我的iOS应用程序为UINavigationBar使用了自定义高度,这在新的iPhone X上导致了一些问题。

是否有人已经知道如何通过编程(在Objective-C中)可靠地检测应用程序是否在iPhone X上运行?

编辑:

当然,检查屏幕的大小是可能的,但是,我想知道是否有一些“内置”的方法,如TARGET_OS_IPHONE来检测iOS…

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
    CGSize screenSize = [[UIScreen mainScreen] bounds].size;
    if (screenSize.height == 812)
        NSLog(@"iPhone X");
}

编辑2:

我不认为,我的问题是一个重复的关联问题。当然,有一些方法可以“测量”当前设备的不同属性,并使用结果来决定使用哪种设备。然而,这并不是我在第一篇编辑中试图强调的问题的实际意义。

真正的问题是:“是否有可能直接检测当前设备是否是iPhone X(例如通过某些SDK功能),还是我必须使用间接测量?”

根据目前给出的答案,我假设答案是“不,没有直接的方法。测量是要走的路。”


当前回答

是的,这是可能的。 下载UIDevice-Hardware扩展(或通过CocoaPod 'UIDevice-Hardware'安装),然后使用:

NSString* modelID = [[[UIDevice currentDevice] modelIdentifier];
BOOL isIphoneX = [modelID isEqualToString:@"iPhone10,3"] || [modelID isEqualToString:@"iPhone10,6"];

注意,这不能在模拟器中工作,只能在实际设备上工作。

其他回答

struct ScreenSize {
    static let width = UIScreen.main.bounds.size.width
    static let height = UIScreen.main.bounds.size.height
    static let maxLength = max(ScreenSize.width, ScreenSize.height)
    static let minLength = min(ScreenSize.width, ScreenSize.height)
    static let frame = CGRect(x: 0, y: 0, width: ScreenSize.width, height: ScreenSize.height)
}

struct DeviceType {
    static let iPhone4orLess = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength < 568.0
    static let iPhone5orSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 568.0
    static let iPhone678 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 667.0
    static let iPhone678p = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 736.0
    static let iPhoneX = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 812.0

    static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.maxLength == 1024.0
    static let IS_IPAD_PRO          = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.maxLength == 1366.0
}

检查设备型号/机器名称,不要在你的代码中直接使用点/像素计数,这是硬代码,对设备硬件没有意义,设备型号是设备类型匹配的唯一标识符。

#import <sys/utsname.h>

NSString* deviceName()
{
    struct utsname systemInfo;
    uname(&systemInfo);

    return [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];
}

结果:

@"iPhone10,3" on iPhone X (CDMA)
@"iPhone10,6" on iPhone X (GSM)

参考这个答案。

完整的代码实现:

#import <sys/utsname.h>

NSString * GetDeviceModel(void)
{
    static dispatch_once_t onceToken;
    static NSString *strModelID = nil;

    dispatch_once(&onceToken, ^{
#if TARGET_IPHONE_SIMULATOR
        strModelID = NSProcessInfo.processInfo.environment[@"SIMULATOR_MODEL_IDENTIFIER"];
#else
        struct utsname systemInfo;

        uname(&systemInfo);
        strModelID = [NSString stringWithCString:systemInfo.machine encoding:NSUTF8StringEncoding];
#endif
    });

    return strModelID;
}

// See the `Hardware strings` in https://en.wikipedia.org/wiki/List_of_iOS_devices
BOOL IsiPhoneX(void)
{
    NSString *strModelID = GetDeviceModel();

    return [strModelID isEqualToString:@"iPhone10,3"] || [strModelID isEqualToString:@"iPhone10,6"];
}

BOOL IsNotchiPhone(void)
{
    NSArray<NSString *> *notchiModels = @[
        @"iPhone10,3", @"iPhone10,6", // iPhone X
        @"iPhone11,2", @"iPhone11,4", @"iPhone11,6", // iPhone XS (Max)
        @"iPhone11,8", // iPhone XR
        @"iPhone12,1", @"iPhone12,3", @"iPhone12,5", // iPhone 11 (Pro (Max))
        @"iPhone13,1", @"iPhone13,2", @"iPhone13,3", @"iPhone13,4", // iPhone 12 ([mini]|[Pro (Max)])
    ];

    return [notchiModels containsObject:GetDeviceModel()];
}

不要像其他解决方案建议的那样使用屏幕像素大小,这很糟糕,因为它可能会导致未来设备出现假阳性;将不工作,如果UIWindow尚未渲染(AppDelegate),将不工作在景观应用程序,并可以失败在模拟器上,如果比例设置。

相反,我已经为此目的做了一个宏,它非常容易使用,并依赖于硬件标志来防止上述问题。

编辑:更新到支持iPhoneX, iPhoneXS, iPhoneXR, iPhoneXS Max


使用方法:

if (IS_DEVICE_IPHONEX) {
    //do stuff
}

是的,真的。


宏:

复制粘贴到任何地方,我更喜欢@end后的。h文件的底部

#import <sys/utsname.h>

#if TARGET_IPHONE_SIMULATOR
#define IS_SIMULATOR YES
#else
#define IS_SIMULATOR NO
#endif

#define IS_DEVICE_IPHONEX (\
(^BOOL (void){\
NSString *__modelIdentifier;\
if (IS_SIMULATOR) {\
__modelIdentifier = NSProcessInfo.processInfo.environment[@"SIMULATOR_MODEL_IDENTIFIER"];\
} else {\
struct utsname __systemInfo;\
uname(&__systemInfo);\
__modelIdentifier = [NSString stringWithCString:__systemInfo.machine encoding:NSUTF8StringEncoding];\
}\
NSString *__iPhoneX_GSM_Identifier = @"iPhone10,6";\
NSString *__iPhoneX_CDMA_Identifier = @"iPhone10,3";\
NSString *__iPhoneXR_Identifier = @"iPhone11,8";\
NSString *__iPhoneXS_Identifier = @"iPhone11,2";\
NSString *__iPhoneXSMax_China_Identifier = @"iPhone11,6";\
NSString *__iPhoneXSMax_Other_Identifier = @"iPhone11,4";\
return ([__modelIdentifier isEqualToString:__iPhoneX_GSM_Identifier] || [__modelIdentifier isEqualToString:__iPhoneX_CDMA_Identifier] || [__modelIdentifier isEqualToString:__iPhoneXR_Identifier] || [__modelIdentifier isEqualToString:__iPhoneXS_Identifier] || [__modelIdentifier isEqualToString:__iPhoneXSMax_China_Identifier] || [__modelIdentifier isEqualToString:__iPhoneXSMax_Other_Identifier]);\
})()\
)

SWIFT 4+回答

iPhone X, XR, XS, XSMAX, 11 Pro, 11 Pro Max:

注:需实物设备进行测试

参考

 let deviceType = UIDevice.current.modelName
        switch deviceType {
        case "iPhone10,3", "iPhone10,6":
            print("iPhoneX")
        case "iPhone11,2":
            print("iPhone XS")
        case "iPhone11,4":
            print("iPhone XS Max")
        case "iPhone11,6":
            print("iPhone XS Max China")
        case "iPhone11,8":
            print("iPhone XR")
        case "iPhone12,3":
            print("iPhone 11 Pro")
        case "iPhone12,5":
            print("iPhone 11 Pro Max")
        default:
            break
}

extension UIDevice {
    var modelName: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
        return identifier
    }
}

在看完所有的答案后,我最后是这么做的:

解决方案(兼容Swift 4.1)

extension UIDevice {
    static var isIphoneX: Bool {
        var modelIdentifier = ""
        if isSimulator {
            modelIdentifier = ProcessInfo.processInfo.environment["SIMULATOR_MODEL_IDENTIFIER"] ?? ""
        } else {
            var size = 0
            sysctlbyname("hw.machine", nil, &size, nil, 0)
            var machine = [CChar](repeating: 0, count: size)
            sysctlbyname("hw.machine", &machine, &size, nil, 0)
            modelIdentifier = String(cString: machine)
        }

        return modelIdentifier == "iPhone10,3" || modelIdentifier == "iPhone10,6"
    }

    static var isSimulator: Bool {
        return TARGET_OS_SIMULATOR != 0
    }
}

Use

if UIDevice.isIphoneX {
    // is iPhoneX
} else {
    // is not iPhoneX
}

Note

Pre Swift 4.1你可以检查应用程序是否在模拟器上运行,就像这样:

TARGET_OS_SIMULATOR != 0

从Swift 4.1开始,你可以使用目标环境平台条件检查应用程序是否在模拟器上运行:

#if targetEnvironment(simulator)
    return true
#else
    return false
#endif

(旧的方法仍然有效,但这个新方法更经得起未来的考验)