我想检查数据,但如果它为空或空忽略它。目前查询如下…

Select              
Coalesce(listing.OfferText, company.OfferText, '') As Offer_Text,         
from tbl_directorylisting listing  
 Inner Join tbl_companymaster company            
  On listing.company_id= company.company_id      

但我想找个伴。OfferText如果列表。Offertext是一个空字符串,如果它是null。

最好的解决方案是什么?


当前回答

这个语法:

SELECT *
FROM tbl_directorylisting listing
WHERE (civilite_etudiant IS NULL)

在Microsoft SQL Server 2008 (SP3)为我工作

其他回答

这里有一个解决方案,但我不知道它是否是最好的....

Select              
Coalesce(Case When Len(listing.Offer_Text) = 0 Then Null Else listing.Offer_Text End, company.Offer_Text, '') As Offer_Text,         
from tbl_directorylisting listing  
 Inner Join tbl_companymaster company            
  On listing.company_id= company.company_id
Select              
Coalesce(NullIf(listing.OfferText, ''), NullIf(company.OfferText, ''), '') As Offer_Text,         
from tbl_directorylisting listing  
 Inner Join tbl_companymaster company            
  On listing.company_id= company.company_id

您可以使用ISNULL并根据已知输出检查答案:

SELECT case when ISNULL(col1, '') = '' then '' else col1 END AS COL1 FROM TEST
SELECT              
    COALESCE(listing.OfferText, 'company.OfferText') AS Offer_Text,         
FROM 
    tbl_directorylisting listing  
    INNER JOIN tbl_companymaster company ON listing.company_id= company.company_id
Select              
CASE
    WHEN listing.OfferText is null or listing.OfferText = '' THEN company.OfferText
    ELSE COALESCE(Company.OfferText, '')
END As Offer_Text,         
from tbl_directorylisting listing  
 Inner Join tbl_companymaster company            
  On listing.company_id= company.company_id