使用slice()方法:

function returnChunksArray(str, chunkSize) {
  var arr = [];
  while(str !== '') {
    arr.push(str.slice(0, chunkSize));
    str = str.slice(chunkSize);
  }
  return arr;
}

使用substring()方法也可以做到这一点。

function returnChunksArray(str, chunkSize) {
  var arr = [];
  while(str !== '') {
    arr.push(str.substring(0, chunkSize));
    str = str.substring(chunkSize);
  }
  return arr;
}

var l = str.length, lc = 0, chunks = [], c = 0, chunkSize = 2;
for (; lc < l; c++) {
  chunks[c] = str.slice(lc, lc += chunkSize);
}

我创建了几个更快的变体，您可以在jsPerf上看到。我最喜欢的是这个:

function chunkSubstr(str, size) {
  const numChunks = Math.ceil(str.length / size)
  const chunks = new Array(numChunks)

  for (let i = 0, o = 0; i < numChunks; ++i, o += size) {
    chunks[i] = str.substr(o, size)
  }

  return chunks
}

使用npm库"chkchars" 但是请记住，要确保给定的字符串长度完全除以“number”参数。

const phrase = "1110010111010011100101110100010000011100101110100111001011101001011101001110010111010001000001110010111010011100101110100"
const number = 7

chkchars.splitToChunks(phrase, number)

// result => ['1110010', '1110100','1110010', '1110100','0100000', '1110010','1110100', '1110010','1110100', '1011101','0011100', '1011101','0001000','0011100','1011101', '0011100','1011101']

// perf => 0.287ms

我对上述解决方案的问题是，不管在句子中的位置如何，它都将字符串划分为正式的大小块。

我认为下面的方法比较好;虽然它需要一些性能调整:

 static chunkString(str, length, size,delimiter='\n' ) {
        const result = [];
        for (let i = 0; i < str.length; i++) {
            const lastIndex = _.lastIndexOf(str, delimiter,size + i);
            result.push(str.substr(i, lastIndex - i));
            i = lastIndex;
        }
        return result;
    }

以原型函数的形式:

String.prototype.lsplit = function(){
    return this.match(new RegExp('.{1,'+ ((arguments.length==1)?(isFinite(String(arguments[0]).trim())?arguments[0]:false):1) +'}', 'g'));
}