如何检测用户用JavaScript在网页上向某个方向滑动手指?

我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。


当前回答

我重做了@ruben-martinez的答案,使用来自@givanse的惊人的解决方案,使用自定义反应钩子处理滑动事件。

import React, { useEffect, useRef, useState } from "react";

export default function useSwiper() {
  const [domRef, setDomRef] = useState<any>();

  const xDown: React.MutableRefObject<number | null> = useRef(null);
  const yDown: React.MutableRefObject<number | null> = useRef(null);

  useEffect(() => {
if (!domRef) return;

function getTouches(event: React.TouchEvent<HTMLDivElement>) {
  return event.touches;
}

function handleTouchStart(event: any) {
  const firstTouch = getTouches(event)[0];
  xDown.current = firstTouch.clientX;
  yDown.current = firstTouch.clientY;
}

function handleTouchMove(event: React.TouchEvent<HTMLDivElement>) {
  if (!xDown.current || !yDown.current) return;

  const firstTouch = getTouches(event)[0];
  const xUp = firstTouch.clientX;
  const yUp = firstTouch.clientY;

  const xDiff = xDown.current - xUp;
  const yDiff = yDown.current - yUp;

  if (Math.abs(xDiff) > Math.abs(yDiff)) {
    // handle horizontal swipes
    if (xDiff > 0) {
      // we swiped right
      console.log("right");
    } else {
      // we swiped left
      console.log("left");
    }
  } else {
    // handle vertical swipes
    if (yDiff > 0) {
      // we swiped down
      console.log("down");
    } else {
      // we swiped up
      console.log("up");
    }
  }
}

function handleTouchEnd(event: React.TouchEvent<HTMLDivElement>) {
  xDown.current = null;
  yDown.current = null;
}


  domRef.addEventListener("touchstart", handleTouchStart, false);
  domRef.addEventListener("touchmove", handleTouchMove, false);
  domRef.addEventListener("touchend", handleTouchEnd, false);

return () => {
    domRef.removeEventListener("touchstart", handleTouchStart, false);
    domRef.removeEventListener("touchmove", handleTouchMove, false);
    domRef.removeEventListener("touchend", handleTouchEnd, false);
};
  }, [domRef]);

  return (ref: any) => setDomRef(ref);
}

我在实现他的答案时遇到的主要挑战是不知道如何将swipe元素的ref绑定到自定义钩子中的ref。

基本上,所发生的是我们从自定义钩子返回一个函数。这个函数允许我们传入一个来自我们想要监听的滑动动作的元素的ref。自定义钩子接收到ref后,用元素的ref更新钩子状态,从而触发重新渲染,这样我们就有了实际的元素!

这种函数式的ref样式还允许我们对多个元素使用钩子。如下所示,我想使用它的项目列表,以启用滑动删除:)

import useSwiper from "./hooks/useSwipe";

const EntryCard = ({ entry, godMode, reload }: EntryProps) => {
const swiperRef = useSwiper();

const handleEntryClick =
(entry: Entry) => async (event: React.MouseEvent<HTMLDivElement>) => {
  if (!godMode) return;

  try {
    reload((state) => !state);
  } catch (err) {
    console.log("Error deleting entry: ", err);
  }
};

return (
  <div className="item" onClick={handleEntryClick(entry)} ref={swiperRef}>
    <div className="username">{entry.userName}</div>
    <div className="score">{entry.weekScore}</div>
  </div>
 );
};

PS:你可以把函数传递给钩子来接收滑动值。谢谢:)如果你喜欢,请投票:)

其他回答

函数检查水平方向和垂直方向,以确定哪个滑动更长,以防止执行两个指令,因为不可能进行完美的单向滑动。滑动总是在X和Y上有偏差。

let touchstartX = 0;
let touchendX = 0;
let touchstartY = 0;
let touchendY = 0;   

function checkDirection() {
    let difX = touchstartX - touchendX;
    let difY = touchstartY - touchendY;
if (Math.abs(difX) > Math.abs(difY)) {
    if (touchendX < touchstartX) {/*left*/}
    if (touchendX > touchstartX) {/*right*/}
} else {
    if (touchendY < touchstartY) {/*up*/}
    if (touchendY > touchstartY) {/*down*/}
}
};
document.addEventListener('touchstart', e => {
    e.preventDefault();
    touchstartX = e.changedTouches[0].screenX;
    touchstartY = e.changedTouches[0].screenY;
});

document.addEventListener('touchend', e => {
    e.preventDefault();
    touchendX = e.changedTouches[0].screenX;
    touchendY = e.changedTouches[0].screenY;
    checkDirection();
});

简单的JS代码示例:

document.addEventListener('touchstart', handleTouchStart, false);        
document.addEventListener('touchmove', handleTouchMove, false);

var xDown = null;                                                        
var yDown = null;

function getTouches(evt) {
  return evt.touches ||             // browser API
         evt.originalEvent.touches; // jQuery
}                                                     
                                                                         
function handleTouchStart(evt) {
    const firstTouch = getTouches(evt)[0];                                      
    xDown = firstTouch.clientX;                                      
    yDown = firstTouch.clientY;                                      
};                                                
                                                                         
function handleTouchMove(evt) {
    if ( ! xDown || ! yDown ) {
        return;
    }

    var xUp = evt.touches[0].clientX;                                    
    var yUp = evt.touches[0].clientY;

    var xDiff = xDown - xUp;
    var yDiff = yDown - yUp;
                                                                         
    if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
        if ( xDiff > 0 ) {
            /* right swipe */ 
        } else {
            /* left swipe */
        }                       
    } else {
        if ( yDiff > 0 ) {
            /* down swipe */ 
        } else { 
            /* up swipe */
        }                                                                 
    }
    /* reset values */
    xDown = null;
    yDown = null;                                             
};

Android测试。

我重新包装了TouchWipe作为一个简短的jquery插件:detectSwipe

我将这里的一些答案合并到一个脚本中,该脚本使用CustomEvent在DOM中触发滑动事件。添加0.7k的swiped-events.min.js脚本到你的页面,并监听滑动事件:

刷卡

document.addEventListener('swiped', function(e) {
    console.log(e.target); // the element that was swiped
    console.log(e.detail.dir); // swiped direction
});

swiped-left

document.addEventListener('swiped-left', function(e) {
    console.log(e.target); // the element that was swiped
});

swiped-right

document.addEventListener('swiped-right', function(e) {
    console.log(e.target); // the element that was swiped
});

swiped-up

document.addEventListener('swiped-up', function(e) {
    console.log(e.target); // the element that was swiped
});

swiped-down

document.addEventListener('swiped-down', function(e) {
    console.log(e.target); // the element that was swiped
});

你也可以直接附加到一个元素:

document.getElementById('myBox').addEventListener('swiped-down', function(e) {
    console.log(e.target); // the element that was swiped
});

可选配置

您可以指定以下属性来调整页面中的滑动交互功能(这些是可选的)。

<div data-swipe-threshold="10"
     data-swipe-timeout="1000"
     data-swipe-ignore="false">
      Swiper, get swiping!
</div>

要在应用程序范围内设置默认值,请在最顶部的元素上设置配置属性:

<body data-swipe-threshold="100" data-swipe-timeout="250">
    <div>Swipe me</div>
    <div>or me</div>
</body>

源代码可在Github

我只想检测左右滑动,但只在触摸事件结束时触发动作,所以我稍微修改了@givanse的答案来实现这一点。

为什么要这么做?例如,在滑动时,用户注意到他最终不想滑动,他可以将手指移动到原来的位置(一个非常流行的“约会”手机应用程序可以做到这一点;)),然后“向右滑动”事件被取消。

因此,为了避免因为水平上有3px的差异而导致“向右滑动”事件,我添加了一个阈值,在该阈值下事件将被丢弃:为了有一个“向右滑动”事件,用户必须至少滑动浏览器宽度的1/3(当然,您可以修改这个)。

所有这些小细节都增强了用户体验。

请注意,目前,如果两个手指中的一个在缩放过程中做了一个大的水平移动,那么“触摸缩放”可能会被检测为滑动。

这是(Vanilla JS)代码:

var xDown = null, yDown = null, xUp = null, yUp = null;
document.addEventListener('touchstart', touchstart, false);        
document.addEventListener('touchmove', touchmove, false);
document.addEventListener('touchend', touchend, false);
function touchstart(evt) { const firstTouch = (evt.touches || evt.originalEvent.touches)[0]; xDown = firstTouch.clientX; yDown = firstTouch.clientY; }
function touchmove(evt) { if (!xDown || !yDown ) return; xUp = evt.touches[0].clientX; yUp = evt.touches[0].clientY; }
function touchend(evt) { 
    var xDiff = xUp - xDown, yDiff = yUp - yDown;
    if ((Math.abs(xDiff) > Math.abs(yDiff)) && (Math.abs(xDiff) > 0.33 * document.body.clientWidth)) { 
        if (xDiff < 0) 
            document.getElementById('leftnav').click();
        else
            document.getElementById('rightnav').click();
    } 
    xDown = null, yDown = null;
}