使用angular-ui-router的ui-sref-active指令 https://github.com/angular-ui/ui-router/wiki/Quick-Reference#statename

<德> <li ui-sref-active=“active”类=“项目”> <a href ="应用程序。用户({用户:‘bilbobaggins})“> @bilbobaggins < / a > < / li > < !——...--> < /德>

我对这个问题的解决方案是使用路由。角模板中的电流。

当你在菜单中突出显示/tasks路由时，你可以将自己的属性menuItem添加到模块声明的路由中:

$routeProvider.
  when('/tasks', {
    menuItem: 'TASKS',
    templateUrl: 'my-templates/tasks.html',
    controller: 'TasksController'
  );

然后在模板任务中。你可以使用以下ng-class指令:

<a href="app.html#/tasks" 
    ng-class="{active : route.current.menuItem === 'TASKS'}">Tasks</a>

在我看来，这比所有提出的解决方案都要干净得多。

使用指令(因为我们在这里做的是DOM操作)，下面可能是最接近“angular方式”的方法:

$scope.timeFilters = [
  {'value':3600,'label':'1 hour'},
  {'value':10800,'label':'3 hours'},
  {'value':21600,'label':'6 hours'},
  {'value':43200,'label':'12 hours'},
  {'value':86400,'label':'24 hours'},
  {'value':604800,'label':'1 week'}
]

angular.module('whatever', []).directive('filter',function(){
return{
    restrict: 'A',
    template: '<li ng-repeat="time in timeFilters" class="filterItem"><a ng-click="changeTimeFilter(time)">{{time.label}}</a></li>',
    link: function linkFn(scope, lElement, attrs){

        var menuContext = attrs.filter;

        scope.changeTimeFilter = function(newTime){
          scope.selectedtimefilter = newTime;

        }

        lElement.bind('click', function(cevent){
            var currentSelection = angular.element(cevent.srcElement).parent();
            var previousSelection = scope[menuContext];

            if(previousSelection !== currentSelection){
                if(previousSelection){
                    angular.element(previousSelection).removeClass('active')
                }
                scope[menuContext] = currentSelection;

                scope.$apply(function(){
                    currentSelection.addClass('active');
                })
            }
        })
    }
}
})

然后你的HTML看起来像这样:

<ul class="dropdown-menu" filter="times"></ul>

Here is the solution that I came up with after reading some of the excellent suggestions above. In my particular situation, I was trying to use Bootstrap tabs component as my menu, but didn't want to use the Angular-UI version of this because I want the tabs to act as a menu, where each tab is bookmark-able, rather than the tabs acting as navigation for a single page. (See http://angular-ui.github.io/bootstrap/#/tabs if you're interested in what the Angular-UI version of bootstrap tabs looks like).

I really liked kfis's answer about creating your own directive to handle this, however it seemed cumbersome to have a directive that needed to be placed on every single link. So I've created my own Angular directive which is placed instead once on the ul. Just in case any one else is trying to do the same thing, I thought I'd post it here, though as I said, many of the above solutions work as well. This is a slightly more complex solution as far as the javascript goes, but it creates a reusable component with minimal markup.

下面是指令的javascript和ng:view的路由提供程序:

var app = angular.module('plunker', ['ui.bootstrap']).
  config(['$routeProvider', function($routeProvider) {
    $routeProvider.
        when('/One', {templateUrl: 'one.html'}).
        when('/Two', {templateUrl: 'two.html'}).
        when('/Three', {templateUrl: 'three.html'}).
        otherwise({redirectTo: '/One'});
  }]).
  directive('navTabs', ['$location', function(location) {
    return {
        restrict: 'A',
        link: function(scope, element) {
            var $ul = $(element);
            $ul.addClass("nav nav-tabs");

            var $tabs = $ul.children();
            var tabMap = {};
            $tabs.each(function() {
              var $li = $(this);
              //Substring 1 to remove the # at the beginning (because location.path() below does not return the #)
              tabMap[$li.find('a').attr('href').substring(1)] = $li;
            });

            scope.location = location;
            scope.$watch('location.path()', function(newPath) {
                $tabs.removeClass("active");
                tabMap[newPath].addClass("active");
            });
        }

    };

 }]);

然后在你的html中你只需:

<ul nav-tabs>
  <li><a href="#/One">One</a></li>
  <li><a href="#/Two">Two</a></li>
  <li><a href="#/Three">Three</a></li>
</ul>
<ng:view><!-- Content will appear here --></ng:view>

这里是它的活塞:http://plnkr.co/edit/xwGtGqrT7kWoCKnGDHYN?p=preview。

我有类似的问题，菜单位于控制器范围之外。不确定这是最好的解决方案还是推荐的解决方案，但这对我来说是有效的。我已经在我的应用程序配置中添加了以下内容:

var app = angular.module('myApp');

app.run(function($rootScope, $location){
  $rootScope.menuActive = function(url, exactMatch){
    if (exactMatch){
      return $location.path() == url;
    }
    else {
      return $location.path().indexOf(url) == 0;
    }
  }
});

那么在视图中，我有:

<li><a href="/" ng-class="{true: 'active'}[menuActive('/', true)]">Home</a></li>
<li><a href="/register" ng-class="{true: 'active'}[menuActive('/register')]">
<li>...</li>

这是我的意见，这很好。

注意:这与子页不匹配(这是我需要的)。

观点:

<a ng-class="{active: isCurrentLocation('/my-path')}"  href="/my-path" >
  Some link
</a>

控制器:

// make sure you inject $location as a dependency

$scope.isCurrentLocation = function(path){
    return path === $location.path()
}