如何检测用户用JavaScript在网页上向某个方向滑动手指?

我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。


当前回答

threshold, timeout swipe, swipeBlockElems添加。

document.addEventListener('touchstart', handleTouchStart, false);
document.addEventListener('touchmove', handleTouchMove, false);
document.addEventListener('touchend', handleTouchEnd, false);     

const SWIPE_BLOCK_ELEMS = [
  'swipBlock',
  'handle',
  'drag-ruble'
]

let xDown = null;
let yDown = null; 
let xDiff = null;
let yDiff = null;
let timeDown = null;
const  TIME_THRESHOLD = 200;
const  DIFF_THRESHOLD = 130;

function handleTouchEnd() {

let timeDiff = Date.now() - timeDown; 
if (Math.abs(xDiff) > Math.abs(yDiff)) { /*most significant*/
  if (Math.abs(xDiff) > DIFF_THRESHOLD && timeDiff < TIME_THRESHOLD) {
    if (xDiff > 0) {
      // console.log(xDiff, TIME_THRESHOLD, DIFF_THRESHOLD)
      SWIPE_LEFT(LEFT) /* left swipe */
    } else {
      // console.log(xDiff)
      SWIPE_RIGHT(RIGHT) /* right swipe */
    }
  } else {
    console.log('swipeX trashhold')
  }
} else {
  if (Math.abs(yDiff) > DIFF_THRESHOLD && timeDiff < TIME_THRESHOLD) {
    if (yDiff > 0) {
      /* up swipe */
    } else {
      /* down swipe */
    }
  } else {
    console.log('swipeY trashhold')
  }
 }
 /* reset values */
 xDown = null;
 yDown = null;
 timeDown = null; 
}
function containsClassName (evntarget , classArr) {
 for (var i = classArr.length - 1; i >= 0; i--) {
   if( evntarget.classList.contains(classArr[i]) ) {
      return true;
    }
  }
}
function handleTouchStart(evt) {
  let touchStartTarget = evt.target;
  if( containsClassName(touchStartTarget, SWIPE_BLOCK_ELEMS) ) {
    return;
  }
  timeDown = Date.now()
  xDown = evt.touches[0].clientX;
  yDown = evt.touches[0].clientY;
  xDiff = 0;
  yDiff = 0;

}

function handleTouchMove(evt) {
  if (!xDown || !yDown) {
    return;
  }

  var xUp = evt.touches[0].clientX;
  var yUp = evt.touches[0].clientY;


  xDiff = xDown - xUp;
  yDiff = yDown - yUp;
}

其他回答

在这里的建议之上,我将跟踪手指号码,因为如果你同时用两个手指触摸,它将获得X位置,而不会导致一个奇怪的行为,而且,你可能想要设置一个“距离”最小值,这样用户在通过你的网站或应用程序触摸时就不会错误地触发滑动。

//Swipe 
let touchstartX = 0
let touchendX = 0
let fingerCount = 0
    
const checkDirection = () => {

  const distance = 50 //Minimum distance for the swipe to work

  //left
  if (touchendX < touchstartX && (touchstartX - touchendX) > distance ){

  //Do something cool
   
  } 
  //right
  if (touchendX > touchstartX && (touchendX - touchstartX) > distance){

    //Do something cooler
}

document.addEventListener('touchstart', e => {

    fingerCount = e.touches.length
    touchstartX = e.changedTouches[0].clientX  
     
})

document.addEventListener('touchend', e => {

    touchendX = e.changedTouches[0].clientX
    if(fingerCount === 1){ 
        checkDirection() 
    }

})

如果有人试图在Android上使用jQuery Mobile,并且有JQM滑动检测的问题

(我在Xperia Z1, Galaxy S3, Nexus 4和一些Wiko手机上也有一些)这可能很有用:

 //Fix swipe gesture on android
    if(android){ //Your own device detection here
        $.event.special.swipe.verticalDistanceThreshold = 500
        $.event.special.swipe.horizontalDistanceThreshold = 10
    }

在android上的滑动不会被检测到,除非它是一个非常长、精确和快速的滑动。

这两条线可以正常工作

jQuery Mobile还包括滑动支持:http://api.jquerymobile.com/swipe/

例子

$("#divId").on("swipe", function(event) {
    alert("It's a swipe!");
});

如果你只需要滑动,你最好只使用你需要的部分。 这应该适用于任何触摸设备。

这是经过gzip压缩,缩小,babel等大约450字节。

我根据其他答案编写了下面的类,它使用移动百分比而不是像素,以及一个事件分派器模式来挂钩/取消挂钩。

像这样使用它:

const dispatcher = new SwipeEventDispatcher(myElement);
dispatcher.on('SWIPE_RIGHT', () => { console.log('I swiped right!') })

export class SwipeEventDispatcher { constructor(element, options = {}) { this.evtMap = { SWIPE_LEFT: [], SWIPE_UP: [], SWIPE_DOWN: [], SWIPE_RIGHT: [] }; this.xDown = null; this.yDown = null; this.element = element; this.options = Object.assign({ triggerPercent: 0.3 }, options); element.addEventListener('touchstart', evt => this.handleTouchStart(evt), false); element.addEventListener('touchend', evt => this.handleTouchEnd(evt), false); } on(evt, cb) { this.evtMap[evt].push(cb); } off(evt, lcb) { this.evtMap[evt] = this.evtMap[evt].filter(cb => cb !== lcb); } trigger(evt, data) { this.evtMap[evt].map(handler => handler(data)); } handleTouchStart(evt) { this.xDown = evt.touches[0].clientX; this.yDown = evt.touches[0].clientY; } handleTouchEnd(evt) { const deltaX = evt.changedTouches[0].clientX - this.xDown; const deltaY = evt.changedTouches[0].clientY - this.yDown; const distMoved = Math.abs(Math.abs(deltaX) > Math.abs(deltaY) ? deltaX : deltaY); const activePct = distMoved / this.element.offsetWidth; if (activePct > this.options.triggerPercent) { if (Math.abs(deltaX) > Math.abs(deltaY)) { deltaX < 0 ? this.trigger('SWIPE_LEFT') : this.trigger('SWIPE_RIGHT'); } else { deltaY > 0 ? this.trigger('SWIPE_UP') : this.trigger('SWIPE_DOWN'); } } } } export default SwipeEventDispatcher;

我也合并了一些答案,主要是第一个和第二个与类,下面是我的版本:

export default class Swipe {
    constructor(options) {
        this.xDown = null;
        this.yDown = null;

        this.options = options;

        this.handleTouchStart = this.handleTouchStart.bind(this);
        this.handleTouchMove = this.handleTouchMove.bind(this);

        document.addEventListener('touchstart', this.handleTouchStart, false);
        document.addEventListener('touchmove', this.handleTouchMove, false);

    }

    onLeft() {
        this.options.onLeft();
    }

    onRight() {
        this.options.onRight();
    }

    onUp() {
        this.options.onUp();
    }

    onDown() {
        this.options.onDown();
    }

    static getTouches(evt) {
        return evt.touches      // browser API

    }

    handleTouchStart(evt) {
        const firstTouch = Swipe.getTouches(evt)[0];
        this.xDown = firstTouch.clientX;
        this.yDown = firstTouch.clientY;
    }

    handleTouchMove(evt) {
        if ( ! this.xDown || ! this.yDown ) {
            return;
        }

        let xUp = evt.touches[0].clientX;
        let yUp = evt.touches[0].clientY;

        let xDiff = this.xDown - xUp;
        let yDiff = this.yDown - yUp;


        if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
            if ( xDiff > 0 && this.options.onLeft) {
                /* left swipe */
                this.onLeft();
            } else if (this.options.onRight) {
                /* right swipe */
                this.onRight();
            }
        } else {
            if ( yDiff > 0 && this.options.onUp) {
                /* up swipe */
                this.onUp();
            } else if (this.options.onDown){
                /* down swipe */
                this.onDown();
            }
        }

        /* reset values */
        this.xDown = null;
        this.yDown = null;
    }
}

之后可以这样使用:

let swiper = new Swipe({
                    onLeft() {
                        console.log('You swiped left.');
                    }
});

当你只想调用“onLeft”方法时,它有助于避免控制台错误。