如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
当前回答
如果你只需要滑动,你最好只使用你需要的部分。 这应该适用于任何触摸设备。
这是经过gzip压缩,缩小,babel等大约450字节。
我根据其他答案编写了下面的类,它使用移动百分比而不是像素,以及一个事件分派器模式来挂钩/取消挂钩。
像这样使用它:
const dispatcher = new SwipeEventDispatcher(myElement);
dispatcher.on('SWIPE_RIGHT', () => { console.log('I swiped right!') })
export class SwipeEventDispatcher { constructor(element, options = {}) { this.evtMap = { SWIPE_LEFT: [], SWIPE_UP: [], SWIPE_DOWN: [], SWIPE_RIGHT: [] }; this.xDown = null; this.yDown = null; this.element = element; this.options = Object.assign({ triggerPercent: 0.3 }, options); element.addEventListener('touchstart', evt => this.handleTouchStart(evt), false); element.addEventListener('touchend', evt => this.handleTouchEnd(evt), false); } on(evt, cb) { this.evtMap[evt].push(cb); } off(evt, lcb) { this.evtMap[evt] = this.evtMap[evt].filter(cb => cb !== lcb); } trigger(evt, data) { this.evtMap[evt].map(handler => handler(data)); } handleTouchStart(evt) { this.xDown = evt.touches[0].clientX; this.yDown = evt.touches[0].clientY; } handleTouchEnd(evt) { const deltaX = evt.changedTouches[0].clientX - this.xDown; const deltaY = evt.changedTouches[0].clientY - this.yDown; const distMoved = Math.abs(Math.abs(deltaX) > Math.abs(deltaY) ? deltaX : deltaY); const activePct = distMoved / this.element.offsetWidth; if (activePct > this.options.triggerPercent) { if (Math.abs(deltaX) > Math.abs(deltaY)) { deltaX < 0 ? this.trigger('SWIPE_LEFT') : this.trigger('SWIPE_RIGHT'); } else { deltaY > 0 ? this.trigger('SWIPE_UP') : this.trigger('SWIPE_DOWN'); } } } } export default SwipeEventDispatcher;
其他回答
threshold, timeout swipe, swipeBlockElems添加。
document.addEventListener('touchstart', handleTouchStart, false);
document.addEventListener('touchmove', handleTouchMove, false);
document.addEventListener('touchend', handleTouchEnd, false);
const SWIPE_BLOCK_ELEMS = [
'swipBlock',
'handle',
'drag-ruble'
]
let xDown = null;
let yDown = null;
let xDiff = null;
let yDiff = null;
let timeDown = null;
const TIME_THRESHOLD = 200;
const DIFF_THRESHOLD = 130;
function handleTouchEnd() {
let timeDiff = Date.now() - timeDown;
if (Math.abs(xDiff) > Math.abs(yDiff)) { /*most significant*/
if (Math.abs(xDiff) > DIFF_THRESHOLD && timeDiff < TIME_THRESHOLD) {
if (xDiff > 0) {
// console.log(xDiff, TIME_THRESHOLD, DIFF_THRESHOLD)
SWIPE_LEFT(LEFT) /* left swipe */
} else {
// console.log(xDiff)
SWIPE_RIGHT(RIGHT) /* right swipe */
}
} else {
console.log('swipeX trashhold')
}
} else {
if (Math.abs(yDiff) > DIFF_THRESHOLD && timeDiff < TIME_THRESHOLD) {
if (yDiff > 0) {
/* up swipe */
} else {
/* down swipe */
}
} else {
console.log('swipeY trashhold')
}
}
/* reset values */
xDown = null;
yDown = null;
timeDown = null;
}
function containsClassName (evntarget , classArr) {
for (var i = classArr.length - 1; i >= 0; i--) {
if( evntarget.classList.contains(classArr[i]) ) {
return true;
}
}
}
function handleTouchStart(evt) {
let touchStartTarget = evt.target;
if( containsClassName(touchStartTarget, SWIPE_BLOCK_ELEMS) ) {
return;
}
timeDown = Date.now()
xDown = evt.touches[0].clientX;
yDown = evt.touches[0].clientY;
xDiff = 0;
yDiff = 0;
}
function handleTouchMove(evt) {
if (!xDown || !yDown) {
return;
}
var xUp = evt.touches[0].clientX;
var yUp = evt.touches[0].clientY;
xDiff = xDown - xUp;
yDiff = yDown - yUp;
}
简单的水平滑动JS示例:
let touchstartX = 0
let touchendX = 0
function checkDirection() {
if (touchendX < touchstartX) alert('swiped left!')
if (touchendX > touchstartX) alert('swiped right!')
}
document.addEventListener('touchstart', e => {
touchstartX = e.changedTouches[0].screenX
})
document.addEventListener('touchend', e => {
touchendX = e.changedTouches[0].screenX
checkDirection()
})
垂直滑动也可以使用相同的逻辑。
在这里的建议之上,我将跟踪手指号码,因为如果你同时用两个手指触摸,它将获得X位置,而不会导致一个奇怪的行为,而且,你可能想要设置一个“距离”最小值,这样用户在通过你的网站或应用程序触摸时就不会错误地触发滑动。
//Swipe
let touchstartX = 0
let touchendX = 0
let fingerCount = 0
const checkDirection = () => {
const distance = 50 //Minimum distance for the swipe to work
//left
if (touchendX < touchstartX && (touchstartX - touchendX) > distance ){
//Do something cool
}
//right
if (touchendX > touchstartX && (touchendX - touchstartX) > distance){
//Do something cooler
}
document.addEventListener('touchstart', e => {
fingerCount = e.touches.length
touchstartX = e.changedTouches[0].clientX
})
document.addEventListener('touchend', e => {
touchendX = e.changedTouches[0].clientX
if(fingerCount === 1){
checkDirection()
}
})
我重做了@givanse的解决方案,使其发挥React钩子的作用。输入是一些可选的事件监听器,输出是一个功能性的ref(需要是功能性的,以便当/如果ref改变时钩子可以重新运行)。
还添加了垂直/水平滑动阈值参数,这样小的运动不会意外触发事件监听器,但这些可以设置为0,以更接近地模拟原始答案。
提示:为了获得最佳性能,应该记住事件侦听器输入函数。
function useSwipeDetector({
// Event listeners.
onLeftSwipe,
onRightSwipe,
onUpSwipe,
onDownSwipe,
// Threshold to detect swipe.
verticalSwipeThreshold = 50,
horizontalSwipeThreshold = 30,
}) {
const [domRef, setDomRef] = useState(null);
const xDown = useRef(null);
const yDown = useRef(null);
useEffect(() => {
if (!domRef) {
return;
}
function handleTouchStart(evt) {
const [firstTouch] = evt.touches;
xDown.current = firstTouch.clientX;
yDown.current = firstTouch.clientY;
};
function handleTouchMove(evt) {
if (!xDown.current || !yDown.current) {
return;
}
const [firstTouch] = evt.touches;
const xUp = firstTouch.clientX;
const yUp = firstTouch.clientY;
const xDiff = xDown.current - xUp;
const yDiff = yDown.current - yUp;
if (Math.abs(xDiff) > Math.abs(yDiff)) {/*most significant*/
if (xDiff > horizontalSwipeThreshold) {
if (onRightSwipe) onRightSwipe();
} else if (xDiff < -horizontalSwipeThreshold) {
if (onLeftSwipe) onLeftSwipe();
}
} else {
if (yDiff > verticalSwipeThreshold) {
if (onUpSwipe) onUpSwipe();
} else if (yDiff < -verticalSwipeThreshold) {
if (onDownSwipe) onDownSwipe();
}
}
};
function handleTouchEnd() {
xDown.current = null;
yDown.current = null;
}
domRef.addEventListener("touchstart", handleTouchStart, false);
domRef.addEventListener("touchmove", handleTouchMove, false);
domRef.addEventListener("touchend", handleTouchEnd, false);
return () => {
domRef.removeEventListener("touchstart", handleTouchStart);
domRef.removeEventListener("touchmove", handleTouchMove);
domRef.removeEventListener("touchend", handleTouchEnd);
};
}, [domRef, onLeftSwipe, onRightSwipe, onUpSwipe, onDownSwipe, verticalSwipeThreshold, horizontalSwipeThreshold]);
return (ref) => setDomRef(ref);
};
我只想检测左右滑动,但只在触摸事件结束时触发动作,所以我稍微修改了@givanse的答案来实现这一点。
为什么要这么做?例如,在滑动时,用户注意到他最终不想滑动,他可以将手指移动到原来的位置(一个非常流行的“约会”手机应用程序可以做到这一点;)),然后“向右滑动”事件被取消。
因此,为了避免因为水平上有3px的差异而导致“向右滑动”事件,我添加了一个阈值,在该阈值下事件将被丢弃:为了有一个“向右滑动”事件,用户必须至少滑动浏览器宽度的1/3(当然,您可以修改这个)。
所有这些小细节都增强了用户体验。
请注意,目前,如果两个手指中的一个在缩放过程中做了一个大的水平移动,那么“触摸缩放”可能会被检测为滑动。
这是(Vanilla JS)代码:
var xDown = null, yDown = null, xUp = null, yUp = null;
document.addEventListener('touchstart', touchstart, false);
document.addEventListener('touchmove', touchmove, false);
document.addEventListener('touchend', touchend, false);
function touchstart(evt) { const firstTouch = (evt.touches || evt.originalEvent.touches)[0]; xDown = firstTouch.clientX; yDown = firstTouch.clientY; }
function touchmove(evt) { if (!xDown || !yDown ) return; xUp = evt.touches[0].clientX; yUp = evt.touches[0].clientY; }
function touchend(evt) {
var xDiff = xUp - xDown, yDiff = yUp - yDown;
if ((Math.abs(xDiff) > Math.abs(yDiff)) && (Math.abs(xDiff) > 0.33 * document.body.clientWidth)) {
if (xDiff < 0)
document.getElementById('leftnav').click();
else
document.getElementById('rightnav').click();
}
xDown = null, yDown = null;
}