(this.afs, col);
      const colSnap = await getDocs(colRef);
      batch.set(countRef, {
        count: colSnap.size + 1,
        docId: ref.id
      });
    }
    batch.commit();
  }
}

删除

async delWithCounter(
  ref: DocumentReference<DocumentData>
): Promise<void> {

  // counter collection
  const counterCol = '_counters';

  const col = ref.path.split('/').slice(0, -1).join('/');
  const countRef = doc(this.afs, counterCol, col);
  const countSnap = await getDoc(countRef);
  const batch = writeBatch(this.afs);

  // if count exists
  batch.delete(ref);
  if (countSnap.exists()) {
    batch.update(countRef, {
      count: increment(-1),
      docId: ref.id
    });
  }
  /*
  if ((countSnap.data() as any).count == 1) {
    batch.delete(countRef);
  }*/
  batch.commit();
}

更多信息请看这里…

J